Indicate what effect the change will have on the acceleration. The mass of the cart is increased to 2 kg.

For 100 points The acceleration decreases

Indicate what effect the change will have on the acceleration. The towing force is increased to 1.0 N.

For 500 points The acceleration increases

Indicate what effect the change will have on the acceleration. Both the mass of the cart and the towing force are doubled.

For 300 points The acceleration remains the same

Indicate what effect the change will have on the acceleration. The 0.5 N towing force is applied at an angle as shown at right.

For 1000 points The acceleration decreases

Indicate what effect the change will have on the acceleration. The track is inclined as shown below at right.

For 2500 points The acceleration decreases

Indicate what effect the change will have on the acceleration. The 0.5 N force is applied to two 500 g carts hooked together as shown below right.

For 400 points The acceleration remains the same

Draw the position vs. time and acceleration vs Draw the position vs. time and acceleration vs. time graphs corresponding to the velocity graph between points c and d

For 100 points

For the interval from a to b the train is: a. speeding up. b. slowing down. c. moving at constant speed. d. moving in the negative direction.

For 10000 points b. slowing down

Is the net force on the train equal to zero at any time? Explain.

For 50000 points From b to c because the train is moving at a constant speed

Where is the net force on the train the largest? Explain.

For 1000 points From c to d because the acceleration is the greatest between those two points

A 700. kg Yugo can go from rest to a speed of 45 m/s in 9. 0s A 700. kg Yugo can go from rest to a speed of 45 m/s in 9.0s. What average net force acts on the car?

For 100 points 3500 N

Consider the block on a surface below Consider the block on a surface below. The coefficient of friction, µ, is 0.20. If a 10. N force is applied to the block, what is its acceleration?

For 8000 points 3 m/s2

Consider the block on a surface below Consider the block on a surface below. The coefficient of friction, µ, is 0.20. How fast will the block be moving if the force of 10 N is applied for 5.0s?

For 200 points 15 m/s

Consider the block on a surface below Consider the block on a surface below. The coefficient of friction, µ, is 0.20. How far will the block travel if the force of 10 N is applied for 5.0s?

For 300 points 38 m

The diagram below depicts a frictionless apparatus similar to that used for your Newton's 2nd Law experiment. Block A has a mass of 25 kg and block B has a mass of 5.0 kg. Determine the acceleration of the system and the tension in the string.

For 3000 points 1.6 m/s2 41 N

A 70. 0 kg box is pulled across a frictionless surface by a 300 A 70.0 kg box is pulled across a frictionless surface by a 300. N force at an angle of 30.° to the horizontal. What is the acceleration of the box in the x-direction?

For 400 points 3.7 m/s2

A 70. 0 kg box is pulled across a frictionless surface by a 300 A 70.0 kg box is pulled across a frictionless surface by a 300. N force at an angle of 30.° to the horizontal. What is the normal force on the box?

For 500 points 536 N

A 20.0 kg block is allowed to accelerate down a ramp with negligible friction. Determine the acceleration of the block.

For 200 points 3.2 m/s2

A 20.0 kg block is allowed to accelerate down a ramp with negligible friction. Would the acceleration be different if the mass of the block were 10kg? Explain.

For 600 points No, because it is gravity that is pulling the block down the ramp. Only changing the incline changes the acceleration, as long as the ramp is frictionless.

For 300 points