38° z SohCah Toa 10’  y. β SohCah Toa 15cm  x 24cm.

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Presentation transcript:

38° z SohCah Toa 10’  y

β SohCah Toa 15cm  x 24cm

37˚ SohCah Toa  x 15.5cm y

13.5° x SohCah Toa 22.3”  y

15.5 m SohCah Toa 31 m  x 

28 Given regular square pyramid with slant height of 50ft. The perimeter of the Base is 112ft Find the altitude. 14 x 50 Family! (7 – 24 – 25) x = 48ft

Find the diagonal of a regular rectangular prism with dimensions of 9, 12, and 20 Find the altitude = x 2 Family! (3 – 4 – 5) x = 25

√2 = 42√2 2 21√ √2 45  I have the hyp, so to get the legs, divide by √2 42 √2 = 21√2 45  Answers in simplified radical form Use special right ∆ rules to solve the triangle. Answers in simplified radical form

12√3 60  18 6√3 30  I have the long leg, so get short leg first by dividing by √3 Then, from the short leg to get the hyp, multiply by 2 √3 = 18√ √3 = 6√3 Answers in simplified radical form Use special right ∆ rules to solve the triangle. Answers in simplified radical form