(Mon) A 75 kg man jumps off of the roof of his garage 8 m above the ground and lands on his trampoline 1 m above the ground. If the total spring coefficient.

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Presentation transcript:

(Mon) A 75 kg man jumps off of the roof of his garage 8 m above the ground and lands on his trampoline 1 m above the ground. If the total spring coefficient of the trampoline is 41 kN/m, how far does the trampoline flex down once he stops bouncing around? (5 min/5 pts)

At equilibrium: F net = 0 8m 1m ?m F g = F e or mg = kx (75kg)(9.81m/s²) = (41kN/m)(x) N = 41,000(x) N x = / 41,000 m x = m Or 1.79 cm (Mon) A 75 kg man jumps off of the roof of his garage 8 m above the ground and lands on his trampoline 1 m above the ground. If the total spring coefficient of the trampoline is 41 kN/m, how far does the trampoline flex down once he stops bouncing around? (5 min/5 pts)

(Tue) A 2600 kg (5750lb) Escalade and a 1160 kg (2550lb) Cooper Mini are stopped at a stoplight. When the light turns green, and both accelerate to 20 m/s (45mph) in a distance of 300 m. How much less force did the Mini have to use to keep even with the Cadillac? (5 min / 5 pts)

W = Fd W = ΔKE W = KEf - KEi X Fd = ½mv² F = ½mv²/d ΔF = (½)(Δm)v²/d ΔF = (0.5)(2600kg-1160kg)(20m/s)²/(300m) ΔF = 960 N

(Wed) A 1000 kg elevator carries a max load of 800 kg. A constant friction force of 4000 N pulls down on the car as it goes up. What is the minimum power, in kW, that the motor must have to lift the car at 3 m/s? (10 min / 10 pts)

Fpull FgFf Mass = Mass Car + Mass People Mass = 1000 kg kg = 1800 kg Constant speed means Net Force =0 ΣFy = 0 or Fp = Ff + Fg Fp = 4000 N + (1800 kg)(9.81 m/s²) Fp = N P = W/t or P = Fv (use this one) P = (21658 N)(3 m/s) P = 64,974 W or…. P = kW

End of Week Procedures: 1.Add up all the points you got this week 2.Put the total number of points at the top of your page (out of 20 points) 3.List any dates you were absent (and why) 4.Make sure your name and period is on the top of the paper 5.Turn in your papers