Momentum and Momentum Conservation Momentum Impulse Conservation of Momentum Collision in 1-D Collision in 2-D

So What’s Momentum ? Momentum = mass x velocity This can be abbreviated to :. momentum = mv Or, if direction is not an important factor :.. momentum = mass x speed So, A really slow moving truck and an extremely fast roller skate can have the same momentum.

Question : Under what circumstances would the roller skate and the truck have the same momentum ? The roller skate and truck can have the same momentum if the ratio of the speed of the skate to the speed of the truck is the same as the ratio of the mass of the truck to the mass of the skate. A 1000 kg truck moving at 0.01 m/sec has the same momentum as a 1 kg skate moving at 10 m/sec. Both have a momentum of 10 kg m/sec. ( 1000 x.01 = 1 x 10 = 10 ) 1000 kg1 kg.01 m/sec10 m/sec

Linear Momentum A new fundamental quantity, like force, energy The linear momentum p of an object of mass m moving with a velocity is defined to be the product of the mass and velocity: –The terms momentum and linear momentum will be used interchangeably in the text –Momentum depend on an object’s mass and velocity

Newton’s Law and Momentum Newton’s Second Law can be used to relate the momentum of an object to the resultant force acting on it The change in an object’s momentum divided by the elapsed time equals the constant net force acting on the object

If momentum changes, it’s because mass or velocity change. Most often mass doesn’t change so velocity changes and that is acceleration. And mass x acceleration = force Applying a force over a time interval to an object changes the momentum Force x time interval = Impulse Impulse = F t or Ft = mv Impulse and Momentum Ft = mv

Impulse-Momentum Theorem The theorem states that the impulse acting on a system is equal to the change in momentum of the system

FORCE An object at rest has no momentum, why? Because anything times zero is zero (the velocity component is zero for an object at rest) To INCREASE MOMENTUM, apply the greatest force possible for as long as possible. Examples : pulling a sling shot drawing an arrow in a bow all the way back a long cannon for maximum range hitting a golf ball or a baseball. (follow through is important for these !) TIME MOMENTUM

SOME VOCABULARY : impulse : impact force X time (newton. sec). Ft = impulse impact : the force acting on an object (N). usually when it hits something. impact forces : average force of impact

Decreasing Momentum Which would it be more safe to hit in a car ? Knowing the physics helps us understand why hitting a soft object is better than hitting a hard one. MOMENTUM mvmv mvmv FtFt FtFt

In each case, the momentum is decreased by the same amount or impulse (force x time) Hitting the haystack extends the impact time (the time in which the momentum is brought to zero). The longer impact time reduces the force of impact and decreases the deceleration. Whenever it is desired to decrease the force of impact, extend the time of impact ! MOMENTUM

DECREASING MOMENTUM If the time of impact is increased by 100 times (say from.01 sec to 1 sec), then the force of impact is reduced by 100 times (say to something survivable). EXAMPLES : Padded dashboards on cars Airbags in cars or safety nets in circuses Moving your hand backward as you catch a fast-moving ball with your bare hand or a boxer moving with a punch. Flexing your knees when jumping from a higher place to the ground. or elastic cords for bungee jumping Using wrestling mats instead of hardwood floors. Dropping a glass dish onto a carpet instead of a sidewalk.

EXAMPLES OF DECREASING MOMENTUM Bruiser Bruno on boxing … Increased impact time reduces force of impact Barbie on bungee Jumping … F t = change in momentum F t = change in momentum Ft = Δmv applies here. mv = the momentum gained before the cord begins to stretch that we wish to change. Ft = the impulse the cord supplies to reduce the momentum to zero. Because the rubber cord stretches for a long time the average force on the jumper is small.

Questions : When a dish falls, will the impulse be less if it lands on a carpet than if it lands on a hard ceramic tile floor ? The impulse would be the same for either surface because there is the same momentum change for each. It is the force that is less for the impulse on the carpet because of the greater time of momentum change. There is a difference between impulse and impact. If a boxer is able to increase the impact time by 5 times by “riding” with a punch, by how much will the force of impact be reduced? Since the time of impact increases by 5 times, the force of impact will be reduced by 5 times.

BOUNCING IMPULSES ARE GREATER WHEN AN OBJECT BOUNCES The impulse required to bring an object to a stop and then to throw it back upward again is greater than the impulse required to merely bring the object to a stop. When a martial artist breaks boards, does their hand bounce? Is impulse or momentum greater ? Example : The Pelton Wheel.

