Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 1 of 34 Chapter 11 Section 1 Random Variables
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 2 of 34 Chapter 11 – Section 1 ●Learning objectives Distinguish between discrete and continuous random variables Identify discrete probability distributions Construct probability histograms Compute and interpret the mean of a discrete random variable Interpret the mean of a discrete random variable as an expected value Compute the variance and standard deviation of a discrete random variable
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 3 of 34 Chapter 11 – Section 1 ●Learning objectives Distinguish between discrete and continuous random variables Identify discrete probability distributions Construct probability histograms Compute and interpret the mean of a discrete random variable Interpret the mean of a discrete random variable as an expected value Compute the variance and standard deviation of a discrete random variable
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 4 of 34 Chapter 11 – Section 1 ●A random variable is a numeric measure of the outcome of a probability experiment Random variables reflect measurements that can change as the experiment is repeated Random variables are denoted with capital letters, typically using X (and Y and Z …) Values are usually written with lower case letters, typically using x (and y and z...)
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 5 of 34 Chapter 11 – Section 1 ●Examples ●Tossing four coins and counting the number of heads The number could be 0, 1, 2, 3, or 4 The number could change when we toss another four coins ●Examples ●Tossing four coins and counting the number of heads The number could be 0, 1, 2, 3, or 4 The number could change when we toss another four coins ●Measuring the heights of students The heights could change from student to student
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 6 of 34 Chapter 11 – Section 1 ●A discrete random variable is a random variable that has either a finite or a countable number of values A finite number of values such as {0, 1, 2, 3, and 4} A countable number of values such as {1, 2, 3, …} ●A discrete random variable is a random variable that has either a finite or a countable number of values A finite number of values such as {0, 1, 2, 3, and 4} A countable number of values such as {1, 2, 3, …} ●Discrete random variables are designed to model discrete variables ●Discrete random variables are often “counts of …”
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 7 of 34 Chapter 11 – Section 1 ●An example of a discrete random variable ●The number of heads in tossing 3 coins (a finite number of possible values) ●An example of a discrete random variable ●The number of heads in tossing 3 coins (a finite number of possible values) There are four possible values – 0 heads, 1 head, 2 heads, and 3 heads ●An example of a discrete random variable ●The number of heads in tossing 3 coins (a finite number of possible values) There are four possible values – 0 heads, 1 head, 2 heads, and 3 heads A finite number of possible values – a discrete random variable ●An example of a discrete random variable ●The number of heads in tossing 3 coins (a finite number of possible values) There are four possible values – 0 heads, 1 head, 2 heads, and 3 heads A finite number of possible values – a discrete random variable This fits our general concept that discrete random variables are often “counts of …”
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 8 of 34 Chapter 11 – Section 1 ●Other examples of discrete random variables ●The possible rolls when rolling a pair of dice A finite number of possible pairs, ranging from (1,1) to (6,6) ●Other examples of discrete random variables ●The possible rolls when rolling a pair of dice A finite number of possible pairs, ranging from (1,1) to (6,6) ●The number of pages in statistics textbooks A countable number of possible values ●Other examples of discrete random variables ●The possible rolls when rolling a pair of dice A finite number of possible pairs, ranging from (1,1) to (6,6) ●The number of pages in statistics textbooks A countable number of possible values ●The number of visitors to the White House in a day A countable number of possible values
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 9 of 34 Chapter 11 – Section 1 ●A continuous random variable is a random variable that has an infinite, and more than countable, number of values The values are any number in an interval ●A continuous random variable is a random variable that has an infinite, and more than countable, number of values The values are any number in an interval ●Continuous random variables are designed to model continuous variables (see section 1.1) ●Continuous random variables are often “measurements of …”
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 10 of 34 Chapter 11 – Section 1 ●An example of a continuous random variable ●The possible temperature in Chicago at noon tomorrow, measured in degrees Fahrenheit ●An example of a continuous random variable ●The possible temperature in Chicago at noon tomorrow, measured in degrees Fahrenheit The possible values (assuming that we can measure temperature to great accuracy) are in an interval ●An example of a continuous random variable ●The possible temperature in Chicago at noon tomorrow, measured in degrees Fahrenheit The possible values (assuming that we can measure temperature to great accuracy) are in an interval The interval may be something like (–20,110) ●An example of a continuous random variable ●The possible temperature in Chicago at noon tomorrow, measured in degrees The possible values (assuming that we can measure temperature to great accuracy) are in an interval The interval may be something like (–20,110) This fits our general concept that continuous random variables are often “measurements of …”
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 11 of 34 Chapter 11 – Section 1 ●Other examples of continuous random variables ●The height of a college student A value in an interval between 3 and 8 feet ●Other examples of continuous random variables ●The height of a college student A value in an interval between 3 and 8 feet ●The length of a country and western song A value in an interval between 1 and 15 minutes ●Other examples of continuous random variables ●The height of a college student A value in an interval between 3 and 8 feet ●The length of a country and western song A value in an interval between 1 and 15 minutes
