Covalent Bonding. Electrons are shared between two nonmetals Weaker attractive force than ionic bonding.

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Presentation transcript:

Covalent Bonding

Electrons are shared between two nonmetals Weaker attractive force than ionic bonding

Properties of Molecular Compounds State at SATPTypically gases & liquids, but some solids StructureVariable (waxy to brittle) Melting & Boiling PointsLow Electrical ConductivityNonelectrolyte Solubility in WaterVariable (low to high) Confused?? Don’t worry…more answers to come

Covalent Bonding Formation of hydrogen chloride: H  + Cl    Cl  H  H - Cl  Covalent bond, shared electrons Lone pairs, valence electrons not involved in covalent bond Structural Formula: H-Cl (lone pairs are not drawn)

Lewis Structures H   H +  Cl  Cl  H2:H2: or H H Cl 2 : Cl   Cl   + or Cl Cl   H H Structural Formula: Cl-Cl

Double and Triple Bonds Atoms can share 4 electrons to form a double bond or 6 electrons to form a triple bond. The number of shared electron pairs (covalent bonds) that an atom can form is the bonding capacity. O2:O2: N2:N2: = O  N 

Multiple Covalent Bonds N N N N N N N N

Multiple Covalent Bonds C O O C O O C O O C O O

Drawing Lewis Structures 1.Arrange the element symbols. Central atoms are generally those with the highest bonding capacity. Carbon atoms are always central atoms Hydrogen atoms are always peripheral atoms 2.Add up the number of valence electrons from all atoms. 3.Draw a skeleton structure with atoms attached by single bonds. 4.Complete the octets of peripheral atoms. 5.Place extra electrons on the central atom. 6.If the central atom doesn’t have an octet, try forming multiple bonds by moving lone pairs.

Practice Problems Examples –Methanal CH 2 O –Chlorate (polyatomic ion) p #1-15

Strategy for Writing Lewis Structures

Draw Lewis structures and the structural formula for: HF: H 2 O: NH 3 : CH 4 : H F  or H F  H O H  or H O H  H N H H  or H N H H  H C H H H  or H C H H H

Molecular formula Atom placement Sum of valence e - Remaining valence e - Lewis structure For NF 3 N FF F N = 5e - F = 7e - X 3 = 21e - Total 26e - : :: :::: : : : Zero: NF 3 is uncharged

SAMPLE PROBLEM 10.1Writing Lewis Structures for Molecules with One Central Atom SOLUTION: PROBLEM:Write a Lewis structure for CCl 2 F 2, one of the compounds responsible for the depletion of stratospheric ozone. Step 1: Carbon has the highest bonding capacity and is the central atom. The other atoms are placed around it. C Steps 2-4: C has 4 valence e -, Cl and F each have 7. The sum is 4 + 4(7) = 32 valence e -. Cl F F C F F Make bonds and fill in remaining valence electrons placing 8e - around each atom. :: : :: : : : : :: :

SAMPLE PROBLEM 10.2Writing Lewis Structure for Molecules with More than One Central Atom PROBLEM:Write the Lewis structure for methanol (molecular formula CH 4 O), an important industrial alcohol that is being used as a gasoline alternative in car engines. SOLUTION:Hydrogen can have only one bond so C and O must be next to each other with H filling in the bonds. There are 4(1) = 14 valence e -. C has 4 bonds and O has 2. O has 2 pair of nonbonding e -. COH H H H : :

SAMPLE PROBLEM 10.3Writing Lewis Structures for Molecules with Multiple Bonds. PLAN: SOLUTION: PROBLEM:Write Lewis structures for the following: (a) Ethylene (C 2 H 4 ), the most important reactant in the manufacture of polymers (b) Nitrogen (N 2 ), the most abundant atmospheric gas For molecules with multiple bonds, there is a Step 5 which follows the other steps in Lewis structure construction. If a central atom does not have 8e -, an octet, then e - can be moved in to form a multiple bond. (a) There are 2(4) + 4(1) = 12 valence e -. H can have only one bond per atom. CC H HH H : CC H HH H (b) N 2 has 2(5) = 10 valence e -. Therefore a triple bond is required to make the octet around each N. N : N :.... N : N :.. N : N :

Drawing Lewis Structures COCl 2 24 ve’s HOCl 14 ve’s CH 3 OH 14 ve’s Cl C Cl O  H O Cl  H C O H H H 