Using Recursion1 Recursion © 2010 Goodrich, Tamassia.

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Using Recursion1 Recursion © 2010 Goodrich, Tamassia

Intro to Recursion  Recursion: when a function calls itself  Types of recursion Linear recursion: one recursive call  Tail recursion: One recursive call at the very end Binary recursion: Two recursive calls Multiple recursion: More than two recursive calls © 2010 Goodrich, Tamassia2Using Recursion

3 Example: Factorial Function  Classic example--the factorial function: n! = 1· 2· 3· ··· · (n-1)· n  Recursive definition:  As a C++ method: // recursive factorial function int recursiveFactorial(int n) { if (n==0) return 1;// base case return n*recursiveFactorial(n- 1);// recursive case } © 2010 Goodrich, Tamassia

Using Recursion4 Linear Recursion  Test for base cases Begin by testing for a set of base cases (there should be at least one). Every possible chain of recursive calls must eventually reach a base case, and the handling of each base case should not use recursion.  One recursive call Perform a single recursive call This step may have a test that decides which of several possible recursive calls to make, but it should ultimately make just one of these calls Define each possible recursive call so that it makes progress towards a base case. © 2010 Goodrich, Tamassia

Using Recursion5 Example of Linear Recursion Algorithm LinearSum(A, n): Input: A integer array A and an integer n = 1, such that A has at least n elements Output: The sum of the first n integers in A if n = 1 then return A[0] else return LinearSum(A, n - 1) + A[n - 1] Example recursion trace: © 2010 Goodrich, Tamassia

Using Recursion6 Reversing an Array Algorithm ReverseArray(A, i, j): Input: An array A and nonnegative integer indices i and j Output: The reversal of the elements in A starting at index i and ending at j if i<j then Swap A[i] and A[ j] ReverseArray(A, i + 1, j - 1) return © 2010 Goodrich, Tamassia

Using Recursion7 Defining Arguments for Recursion  In creating recursive methods, it is important to define the methods in ways that facilitate recursion.  This sometimes requires we define additional paramaters that are passed to the method.  For example, we defined the array reversal method as ReverseArray(A, i, j), not ReverseArray(A). © 2010 Goodrich, Tamassia

Using Recursion8 Computing Powers  The power function, p(x,n)=x n, can be defined recursively:  This leads to an power function that runs in O(n) time (for we make n recursive calls).  We can do better than this, however. © 2010 Goodrich, Tamassia

Using Recursion9 Recursive Squaring  We can derive a more efficient linearly recursive algorithm by using repeated squaring:  For example, 2 4 = 2 ( 4 / 2 ) 2 = ( 2 4 / 2 ) 2 = ( 2 2 ) 2 = 4 2 = = 2 1 +( 4 / 2 ) 2 = 2 ( 2 4 / 2 ) 2 = 2 ( 2 2 ) 2 = 2 ( 4 2 ) = = 2 ( 6 / 2)2 = ( 2 6 / 2 ) 2 = ( 2 3 ) 2 = 8 2 = = 2 1 +( 6 / 2 ) 2 = 2 ( 2 6 / 2 ) 2 = 2 ( 2 3 ) 2 = 2 ( 8 2 ) = 128. © 2010 Goodrich, Tamassia

Using Recursion10 Recursive Squaring Method Algorithm Power(x, n): Input: A number x and integer n = 0 Output: The value x n if n = 0then return 1 if n is odd then y = Power(x, (n - 1)/ 2) return x·y·y else y = Power(x, n/ 2) return y·y It is important that we use a variable twice here rather than calling the method twice. Each time we make a recursive call we halve the value of n; hence, we make log n recursive calls. That is, this method runs in O(log n) time. © 2010 Goodrich, Tamassia

