Stoichiometry !!
Problem What mass of CdS is produced if 8.47g of cadmium reacts with 2.51g of sulfur ? Cd + S CdS Next!!
What’s The First Step To Solving This Problem ? . Figure Out The Grams For Cd Convert The Grams Into Moles. Make Sure The Problem Is Balanced. Back !!
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The Next Step Is Changing 8. 47g of Cd Into Moles The Next Step Is Changing 8.47g of Cd Into Moles. How Would You Do That ? . 112.41gCd * 8.47gCd * Back To Problem !!
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The Next Step Is: Where Did The 1’s Come From ? The Mass The Charges The coefficients Back To The Problem !!
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The Mass of CdS (144.47)would go over ?? 1molCdS 1molCd 112.41gCd Back To Problem !!
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Do The Calculations !! 8.47gCd * * * is equal to ?? 10.89gCd 10.89molCd 10.89gCdS Back To Problem !!
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Now, Change 2.51gS into grams of CdS. 2.51gS * * * = 11.31gS 2.51gS * * * = 11.31gCd 2.51gS * * * = 11.31gCdS
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8.47gCd is 10.89gCdS. 2.51gS is 11.31gCdS. Which one is the limiting reactant ?
Your Finished !! Good Job !!
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