Warm-up Solve for missing variable: 1)(14√2)² = 14² + b² 2)A = (b1 + b2)h/2; for b1.

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Presentation transcript:

Warm-up Solve for missing variable: 1)(14√2)² = 14² + b² 2)A = (b1 + b2)h/2; for b1

9.3 The Converse of the Pythagorean Theorem Geometry NCSCOS: 1.02; 2.03

Essential Question: How can we use the Converse of Pythagorean Theorem? How can we use the lengths of triangles to classify them by angle measures?

What did we learn so far? 9.1 short review 9.2 short review Check the work from yesterday Tomorrow quiz:

Using the Converse The Converse of the Pythagorean Theorem is True. Remember “Converse” means “Reverse.”

Theorem 9.5: Converse of the Pythagorean Theorem If the square of the length of the longest side of the triangle is equal to the sum of the squares of the lengths of the other two sides, then the triangle is a right triangle. If c 2 = a 2 + b 2, then ∆ABC is a right triangle.

Note: Use the Converse of the Pythagorean Theorem to show that a given triangle is a right triangle.

Ex. 1: Verifying Right Triangles Check to see whether the side lengths satisfy the equation √113 The triangle is a right triangle.

Ex. 2: Verifying Right Triangles 4√95 The triangle is NOT a right triangle.

Classifying Triangles Sometimes it is hard to tell from looking at a triangle whether it is obtuse or acute. The theorems on the following slides can help you tell.

Theorem 9.6—Triangle Inequality If the square of the length of the longest side of a triangle is less than the sum of the squares of the lengths of the other two sides, then the triangle is acute. If c 2 < a 2 + b 2, then ∆ABC is acute c 2 < a 2 + b 2

Theorem 9.7—Triangle Inequality If the square of the length of the longest side of a triangle is greater than the sum of the squares of the lengths of the other two sides, then the triangle is obtuse. If c 2 > a 2 + b 2, then ∆ABC is obtuse c 2 > a 2 + b 2

Ex. 2: Classifying Triangles Decide whether the set of numbers can represent the side lengths of a triangle. If they can, classify the triangle as right, acute or obtuse. a.38, 77, 86b. 10.5, 36.5, 37.5

Triangle Inequality to confirm Example 2a c 2 ? a 2 + b ? c 2 is greater than a 2 + b 2 The triangle is obtuse

Triangle Inequality to confirm Example 2b c 2 ? a 2 + b ? c 2 is less than a 2 + b 2 The triangle is acute

Ex. 3: Building a foundation Construction: You use four stakes and string to mark the foundation of a house. You want to make sure the foundation is rectangular. A friend measures the four sides to be 30 feet, 30 feet, 72 feet, and 72 feet. He says these measurements prove that the foundation is rectangular. Is he correct?

Ex. 3: Building a foundation Solution: Your friend is not correct. The foundation could be a nonrectangular parallelogram, as shown below.

b. You measure one of the diagonals to be 78 feet. Explain how you can use this measurement to tell whether the foundation will be rectangular.

Ex. 3: Building a foundation Solution: The diagonal divides the foundation into two triangles. Compare the square of the length of the longest side with the sum of the squares of the shorter sides of one of these triangles. Because = 782, you can conclude that both the triangles are right triangles. The foundation is a parallelogram with two right angles, which implies that it is rectangular