Organic chemistry Assistance Lecturer Amjad Ahmed Jumaa Nucleophilic aliphatic substitution. Substitution nucleophilic bimolecular (SN 2 ). The (SN 2 ) mechanism of nucleophilic substitution. 1
Nucleophilic aliphatic substitutions: Alkyl halides: We shall consider as alkyl halides all compounds of the general formula R─X, where R is any simple alkyl or substituted alkyl group. For example. Nucleophilic aliphatic substitutions: Alkyl halides: We shall consider as alkyl halides all compounds of the general formula R─X, where R is any simple alkyl or substituted alkyl group. For example.
Alkyl halides are classified into primary, secondary, tertiary according to the degree of substitution of the carbon that bears the halogen atom(X). RCH 2 X (1º) primary alkyl halide, example, ethyl bromide CH 3 CH 2 Br. R 2 CHX (2º) secondary alkyl halide, example, 2-chloropropane, CH 3 CHBrCH 3. R 3 CX (3º) tertiary alkyl halide, example, 2-chloro-2- methylpropane. Alkyl halides are classified into primary, secondary, tertiary according to the degree of substitution of the carbon that bears the halogen atom(X). RCH 2 X (1º) primary alkyl halide, example, ethyl bromide CH 3 CH 2 Br. R 2 CHX (2º) secondary alkyl halide, example, 2-chloropropane, CH 3 CHBrCH 3. R 3 CX (3º) tertiary alkyl halide, example, 2-chloro-2- methylpropane.
Substitution nucleophilic bimolecular (SN 2 ) The term bimolecular is used here since the rate-determining step involves collision of two particles. For example: The reaction between methyl bromide and hydroxide ion to yield methanol. Substitution nucleophilic bimolecular (SN 2 ) The term bimolecular is used here since the rate-determining step involves collision of two particles. For example: The reaction between methyl bromide and hydroxide ion to yield methanol. When hydroxide ion collides with a methyl bromide molecule at the face most remote from the bromine, and when such a collision has sufficient energy, a C─OH bond forms and the C─Br bond breaks, liberating bromide ion. The (SN 2 ) reactions the order of reactivity of R─X is CH 3 X > 1º > 2º > 3º.
The (SN 2 ) mechanism of nucleophilic substitution: The reaction proceeds in one (single) step, the hydroxide ion acts as a nucleophile. While the C─Br bond is breaking, the C─O bond is forming. The reaction involves forming the transition state. Look at the following steps. The hydroxide ion (OH - ) attacks the methyl bromide from the opposite side to form the transition state and the product methanol in one step.
The transition state: hydroxide ion (OH - ) attacks from the opposite the C─Br bond. The transition state in the following figure:
Problem: expect the product when 2-bromooctane treated with the sodium hydroxide in the presence of (ethanol-water) as solvent. Explain the transition state for the product. Solution : The transition state for the product:
Follow problem: write an equation for the reaction of 2- bromopropane with sodium hydroxide in the presence of the (ethanol-water) as a solvent, explain the transition state for the product.