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 12 of 34 Chapter 11 – Section 1 ●Learning objectives Distinguish between discrete and continuous random variables Identify discrete probability distributions Construct probability histograms Compute and interpret the mean of a discrete random variable Interpret the mean of a discrete random variable as an expected value Compute the variance and standard deviation of a discrete random variable
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 13 of 34 Chapter 11 – Section 1 ●The probability distribution of a discrete random variable X relates the values of X with their corresponding probabilities ●A distribution could be In the form of a table In the form of a graph In the form of a mathematical formula
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 14 of 34 Chapter 11 – Section 1 ●If X is a discrete random variable and x is a possible value for X, then we write P(x) as the probability that X is equal to x ●Examples In tossing one coin, if X is the number of heads, then P(0) = 0.5 and P(1) = 0.5 In rolling one die, if X is the number rolled, then P(1) = 1/6
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 15 of 34 Chapter 11 – Section 1 ●Properties of P(x) ●Since P(x) form a probability distribution, they must satisfy the rules of probability 0 ≤ P(x) ≤ 1 Σ P(x) = 1 ●In the second rule, the Σ sign means to add up the P(x)’s for all the possible x’s
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 16 of 34 Chapter 11 – Section 1 ●An example of a discrete probability distribution ●All of the P(x) values are positive and they add up to 1 xP(x)P(x)
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 17 of 34 Chapter 11 – Section 1 ●An example that is not a probability distribution ●Two things are wrong xP(x)P(x) ●An example that is not a probability distribution ●Two things are wrong P(5) is negative xP(x)P(x) ●An example that is not a probability distribution ●Two things are wrong P(5) is negative The P(x)’s do not add up to 1 xP(x)P(x)
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 18 of 34 Chapter 11 – Section 1 ●Learning objectives Distinguish between discrete and continuous random variables Identify discrete probability distributions Construct probability histograms Compute and interpret the mean of a discrete random variable Interpret the mean of a discrete random variable as an expected value Compute the variance and standard deviation of a discrete random variable
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 19 of 34 Chapter 11 – Section 1 ●A probability histogram is a histogram where The horizontal axis corresponds to the possible values of X (i.e. the x’s) The vertical axis corresponds to the probabilities for those values (i.e. the P(x)’s) ●A probability histogram is very similar to a relative frequency histogram
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 20 of 34 Chapter 11 – Section 1 ●An example of a probability histogram ●The histogram is drawn so that the height of the bar is the probability of that value
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 21 of 34 Chapter 11 – Section 1 ●Learning objectives Distinguish between discrete and continuous random variables Identify discrete probability distributions Construct probability histograms Compute and interpret the mean of a discrete random variable Interpret the mean of a discrete random variable as an expected value Compute the variance and standard deviation of a discrete random variable
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 22 of 34 Chapter 11 – Section 1 ●The mean of a probability distribution can be thought of in this way: There are various possible values of a discrete random variable ●The mean of a probability distribution can be thought of in this way: There are various possible values of a discrete random variable The values that have the higher probabilities are the ones that occur more often ●The mean of a probability distribution can be thought of in this way: There are various possible values of a discrete random variable The values that have the higher probabilities are the ones that occur more often The values that occur more often should have a larger role in calculating the mean ●The mean of a probability distribution can be thought of in this way: There are various possible values of a discrete random variable The values that have the higher probabilities are the ones that occur more often The values that occur more often should have a larger role in calculating the mean The mean is the weighted average of the values, weighted by the probabilities
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 23 of 34 Chapter 11 – Section 1 ●The mean of a discrete random variable is μ X = Σ [ x P(x) ] ●The mean of a discrete random variable is μ X = Σ [ x P(x) ] ●In this formula x are the possible values of X P(x) is the probability that x occurs Σ means to add up these terms for all the possible values x
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 24 of 34 Chapter 11 – Section 1 ●Example of a calculation for the mean xP(x)P(x) ●Example of a calculation for the mean xP(x)P(x)x P(x) Multiply ●Example of a calculation for the mean xP(x)P(x)x P(x) Multiply Multiply again ●Example of a calculation for the mean ●Add: = 2.5 ●The mean of this discrete random variable is 2.5 Multiply again
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 25 of 34 Chapter 11 – Section 1 ●The calculation for this problem written out μ X = Σ [ x P(x) ] = [1 0.2] + [2 0.6] + [5 0.1] + [6 0.1] = = 2.5 ●The mean of this discrete random variable is 2.5
