CHAPTER SEVEN Groundwater

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Presentation transcript:

CHAPTER SEVEN Groundwater Engineering Hydrology (ECIV 4323) CHAPTER SEVEN Groundwater Instructors: Dr. Yunes Mogheir Dr. Ramadan Al Khatib

1. The occurrence of groundwater Aquifer: the water bearing strata Unconsolidated formation: sands, gravel (Porous aquifer) Consolidated formation: sandstone, limestone (karstic aquifer) Permeability: the measurement of resistance of underground flow due to gradational forces.

Type of aquifer Confined aquifer Unconfined aquifer Phreatic surface, spring, impermeable, river, confined, artesian spring, artesian well, fault

5.2 Factors of Influence Groundwater flow is laminar. Density: greater importance is salinity Viscosity: measure of shear strength of a liquid

5.2 Factors of Influence Porosity: (Ranges from few% to 90%) The more regular the soil, the more porous it tends to be. Effective porosity ne In coarse gravel’s ne = n, in fine material the difference may be 5%,

5.2 Factors of influence Permeability: is a function of Porosity, Structure (grain size, shape of the particles, distribution), Geological history Permeability may vary in horizontal and vertical directions (anisotropic) Permeability is defined by permeability coefficient (k) For homogeneous rounded grain media: k (m/d) = c (d10 )2 d10 = the grain size in mm where 10% is finer and 90% is coarse c: constant 400-1200 This formula is widely used with sand filter for water supply. It only applies to homogeneous rounded grain media.

k for clean gravel 1-100 cm/s, fine sand 0. 001-0 k for clean gravel 1-100 cm/s, fine sand 0.001-0.05 cm/s, Clay <10-6 cm/s

5.3 Ground flow Darcy law: applied under the following assumption: The material is homogenous and isotropic There is no capillary zone Steady state of flow v = rate of flow/unit area which is proportional to i, where i = gradient of potential head

5.3 Ground flow

5.3 Ground flow Note that the specific velocity used in Darcy’s law is not the actual velocity; but is merely Q/A The actual velocity in the pores is greater than the specific velocity (why?).

5.3.1 Flow in a confined aquifer If there is no change in flow from point to point: Then,

5.3.1 Flow in phreatic aquifer (unconfined) Darcy law: vs =-k dφ/dL By using Dupuit assumptions Then dφ/dL = dh/dx

5.3.1 Flow in phreatic aquifer (unconfined) The following is a proof of how

5.3.1 Flow in Phreatic Aquifer (unconfined) The case of having Net Infiltration N from rainfall

Example 5.1

5.4 The abstraction of groundwater Steps for well drilling Rotary method is commonly used As the well drilled it is cased with steel casing to prevent wall collapse Screen is constructed at the bottom of the well The screen is covered by gravel packs Once the water has entered though the well it has to be pumped to the surface by pumps (rotating vertical shaft; submersible)

5.4 The abstraction of groundwater

5.4 The abstraction of groundwater PVC pipes and screens are available from 33mm diameter to 630mm diameter

5.5 The yield of well 5.5.1 Steady confined flow Darcy law: Q=A vs =-k ds/dr . 2πrH Q=Q0 ………..continuity

5.5 The yield of well 5.5.1 Steady confined flow Darcy law: Q=A vs =-k ds/dr . 2πrH Q=Q0 ………..continuity Theim’s equation: S1-S2=(Q0/2 πkH )x ln(r2/r1) (KH is transmissibility coefficient ) Valid for steady and unsteady, confined and unconfined

5.5 The yield of well S= (Q0/2 πkH) x ln(r)+c S=0 when r=R S= (Q0/2 πkH) x ln(R/r) Q0&R can be determined from the boundary conditions Q0: constant discharge of the well R=R0 where the drawdown is close to the well that is important

5.5 The yield of well 5.5.2 Steady unconfined flow When the drawdown is slight comparing with H use the case of confined aquifer Darcy flow: Q=2πr.h.k.(dh/dr) Q=Q0

5.5 The yield of well 5.5.2 Steady unconfined flow h2=Q0/πk . ln(r) +c if h = H, at r = R H2-h2 = Q0/πk . ln(R/r) (boundary conditions) Well face (H-h0) -- H2-h02 = Q0/πk . ln(R/r0)

5.5 The yield of well 5.5.2 Steady unconfined flow with rainfall Q=2 πr.h.k.(dh/dr) For continuity dQ=-2πr.dr.N (N=net infiltration) Q= -πr2N+C Q= -πr2N+Q0 where r =r0=0, Q=Q0

5.5 The yield of well h2=Q0/πk . ln(r) +Nr2/2k+C2 r=R h=H S=H2- Q0/πk . ln(R)+N/2k . R2 (depend on boundary conditions) H2-h2 = Q0/πk x ln(R/r) – N/2k . (R2-r2) When Q0 = 0 (No pumping) H2-h2 =– N/2k . (R2-r2)

Example 5.4

Example 5.4

Example 5.4

Example 5.4

5.6 Test Pumping Analysis In addition to boring test which provide information about the geology of the aquifer, the extent of the yield aquifer can finally be determined only by pumping test. Pumping test: The extent of the yield of an aquifer can finally be determined only by test pumping from a well. Such a well should be positioned so that observation wells are placed on either side of it, on a line through the well, and preferably on two lines at right angles with the pumping well at the intersection. Pumping tests can be performed by pumping from the well until steady-state conditions are obtained. Observation wells should be placed at increasing intervals from the pumping well (say at 20, 50, 100, 200, and 500 m)

5.6 Test Pumping Analysis Pumping test in confined aquifer S= Q0/2πkH x ln(R/r) Observed S are plotted against distance r (logarithmic scale) then straight line is obtained where S=A-Blog(r) Then kH=(1/B) . (1.15Q0/π)

Example 5.5

…example 5.5 First, draw the relationship between s and log(r). The graph is shown in the previous slide. This will give you a linear relationship. The slope of the resulting line is B. The resulting line will intersect the x-axis at the radius of influence ( since s = 0). To compute B: at s = 0, r = 610 and log(r) = 2.79 at s = 1.2, r = 10 and log(r) = 1.0 B = (1.2 – 0)/(2.79 – 1.0) = 0.67 , which is the slope of the line kH = (1/B) . (1.15Q0/π) = (1/0.67).(1.15) . (0.03 / π) = 1.64x10-2 m2/s To find the radius of influence, R: The line intersects the x-axis at the value of R (since this is corresponding to a zero drawdown). → R = 610 m To find the value of A: slope = 0.67 = y/x = A / log(610) A = (0.67) . Log(610) = 2.79