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Based on the Systems Approach to Problem Solving The six step process as presented in Alexander and Sadiku

Six Steps Define Present Alternate Solutions

Six Steps Attempt Evaluate Rework/Export

Electric Circuits IDE Problem Name: Example 03-02 Date: 6/9/2005

Problem Statement We are to determine the node voltages in the following circuit. In addition, we are to find them using nodal analysis.

Define

Your Analysis on the Problem We are to solve for the node voltages in the circuit using nodal analysis. We label the voltages as v1 representing the unknown node voltage at the top of the current source. The unknown node voltage between the 2-ohm and 8-ohm resistors we will label as v2. The unknown node voltage at the top of the dependent source we will label as v3. Please note that the number of nodes represent all the nodes excluding the reference node.

Present Number of Nodes in the circuit are 3 Number of Loops in the loops are 3 Let Node Voltage at Node 1 be v1 V Let Node Voltage at Node 2 be v2 V Let Node Voltage at Node 3 be v3 V Let Loop Current in Loop 1 be i1 A Let Loop Current in Loop 2 be i2 A Let Loop Current in Loop 3 be i3 A

ALTERNATE SOLUTIONS The Methods Selected for Solving the Problem are: Ohms Law Nodal Analysis(KCL) The Reasons for Selecting the Methods are: Stated in problem definition

Attempt Intermediate steps: 0.75*v1-0.5*v2-0.25*v3=3 We could have also included any comments here that could show how we get the above equations.

ATTEMPT-II Final Answers: v1 = 4.8 v2 = 2.4 v3 = -2.4

Evaluate

Comments We have successfully completed the assignment. The answers obtained from two different approaches agree. We should also go back to the circuit and see if the answers make sense. If they do not, my suggestion would be to try to solve for the loop currents by using mesh analysis and then solve for the node voltages using the loop currents. Another approach would be to use the node voltages to determine the branch currents and see if the satisfy Kirchhoff's current law. Looking at the original circuit, the answers do make sense.

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