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 26 of 34 Chapter 11 – Section 1 ●The mean can also be thought of this way (as in the Law of Large Numbers) If we repeat the experiment many times ●The mean can also be thought of this way (as in the Law of Large Numbers) If we repeat the experiment many times If we record the result each time ●The mean can also be thought of this way (as in the Law of Large Numbers) If we repeat the experiment many times If we record the result each time If we calculate the mean of the results (this is just a mean of a group of numbers) ●The mean can also be thought of this way (as in the Law of Large Numbers) If we repeat the experiment many times If we record the result each time If we calculate the mean of the results (this is just a mean of a group of numbers) Then this mean of the results gets closer and closer to the mean of the random variable
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 27 of 34 Chapter 11 – Section 1 ●Learning objectives Distinguish between discrete and continuous random variables Identify discrete probability distributions Construct probability histograms Compute and interpret the mean of a discrete random variable Interpret the mean of a discrete random variable as an expected value Compute the variance and standard deviation of a discrete random variable
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 28 of 34 Chapter 11 – Section 1 ●The expected value of a random variable is another term for its mean ●The term “expected value” illustrates the long term nature of the experiments – as we perform more and more experiments, the mean of the results of those experiments gets closer to the “expected value” of the random variable
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 29 of 34 Chapter 11 – Section 1 ●Learning objectives Distinguish between discrete and continuous random variables Identify discrete probability distributions Construct probability histograms Compute and interpret the mean of a discrete random variable Interpret the mean of a discrete random variable as an expected value Compute the variance and standard deviation of a discrete random variable
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 30 of 34 Chapter 11 – Section 1 ●The variance of a discrete random variable is computed similarly as for the mean ●The mean is the weighted sum of the values μ X = Σ [ x P(x) ] ●The variance of a discrete random variable is computed similarly as for the mean ●The mean is the weighted sum of the values μ X = Σ [ x P(x) ] ●The variance is the weighted sum of the squared differences from the mean σ X 2 = Σ [ (x – μ X ) 2 P(x) ] ●The variance of a discrete random variable is computed similarly as for the mean ●The mean is the weighted sum of the values μ X = Σ [ x P(x) ] ●The variance is the weighted sum of the squared differences from the mean σ X 2 = Σ [ (x – μ X ) 2 P(x) ] ●The standard deviation, as we’ve seen before, is the square root of the variance … σ X = √ σ X 2
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 31 of 34 Chapter 11 – Section 1 ●The variance formula σ X 2 = Σ [ (x – μ X ) 2 P(x) ] can involve calculations with many decimals or fractions ●An equivalent formula is σ X 2 = [ Σ x 2 P(x) ] – μ X 2 ●This formula is often easier to compute
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 32 of 34 Chapter 11 – Section 1 ●For variables and samples, we had the concept of a population variance (for the entire population) and a sample variance (for a sample from that population) ●These probability distributions model the complete population These are population variance formulas There is no analogy for sample variance here
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 33 of 34 Chapter 11 Section 2 The Binomial Probability Distribution
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 34 of 34 Chapter 11 – Section 2 ●Learning objectives Determine whether a probability experiment is a binomial experiment Compute probabilities of binomial experiments Compute the mean and standard deviation of a binomial random variable Construct binomial probability histograms
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 35 of 34 Chapter 11 – Section 2 ●Learning objectives Determine whether a probability experiment is a binomial experiment Compute probabilities of binomial experiments Compute the mean and standard deviation of a binomial random variable Construct binomial probability histograms
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 36 of 34 Chapter 11 – Section 2 ●A binomial experiment has the following structure The first test is performed … the result is either a success or a failure ●A binomial experiment has the following structure The first test is performed … the result is either a success or a failure The second test is performed … the result is either a success or a failure. This result is independent of the first and the chance of success is the same ●A binomial experiment has the following structure The first test is performed … the result is either a success or a failure The second test is performed … the result is either a success or a failure. This result is independent of the first and the chance of success is the same A third test is performed … the result is either a success or a failure. The result is independent of the first two and the chance of success is the same
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 37 of 34 Chapter 11 – Section 2 ●Example A card is drawn from a deck. A “success” is for that card to be a heart … a “failure” is for any other suit ●Example A card is drawn from a deck. A “success” is for that card to be a heart … a “failure” is for any other suit The card is then put back into the deck ●Example A card is drawn from a deck. A “success” is for that card to be a heart … a “failure” is for any other suit The card is then put back into the deck A second card is drawn from the deck with the same definition of success. ●Example A card is drawn from a deck. A “success” is for that card to be a heart … a “failure” is for any other suit The card is then put back into the deck A second card is drawn from the deck with the same definition of success. The second card is put back into the deck ●Example A card is drawn from a deck. A “success” is for that card to be a heart … a “failure” is for any other suit The card is then put back into the deck A second card is drawn from the deck with the same definition of success. The second card is put back into the deck We continue for 10 cards