Using Recursion11 Tail Recursion  Tail recursion occurs when a linearly recursive method makes its recursive call as its last step.  The array reversal method is an example.  Such methods can be easily converted to non- recursive methods (which saves on some resources).  Example: Algorithm IterativeReverseArray(A, i, j ): Input: An array A and nonnegative integer indices i and j Output: The reversal of the elements in A starting at index i and ending at j while i < j do Swap A[i ] and A[ j ] i = i + 1 j = j - 1 return © 2010 Goodrich, Tamassia

Using Recursion12 Binary Recursion  Binary recursion occurs whenever there are two recursive calls for each non-base case.  Example: the DrawTicks method for drawing ticks on an English ruler. © 2010 Goodrich, Tamassia

Using Recursion13 A Binary Recursive Method for Drawing Ticks © 2010 Goodrich, Tamassia Note the two recursive calls Draw inch labels

Using Recursion14 Another Binary Recusive Method  Problem: add all the numbers in an integer array A: Algorithm BinarySum(A, i, n): Input: An array A and integers i and n Output: The sum of the n integers in A starting at index i if n = 1 then return A[i ] return BinarySum(A, i, n/ 2) + BinarySum(A, i + n/ 2, n/ 2)  Example trace: © 2010 Goodrich, Tamassia

Using Recursion15 Computing Fibonacci Numbers  Fibonacci numbers are defined recursively: F 0 = 0 F 1 = 1 F i = F i F i - 2 for i > 1.  Recursive algorithm (first attempt): Algorithm BinaryFib( k ) : Input: Nonnegative integer k Output: The kth Fibonacci number F k if k = 1 then return k else return BinaryFib( k - 1 ) + BinaryFib( k - 2 ) © 2010 Goodrich, Tamassia

Using Recursion16 Analysis  Let n k be the number of recursive calls by BinaryFib(k) n 0 = 1 n 1 = 1 n 2 = n 1 + n = = 3 n 3 = n 2 + n = = 5 n 4 = n 3 + n = = 9 n 5 = n 4 + n = = 15 n 6 = n 5 + n = = 25 n 7 = n 6 + n = = 41 n 8 = n 7 + n = = 67.  Note that n k at least doubles every other time  That is, n k > 2 k/2. It is exponential! © 2010 Goodrich, Tamassia

Using Recursion17 A Better Fibonacci Algorithm  Use linear recursion instead Algorithm LinearFibonacci(k): Input: A nonnegative integer k Output: Pair of Fibonacci numbers (F k, F k  1 ) if k = 1 then return (k, 0) else (i, j) = LinearFibonacci(k  1) return (i +j, i)  LinearFibonacci makes k  1 recursive calls © 2010 Goodrich, Tamassia

Using Recursion18 Multiple Recursion  Motivating example: summation puzzles  pot + pan = bib  dog + cat = pig  boy + girl = baby  Multiple recursion: makes potentially many recursive calls not just one or two © 2010 Goodrich, Tamassia

Using Recursion19 Algorithm for Multiple Recursion Algorithm PuzzleSolve(k, S, U): Input: Integer k, sequence S, and set U (universe of elements to test) Output: Enumeration of all k-length extensions to S using elements in U without repetitions for all e in U do if k = 0 then if S solves the puzzle then return “Solution found: ” S else PuzzleSolve(k-1, S+e, U-{e}) © 2010 Goodrich, Tamassia

Example © 2010 Stallmann20Using Recursion cbb + ba = abca,b,c stand for 7,8,9; not necessarily in that order [] {a,b,c} [a] {b,c} a=7 [b] {a,c} b=7 [c] {a,b} c=7 [ab] {c} a=7,b=8 c=9 [ac] {b} a=7,c=8 b=9 [ba] {c} b=7,a=8 c=9 [bc] {a} b=7,c=8 a=9 [ca] {b} c=7,a=8 b=9 [cb] {a} c=7,b=8 a=9 might be able to stop sooner Slide by Matt Stallmann included with permission = 997

Using Recursion21 Visualizing PuzzleSolve © 2010 Goodrich, Tamassia