Calculating the Change of Momentum For the teddy bear For the bouncing ball

How Good Are the Bumpers?  In a crash test, a car of mass 1.5  10 3 kg collides with a wall and rebounds as in figure. The initial and final velocities of the car are v i =-15 m/s and v f = 2.6 m/s, respectively. If the collision lasts for 0.15 s, find (a) the impulse delivered to the car due to the collision (b) the size and direction of the average force exerted on the car

How Good Are the Bumpers?  In a crash test, a car of mass 1.5  10 3 kg collides with a wall and rebounds as in figure. The initial and final velocities of the car are v i =-15 m/s and v f = 2.6 m/s, respectively. If the collision lasts for 0.15 s, find (a) the impulse delivered to the car due to the collision (b) the size and direction of the average force exerted on the car

CONSERVATION OF MOMENTUM To accelerate an object, a force must be applied. The force or impulse on the object must come from outside the object. EXAMPLES : The air in a basketball, sitting in a car and pushing on the dashboard or sitting in a boat and blowing on the sail don’t create movement. Internal forces like these are balanced and cancel each other. If no outside force is present, no change in momentum is possible.

The Law of Conservation of Momentum In the absence of an external force, the momentum of a system remains unchanged. This means that, when all of the forces are internal (for EXAMPLE: the nucleus of an atom undergoing. radioactive decay,. cars colliding, or. stars exploding the net momentum of the system before and after the event is the same.

Conservation of Momentum In an isolated and closed system, the total momentum of the system remains constant in time. –Isolated system: no external forces –Closed system: no mass enters or leaves –The linear momentum of each colliding body may change. –The total momentum P of the system cannot change.

Conservation of Momentum Start from impulse-momentum theorem Since Then So

QUESTIONS 1. Newton’s second law states that if no net force is exerted on a system, no acceleration occurs. Does it follow that no change in momentum occurs? No acceleration means that no change occurs in velocity of momentum. 2. Newton’s 3 rd law states that the forces exerted on a cannon and cannonball are equal and opposite. Does it follow that the impulse exerted on the cannon and cannonball are also equal and opposite? Since the time interval and forces are equal and opposite, the impulses (F x t) are also equal and opposite.

ELASTIC COLLISIONS INELASTIC COLLISIONS COLLISIONS Momentum transfer from one Object to another. Is a Newton’s cradle like the one Pictured here, an example of an elastic or inelastic collision?

Problem Solving #1 A 6 kg fish swimming at 1 m/sec swallows a 2 kg fish that is at rest. Find the velocity of the fish immediately after “lunch”. net momentum before = net momentum after (net mv) before = (net mv) after (6 kg)(1 m/sec) + (2 kg)(0 m/sec) = (6 kg + 2 kg)(v after ) 6 kg. m/sec = (8 kg)(v after ) v after = 6 kg. m/sec / 8 kg 8 kg v after = ¾ m/sec v after =

Problem Solving #2 Now the 6 kg fish swimming at 1 m/sec swallows a 2 kg fish that is swimming towards it at 2 m/sec. Find the velocity of the fish immediately after “lunch”. net momentum before = net momentum after (net mv) before = (net mv) after (6 kg)(1 m/sec) + (2 kg)(-2 m/sec) = (6 kg + 2 kg)(v after ) 6 kg. m/sec + -4 kg. m/sec = (8 kg)(v after ) v after = 2 kg. m/sec / 8 kg 8 kg v after = ¼ m/sec v after =

Problem Solving #3 & #4 Now the 6 kg fish swimming at 1 m/sec swallows a 2 kg fish that is swimming towards it at 3 m/sec. (net mv) before = (net mv) after (6 kg)(1 m/sec) + (2 kg)(-3 m/sec) = (6 kg + 2 kg)(v after ) 6 kg. m/sec + -6 kg. m/sec = (8 kg)(v after ) v after = 0 m/sec Now the 6 kg fish swimming at 1 m/sec swallows a 2 kg fish that is swimming towards it at 4 m/sec. (net mv) before = (net mv) after (6 kg)(1 m/sec) + (2 kg)(-4 m/sec) = (6 kg + 2 kg)(v after ) 6 kg. m/sec + -8 kg. m/sec = (8 kg)(v after ) v after = -1/4 m/sec

The Archer  An archer stands at rest on frictionless ice and fires a 0.5-kg arrow horizontally at 50.0 m/s. The combined mass of the archer and bow is 60.0 kg. With what velocity does the archer move across the ice after firing the arrow?

Types of Collisions Momentum is conserved in any collision Inelastic collisions: rubber ball and hard ball –Kinetic energy is not conserved –Perfectly inelastic collisions occur when the objects stick together Elastic collisions: billiard ball –both momentum and kinetic energy are conserved Actual collisions –Most collisions fall between elastic and perfectly inelastic collisions

Collision between two objects of the same mass. One mass is at rest. Collision between two objects. One not at rest initially has twice the mass. Collision between two objects. One at rest initially has twice the mass. Simple Examples of Head-On Collisions (Energy and Momentum are Both Conserved)

Collision between two objects of the same mass. One mass is at rest. Example of Non-Head-On Collisions (Energy and Momentum are Both Conserved) If you vector add the total momentum after collision, you get the total momentum before collision.

