Starter: wb page 74, Q5b, Karl has a mass of 80 Kg and jumps with a velocity of 3 m/s east. Boat A has a mass of 100 Kg. What is its velocity just after.

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Presentation transcript:

Starter: wb page 74, Q5b, Karl has a mass of 80 Kg and jumps with a velocity of 3 m/s east. Boat A has a mass of 100 Kg. What is its velocity just after Karl jumps? 1.Work out the momentum before the jump (of the whole system, boat + karl) Momentum before jump = 100Kg x0 + 80Kg x 0= 0 kg m/s

Momentum before jump = momentum after jump Momentum after jump = momentum boat + momentum karl =(100 Kg x v) + (80 Kg x 3m/s) 0 kg m/s = (100 Kg x v) + (80 Kg x 3m/s) v= -(80 kg x v) / 100 = m/s

Karl has a mass of 80 Kg and jumps with a velocity of 3 m/s east. Boat A has a mass of 100 Kg. Boat B has a mass of 112 kg. Calculate boat B’s velocity after Karl lands in it. Momentum before Karl lands = momentum after Karl lands. Work out momentum before.. 2. Momentum before Karl lands = momentum of the boat + momentum of Karl = (112 kg x 0) + (80 Kg x 3m/s) = 240 Kg m/s

Momentum after Karl landed = ( ) v Momentum before… = momentum after…= 240 Kg m/s 240 kg m/s = ( ) v V= 240/192 = m/s

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