Equilibrium. Stable equilibrium (negative feedback)

Slides:



Advertisements
Similar presentations
A: acceleration E: equilibrium Determine whether the following diagrams illustrate acceleration or equilibrium. Number your paper from 1 to 5 and answer.
Advertisements

Artrelle Fragher & Robert walker. 1 you look for the median 1 you look for the median 2 then you look for the min and max 2 then you look for the min.
AP Physics C Montwood High School R. Casao
RC Circuit: Charging Capacitor
Carbon Cycle.
Ozone Level ppb (parts per billion)
Demonstration Problem
Freefall Motion for which the only force acting is the force of gravity. It can be moving up or down. (Air friction is negligible) Negligible – So insignificant.
Copyright © 2002 Harcourt, Inc.All rights reserved. Types of leases Tax treatment of leases Effects on financial statements Lessees analysis Lessors.
Half Life. The half-life of a quantity whose value decreases with time is the interval required for the quantity to decay to half of its initial value.
1 1  1 =.
1  1 =.
Science Jeopardy >>>> Topic 1 Topic 2 Topic 4 Topic Topic 5.
2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt ShapesPatterns Counting Number.
DIVIDING INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
MULT. INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
Addition Facts
November 18 AP Physics.
Year 6 mental test 15 second questions Numbers and number system Numbers and the number system, Measures and Shape.
Click here Can you work out the answer? 20 ÷ 4 =
It is 2 o C The temperature drops by 3 degrees What temperature is it now? -1 o C.
Risk, Return, and the Time Value of Money

Analysis grid superimposed 2D Street Grid Calculating Travel-Time …vector to raster conversion Note that a 100 row by 100 column analysis grid (10,000.
Principles of Mass Balance
© Richard A. Medeiros 2004 x y Function Machine Function Machine next.
Impact of Population Change Natural Population Change.
Three Key Process Measures: Flow Rate
Area of triangles.
12-5 Surface Areas of Pyramids. Objectives: Find lateral areas of regular pyramids Find surface areas of regular pyramids.
Direct-Current Circuits
8.6 Linear Programming. Linear Program: a mathematical model representing restrictions on resources using linear inequalities combined with a function.
11 THE MACROECONOMICS OF OPEN ECONOMIES. Copyright © 2004 South-Western 31 Open-Economy Macroeconomics: Basic Concepts.
Chapter 7. Characteristics of Bonds  Bonds pay fixed coupon (interest) payments at fixed intervals (usually every 6 months) and pay the par value at.
Least Common Multiples and Greatest Common Factors
Limits (Algebraic) Calculus Fall, What can we do with limits?
Lecture 10: RL & RC Circuits Nilsson & Riedel ENG17 (Sec. 2): Circuits I Spring May 1, 2014.
Chapter Organisation 6.1 Bond Valuation 6.2 Common Stock Valuation
Addition 1’s to 20.
You will be given the answer. You must give the correct question.
Week 1.
Number bonds to 10,
Beat the Computer Drill Divide 10s Becky Afghani, LBUSD Math Curriculum Office, 2004 Vertical Format.
2 x0 0 12/13/2014 Know Your Facts!. 2 x1 2 12/13/2014 Know Your Facts!
Sections: 1.3 and 1.5 m > 0 Positive Rising, Increasing Concave up m > 0 Positive Rising, Increasing Concave down Use the following table to decide if.
Jeopardy Start Final Jeopardy Question Category 1Category 2Category 3Category 4Category
Back to menu category 1 type you categories here– delete these instructions. Final jeopardy question.
Array Operations ENGR 1181 MATLAB 4. Aerospace Engineers use turbulence data to calculate how close other planes can fly near the wake of a larger plane.
Latent Heat Materials can also go through a change in state called a phase change. Changes between solid, liquid, gaseous and plasma states. Energy Is.
FIRM BEHAVIOR AND THE ORGANIZATION OF INDUSTRY
FIRM BEHAVIOR AND THE ORGANIZATION OF INDUSTRY
Copyright©2004 South-Western 13 The Costs of Production.
MARKOV CHAIN A, B and C are three towns. Each year: 10% of the residents of A move to B 30% of the residents of A move to C 20% of the residents of B move.
EXAMPLE 3 Use synthetic division
FE Review for Environmental Engineering Problems, problems, problems Presented by L.R. Chevalier, Ph.D., P.E. Department of Civil and Environmental Engineering.
Ch 2.3: Modeling with First Order Equations Mathematical models characterize physical systems, often using differential equations. Model Construction:
Agenda Recap of Lecture 3 Dynamic behavior of basic systems
Cross-Over Distortion The non-zero “turn-on” voltage of a transistor causes cross-over distortion in a class B output stage. Approximate transistor response.
Closing the Loop: Dynamics of Simple Structures
Generic structure: Leaky water tank and applications John Sternam from MIT argues the importance.
Money & Banking - ECO Dr. D. Foster Interest Rates II: How rates are determined The Term Structure.
This is unchecked growth:
Jump to first page Copyright 2003 South-Western Thomson Learning. All rights reserved. Loanable Funds Market.
Simple positive feedback Example: Bank balance Interest Payments = Bank Balance * Interest Rate Positive feedback = the stock will continue to increase.
First Order Differential Equations Sec 2.7 Linear Models By Dr. Iman Gohar.
Bathtub Dynamics and Climate Change
Mass Balance with a water Tank
Calculus & Exam Section 6
Systems Thinking and Climate Change
Motion and Force. Motion and Force On page 36 of your notebook, prepare Cornell Notes with these questions: What does the word net mean? Net force.
Presentation transcript:

