Evaluating a Permutation EXAMPLE 3 Evaluating a Permutation Poetry Two students are chosen from a group of 6 to read the first and second poems at the school’s poetry reading. To find how many different ways the students can be chosen, find 6P2. 6P2 – = 6! (6 2)! 4! Use permutation formula. = 6 5 4 3 2 1 4 3 2 1 Divide out common factors. = 30 Multiply. ANSWER The students can be chosen in 30 ways.
GUIDED PRACTICE for Example 3 Find the number of permutations. 6. 5P3 = 60 7. 6P6 = 720
GUIDED PRACTICE for Example 3 8. 8P7 = 40, 320 9. 100P2 = 9, 900
GUIDED PRACTICE for Example 3 10. What If? Suppose 3 students are chosen from a group of 8 to read in Example 3. In how many different ways can the students be chosen? To find how many different ways can the students be chosen, find . 8P3 = 336 8P3