Collisions Summary In an elastic collision, both momentum and kinetic energy are conserved In an inelastic collision, momentum is conserved but kinetic energy is not. Moreover, the objects do not stick together In a perfectly inelastic collision, momentum is conserved, kinetic energy is not, and the two objects stick together after the collision, so their final velocities are the same Elastic and perfectly inelastic collisions are limiting cases, most actual collisions fall in between these two types Momentum is conserved in all collisions

More about Perfectly Inelastic Collisions When two objects stick together after the collision, they have undergone a perfectly inelastic collision Conservation of momentum Kinetic energy is NOT conserved

An SUV Versus a Compact  An SUV with mass 1.80  10 3 kg is travelling eastbound at m/s, while a compact car with mass 9.00  10 2 kg is travelling westbound at m/s. The cars collide head-on, becoming entangled. (a) Find the speed of the entangled cars after the collision. (b) Find the change in the velocity of each car. (c) Find the change in the kinetic energy of the system consisting of both cars.

(a) Find the speed of the entangled cars after the collision. An SUV Versus a Compact

(b) Find the change in the velocity of each car. An SUV Versus a Compact

(c) Find the change in the kinetic energy of the system consisting of both cars. An SUV Versus a Compact

More About Elastic Collisions Both momentum and kinetic energy are conserved Typically have two unknowns Momentum is a vector quantity –Direction is important –Be sure to have the correct signs Solve the equations simultaneously

Elastic Collisions A simpler equation can be used in place of the KE equation

Summary of Types of Collisions In an elastic collision, both momentum and kinetic energy are conserved In an inelastic collision, momentum is conserved but kinetic energy is not In a perfectly inelastic collision, momentum is conserved, kinetic energy is not, and the two objects stick together after the collision, so their final velocities are the same

Problem Solving for 1D Collisions, 1 Coordinates: Set up a coordinate axis and define the velocities with respect to this axis –It is convenient to make your axis coincide with one of the initial velocities Diagram: In your sketch, draw all the velocity vectors and label the velocities and the masses

Problem Solving for 1D Collisions, 2 Conservation of Momentum: Write a general expression for the total momentum of the system before and after the collision –Equate the two total momentum expressions –Fill in the known values

Problem Solving for 1D Collisions, 3 Conservation of Energy: If the collision is elastic, write a second equation for conservation of KE, or the alternative equation –This only applies to perfectly elastic collisions Solve: the resulting equations simultaneously

One-Dimension vs Two-Dimension

Two-Dimensional Collisions For a general collision of two objects in two- dimensional space, the conservation of momentum principle implies that the total momentum of the system in each direction is conserved

Two-Dimensional Collisions The momentum is conserved in all directions Use subscripts for –Identifying the object –Indicating initial or final values –The velocity components If the collision is elastic, use conservation of kinetic energy as a second equation –Remember, the simpler equation can only be used for one-dimensional situations

Glancing Collisions The “after” velocities have x and y components Momentum is conserved in the x direction and in the y direction Apply conservation of momentum separately to each direction

Problem Solving for Two- Dimensional Collisions, 3 Conservation of Energy: If the collision is elastic, write an expression for the total energy before and after the collision –Equate the two expressions –Fill in the known values –Solve the quadratic equations Can’t be simplified

Problem Solving for Two- Dimensional Collisions, 4 Solve for the unknown quantities –Solve the equations simultaneously –There will be two equations for inelastic collisions –There will be three equations for elastic collisions Check to see if your answers are consistent with the mental and pictorial representations. Check to be sure your results are realistic

Collision at an Intersection  A car with mass 1.5×10 3 kg traveling east at a speed of 25 m/s collides at an intersection with a 2.5×10 3 kg van traveling north at a speed of 20 m/s. Find the magnitude and direction of the velocity of the wreckage after the collision, assuming that the vehicles undergo a perfectly inelastic collision and assuming that friction between the vehicles and the road can be neglected.

Collision at an Intersection

MOMENTUM VECTORS Momentum can be analyzed by using vectors The momentum of a car accident is equal to the vector sum of the momentum of each car A & B before the collision. A B

MOMENTUM VECTORS (Continued) When a firecracker bursts, the vector sum of the momenta of its fragments add up to the momentum of the firecracker just before it exploded. The same goes for subatomic elementary particles. The tracks they leave help to determine their relative mass and type.