Equilibrium

Stable equilibrium (negative feedback)

Unstable equilibrium (positive feedback),

At Equilibrium: Inflows=Outflows

80 gal/min 120 gal ???

Assume Equilibrium: Inflows=Outflows 80 gal/min 120 gal 80 gal/min

At Equilibrium: Inflows=Outflows 80 gal/min 120 gal 20 gal/min Is water level a)rising b)Falling c)Staying the same

At Equilibrium: Inflows=Outflows 80 gal/min 120 gal 20 gal/min Is water level a)rising b)Falling c)Staying the same

At Equilibrium: Inflows=Outflows 80 gal/min 120 gal 80 gal/min Is water level a)rising b)Falling c)Staying the same

At Equilibrium: Inflows=Outflows 80 gal/min 120 gal 80 gal/min Is water level a)rising b)Falling c)Staying the same

At Equilibrium: Inflows=Outflows 80 gal/min 120 gal 140 gal/min Is water level a)rising b)Falling c)Staying the same

At Equilibrium: Inflows=Outflows 80 gal/min 120 gal 140 gal/min Is water level a)rising b)Falling c)Staying the same

At Equilibrium: Inflows=Outflows Is water level a)rising b)Falling c)Staying the same =2 min 8 gal/min 20 gal ??=_________

At Equilibrium: Inflows=Outflows Is water level a)rising b)Falling c)Staying the same =2 min 8 gal/min 20 gal ??=_10 gal/min________

At Equilibrium: Inflows=Outflows Is water level a)rising b)Falling c)Staying the same =2 min 8 gal/min 16 gal ??=_________

At Equilibrium: Inflows=Outflows Is water level a)rising b)Falling c)Staying the same =2 min 8 gal/min 16 gal ??=__8 gal/min_______

At Equilibrium: Inflows=Outflows Is water level a)rising b)Falling c)Staying the same =2 min 8 gal/min 12 gal ??=_________

At Equilibrium: Inflows=Outflows Is water level a)rising b)Falling c)Staying the same =2 min 8 gal/min 12 gal ??=___6 gal/min_____

At Equilibrium: Inflows=Outflows Is pollutant level a)rising b)Falling c)Staying the same 8 ppm/yr 12 ppm =.2 (1/yr) ??=_________

At Equilibrium: Inflows=Outflows Is pollutant level a)rising b)Falling c)Staying the same 8 ppm/yr 12 ppm =.2 (1/yr) ??=__2.4 ppm/yr____

At Equilibrium: Inflows=Outflows Is pollutant level a)rising b)Falling c)Staying the same 8 ppm/yr ?? =.2 (1/yr) 8 ppm/yr What is the lifetime?

At Equilibrium: Inflows=Outflows Is pollutant level a)rising b)Falling c)Staying the same 8 ppm/yr ??= 40 ppm =.2 (1/yr) 8 ppm/yr What is the lifetime? Lifetime=1/(DecayConstant)=5 yr

Whenever the net flow = -k*stock you get exponential decay to zero** Summary (exponential decay/Goal seeking) Sometimes we like to use the concept of lifetime (decay time constant) instead of decay rate constant. Here k is the decay rate constant.

Whenever the net flow = inflow-k*stock you get exponential decay to a Goal, Xeq Summary (exponential decay/Goal seeking) The Goal is the value of X (the stock) that makes the net flow zero Inflow=outflow Inflow=k*stock at equilibrium Here X is any stock.

Ceq=Inflow*lifetime Ceq=Inflow/(DecayRateConstant) Outflow=Content/(lifetime) Outflow=DecayRateConstant*Content Summary (exponential decay/Goal seeking)