Definition of Sine and Cosine Revisited Suppose P = (x,y) is the point on the unit circle specified by the angle. We define the functions, cosine of, or, and the sine of, or, by either pair of formulas: (-1,0) Hypotenuse Side Opposite Side Adjacent

The Tangent Function Revisited Suppose P = (x, y) is the point on the unit circle specified by the angle. We define the tangent of, or tan, by tan = y/x, or by: Side Opposite Side Adjacent

Solving Right Triangles One of the angles of a right triangle is 90°. Thus, one part is already known and the only additional information necessary is either two sides or an acute angle and a side. With this additional information, it is possible to solve for the remaining parts. Making a carefully labeled sketch of the triangle is important in solving these problems. Problem 23, page 305. The top of a 200-foot tower is to be anchored by cables that make an angle of 30° with the ground. How long must the cables be? How far from the base of the tower should the anchors be placed? sin 30° = 200/h => h = 200/sin 30° = 400 ft tan 30° = 200/x => x = 200/tan 30° = ft 200 ft h x 30°

Solving Non-right Triangles Suppose the triangle to be solved does not contain a right angle. If we are given three parts of the triangle, not all angles, then we can solve for the remaining parts. The solution exists and is unique except in one case--discussed in a later slide. Usually we label the angles of the triangle as A, B, C and the sides opposite these angles as a, b, and c, respectively. Law of Cosines: Law of Sines: ba c A C B

An example using the Law of Cosines A person leaves her home and walks 5 miles due east and then 3 miles northeast. How far away from home (as the crow flies) is she? As seen from her home, what is the angle  between the easterly direction and the direction to her destination? By applying the Law of Cosines, we can solve for x: A second application of the Law of Cosines gives: Home Destination x °135° N

An example using the Law of Sines Problem 29, page 312. Two fire stations are located 56.7 miles apart, at points A and B. There is a forest fire at point C. If  CAB = 54° and  CBA = 58°, which fire station is closer? How much closer? The fire station at point B is closer to the fire by – = miles. 54° 68° 58° C AB b c = 56.7 miles a

The ambiguous case for solving a triangle Suppose we are given two sides of a triangle and the angle opposite one of them, and we are asked to find the remaining parts of the triangle. Depending on the data given, there may be: two possible triangles, one possible triangle, or no possible triangle. Example.  CAB = 45°, b = 1, and various values of a: No triangle exists. b=1 45° a=  2/2 b=1 a=3/10 One triangle exists. A b=1 45° a=8/10 A Two triangles exist. b=1 45° A a=11/10 45° A C CC B B C

Summary for Trigonometry Sine, cosine, and tangent were redefined in terms of right triangles. Right triangles in which either two sides or an acute angle and a side are given can be solved. We may consider solving non-right triangles in which three parts, not all angles, are given. The solution exists and is unique except in the ambiguous case when two sides and the angle opposite one of them are given. In the ambiguous case, there may be: two possible triangles, one possible triangle, or no possible triangle. The law of cosines is a generalization of the Pythagorean theorem that works for any triangle. The law of sines is useful when we know a side and the angle opposite it.