Section 1.1 Slopes and Equations of Lines

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Presentation transcript:

Section 1.1 Slopes and Equations of Lines

Slope of a line If a line passes through two points (x1,y1) and (x2,y2), then its slope is given by The slope of a horizontal line is 0 The slope of a vertical line is undefined

Slope-Intercept form of a line If a line has slope m and y-intercept (0,b), then the equation of the line is given by

Example Graph Solution: The y-intercept is (0, 2).

Point-Slope form of a line If a line has slope m and passes through a point (x1,y1), then the equation of the line is given by

Example Find the equation of the line containing the points (2, 7) and (1, 8). Solution: First determine the slope: Using the point-slope equation,

Horizontal and vertical lines Horizontal line has equation of the form Vertical line has equation of the form

General Form of a Line Examples: 2x + y = 10 x – 5 = 1 3y – 9 = 0

Parallel Lines Vertical lines are parallel. Nonvertical lines are parallel if and only if they have the same slope and different y-intercepts. y = 3x + 2 y = 3x  4

Perpendicular Lines Two lines with slopes m1 and m2 are perpendicular if and only if the product of their slopes is 1: m1m2 = 1. Lines are also perpendicular if one is vertical (x = a) and the other is horizontal (y = b). y = 3x  4

Examples Determine whether each of the following pairs of lines is parallel, perpendicular, or neither. a) y  4x =  3, 4y  8 =  x (perpendicular) b) 2x + 3y = 4, 3x + 2y = 8 (neither) c) 2y = 4x + 12, y  8 = 2x (parallel)

Example Write an equation of the line containing the point (1,  2) and is (a) parallel to the line 3y + 4 = 18x. (b) perpendicular to the line 3y + 4 = 18x. Solution: Solve the equation for y: So, its slope is 6.

Example continued The line parallel to the given line will have the same slope, which is 6.

Example continued (b) For a line perpendicular, its slope will be m =