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 38 of 34 Chapter 11 – Section 2 ●A binomial experiment is an experiment with the following characteristics The experiment is performed a fixed number of times, each time called a trial ●A binomial experiment is an experiment with the following characteristics The experiment is performed a fixed number of times, each time called a trial The trials are independent ●A binomial experiment is an experiment with the following characteristics The experiment is performed a fixed number of times, each time called a trial The trials are independent Each trial has two possible outcomes, usually called a success and a failure ●A binomial experiment is an experiment with the following characteristics The experiment is performed a fixed number of times, each time called a trial The trials are independent Each trial has two possible outcomes, usually called a success and a failure The probability of success is the same for every trial
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 39 of 34 Chapter 11 – Section 2 ●Notation used for binomial distributions The number of trials is represented by n The probability of a success is represented by p The total number of successes in n trials is represented by X ●Because there cannot be a negative number of successes, and because there cannot be more than n successes (out of n attempts) 0 ≤ X ≤ n
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 40 of 34 Chapter 11 – Section 2 ●In our card drawing example Each trial is the experiment of drawing one card The experiment is performed 10 times, so n = 10 ●In our card drawing example Each trial is the experiment of drawing one card The experiment is performed 10 times, so n = 10 The trials are independent because the drawn card is put back into the deck ●In our card drawing example Each trial is the experiment of drawing one card The experiment is performed 10 times, so n = 10 The trials are independent because the drawn card is put back into the deck Each trial has two possible outcomes, a “success” of drawing a heart and a “failure” of drawing anything else The probability of success is 0.25, the same for every trial, so p = 0.25 ●In our card drawing example Each trial is the experiment of drawing one card The experiment is performed 10 times, so n = 10 The trials are independent because the drawn card is put back into the deck Each trial has two possible outcomes, a “success” of drawing a heart and a “failure” of drawing anything else The probability of success is 0.25, the same for every trial, so p = 0.25 X, the number of successes, is between 0 and 10
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 41 of 34 Chapter 11 – Section 2 ●The word “success” does not mean that this is a good outcome or that we want this to be the outcome ●A “success” in our card drawing experiment is to draw a heart ●If we are counting hearts, then this is the outcome that we are measuring ●There is no good or bad meaning to “success”
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 42 of 34 Chapter 11 – Section 2 ●Learning objectives Determine whether a probability experiment is a binomial experiment Compute probabilities of binomial experiments Compute the mean and standard deviation of a binomial random variable Construct binomial probability histograms
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 43 of 34 Chapter 11 – Section 2 ●We would like to calculate the probabilities of X, i.e. P(0), P(1), P(2), …, P(n) ●Do a simpler example first For n = 3 trials With p =.4 probability of success Calculate P(2), the probability of 2 successes
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 44 of 34 Chapter 11 – Section 2 ●For 3 trials, the possible ways of getting exactly 2 successes are S S F S F S F S S ●For 3 trials, the possible ways of getting exactly 2 successes are S S F S F S F S S ●The probabilities for each (using the multiplication rule) are = = = 0.096
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 45 of 34 Chapter 11 – Section 2 ●The total probability is P(2) = = ●But there is a pattern Each way had the same probability … the probability of 2 success (0.4 times 0.4) times the probability of 1 failure (0.6) ●The probability for each case is
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 46 of 34 Chapter 11 – Section 2 ●There are 3 cases S S F could represent choosing a combination of 2 out of 3 … choosing the first and the second S F S could represent choosing a second combination of 2 out of 3 … choosing the first and the third F S S could represent choosing a third combination of 2 out of 3 ●There are 3 cases S S F could represent choosing a combination of 2 out of 3 … choosing the first and the second S F S could represent choosing a second combination of 2 out of 3 … choosing the first and the third F S S could represent choosing a third combination of 2 out of 3 ●These are the 3 = 3 C 2 ways to choose 2 out of 3
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 47 of 34 Chapter 11 – Section 2 ●Thus the total probability P(2) = =.288 can also be written as P(2) = 3 C ●Thus the total probability P(2) = =.288 can also be written as P(2) = 3 C ●In other words, the probability is The number of ways of choosing 2 out of 3, times The probability of 2 successes, times The probability of 1 failure
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 48 of 34 Chapter 11 – Section 2 ●The general formula for the binomial probabilities is just this ●For P(x), the probability of x successes, the probability is The number of ways of choosing x out of n, times The probability of x successes, times The probability of n-x failures ●The general formula for the binomial probabilities is just this ●For P(x), the probability of x successes, the probability is The number of ways of choosing x out of n, times The probability of x successes, times The probability of n-x failures ●This formula is P(x) = n C x p x (1 – p) n-x
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 49 of 34 Chapter 11 – Section 2 ●Example ●A student guesses at random on a multiple choice quiz There are n = 10 questions in total There are 5 choices per question so that the probability of success p = 1/5 =.2 ●What is the probability that the student gets 6 questions correct?
