A4.1 GT Geometry. Simplify each expression. 1. 90 – (x + 20) 2. 180 – (3x – 10) Write an algebraic expression for each of the following. 3. 4 more than.

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Presentation transcript:

A4.1 GT Geometry

Simplify each expression – (x + 20) – (3x – 10) Write an algebraic expression for each of the following more than twice a number 4. 6 less than half a number 70 – x 190 – 3x 2n + 4 Drill: Thurs, 9/16 OBJ: SWBAT identify adjacent, vertical, complementary, and supplementary angles in order to find angle measures.

M OTIVATION

W HAT ARE A DJACENT A NGLES ?

Holt McDougal Geometry 1-4 Pairs of Angles Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent. Example 1A: Identifying Angle Pairs AEB and BED AEB and BED have a common vertex, E, a common side, EB, and no common interior points. Their noncommon sides, EA and ED, are opposite rays. Therefore, AEB and BED are adjacent angles and form a linear pair.

Holt McDougal Geometry 1-4 Pairs of Angles Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent. Example 1B: Identifying Angle Pairs AEB and BEC AEB and BEC have a common vertex, E, a common side, EB, and no common interior points. Therefore, AEB and BEC are only adjacent angles.

Holt McDougal Geometry 1-4 Pairs of Angles DEC and AEB DEC and AEB share E but do not have a common side, so DEC and AEB are not adjacent angles. Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent. Example 1C: Identifying Angle Pairs

Holt McDougal Geometry 1-4 Pairs of Angles Check It Out! Example 1a 5 and 6 Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent. 5 and 6 are adjacent angles. Their noncommon sides, EA and ED, are opposite rays, so 5 and 6 also form a linear pair.

Holt McDougal Geometry 1-4 Pairs of Angles Check It Out! Example 1b 7 and SPU Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent. 7 and SPU have a common vertex, P, but do not have a common side. So 7 and SPU are not adjacent angles.

Holt McDougal Geometry 1-4 Pairs of Angles Check It Out! Example 1c 7 and 8 Tell whether the angles are only adjacent, adjacent and form a linear pair, or not adjacent. 7 and 8 have a common vertex, P, but do not have a common side. So 7 and 8 are not adjacent angles.

C OMPLEMENTARY & S UPPLEMENTARY A NGLE M ATCH -U P

G EO S KETCH FOR V ERTICAL A NGLES

Another angle pair relationship exists between two angles whose sides form two pairs of opposite rays. Vertical angles are two nonadjacent angles formed by two intersecting lines.  1 and  3 are vertical angles, as are  2 and  4.

A LGEBRA AND A NGLES (RS A4 D )

Light passing through a fiber optic cable reflects off the walls of the cable in such a way that  1 ≅  2,  1 and  3 are complementary, and  2 and  4 are complementary. If m  1 = 47°, find m  2, m  3, and m  4. Example 4: Problem-Solving Application

1 Understand the Problem The answers are the measures of  2,  3, and  4. List the important information:  1   2  1 and  3 are complementary, and  2 and  4 are complementary. m  1 = 47°

2 Make a Plan If  1   2, then m  1 = m  2. If  3 and  1 are complementary, then m  3 = (90 – 47)°. If  4 and  2 are complementary, then m  4 = (90 – 47)°.

Solve 3 By the Transitive Property of Equality, if m  1 = 47° and m  1 = m  2, then m  2 = 47°. Since  3 and  1 are complementary, m  3 = 43°. Similarly, since  2 and  4 are complementary, m  4 = 43°.

Look Back4 The answer makes sense because 47° + 43° = 90°, so  1 and  3 are complementary, and  2 and  4 are complementary. Thus m  2 = 47°, m  3 = 43°, and m  4 =43°.

What if...? Suppose m  3 = 27.6°. Find m  1, m  2, and m  4. Check It Out! Example 4

1 Understand the Problem The answers are the measures of  1,  2, and  4. List the important information:  1   2  1 and  3 are complementary, and  2 and  4 are complementary. m  3 = 27.6°

2 Make a Plan If  1   2, then m  1 = m  2. If  3 and  1 are complementary, then m  1 = (90 – 27.6)°. If  4 and  2 are complementary, then m  4 = (90 – 27.6)°.

Solve 3 By the Transitive Property of Equality, if m  1 = 62.4° and m  1 = m  2, then m  2 = 62.4°. Since  3 and  1 are complementary, m  3 = 27.6°. Similarly, since  2 and  4 are complementary, m  4 = 27.6°.

Look Back4 The answer makes sense because 27.6° ° = 90°, so  1 and  3 are complementary, and  2 and  4 are complementary. Thus m  1 = m  2 = 62.4°; m  4 = 27.6°.