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 50 of 34 Chapter 11 – Section 2 ●Example continued ●This is a binomial experiment There are a finite number n = 10 of trials Each trial has two outcomes (a correct guess and an incorrect guess) The probability of success is independent from trial to trial (every one is a random guess) The probability of success p =.2 is the same for each trial
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 51 of 34 Chapter 11 – Section 2 ●Example continued ●The probability of 6 correct guesses is P(x)= n C x p x (1 – p) n-x ●Example continued ●The probability of 6 correct guesses is P(x)= n C x p x (1 – p) n-x = 6 C = = ●Example continued ●The probability of 6 correct guesses is P(x)= n C x p x (1 – p) n-x = 6 C = = ●This is less than a 1% chance ●Example continued ●The probability of 6 correct guesses is P(x)= n C x p x (1 – p) n-x = 6 C = = ●This is less than a 1% chance ●In fact, the chance of getting 6 or more correct (i.e. a passing score) is also less than 1%
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 52 of 34 Chapter 11 – Section 2 ●Binomial calculations can be difficult because of the large numbers (the n C x ) times the small numbers (the p x and (1-p) n-x ) ●It is possible to use tables to look up these probabilities ●It is best to use a calculator routine or a software program to compute these probabilities
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 53 of 34 Chapter 11 – Section 2 ●Learning objectives Determine whether a probability experiment is a binomial experiment Compute probabilities of binomial experiments Compute the mean and standard deviation of a binomial random variable Construct binomial probability histograms
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 54 of 34 Chapter 11 – Section 2 ●We would like to find the mean of a binomial distribution ●Example There are 10 questions The probability of success is.20 on each one Then the expected number of successes would be = 2 ●The general formula μ X = n p
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 55 of 34 Chapter 11 – Section 2 ●We would like to find the standard deviation and variance of a binomial distribution ●This calculation is more difficult ●The standard deviation is σ X = √ n p (1 – p) and the variance is σ X 2 = n p (1 – p)
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 56 of 34 Chapter 11 – Section 2 ●For our random guessing on a quiz problem n = 10 p =.2 x = 6 ●For our random guessing on a quiz problem n = 10 p =.2 x = 6 ●Therefore The mean is np = 10.2 = 2 The variance is np(1-p) = =.16 The standard deviation is √.16 =.4 ●For our random guessing on a quiz problem n = 10 p =.2 x = 6 ●Therefore The mean is np = 10.2 = 2 The variance is np(1-p) = =.16 The standard deviation is √.16 =.4 ● Remember the empirical rule? A passing grade of 6 is 10 standard deviations from the mean …
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 57 of 34 Chapter 11 – Section 2 ●Learning objectives Determine whether a probability experiment is a binomial experiment Compute probabilities of binomial experiments Compute the mean and standard deviation of a binomial random variable Construct binomial probability histograms
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 58 of 34 Chapter 11 – Section 2 ●With the formula for the binomial probabilities P(x), we can construct histograms for the binomial distribution ●There are three different shapes for these histograms When p <.5, the histogram is skewed right When p =.5, the histogram is symmetric When p >.5, the histogram is skewed left
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 59 of 34 Chapter 11 – Section 2 ●For n = 10 and p =.2 (skewed right) Mean = 2 Standard deviation =.4
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 60 of 34 Chapter 11 – Section 2 ●For n = 10 and p =.5 (symmetric) Mean = 5 Standard deviation =.5
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 61 of 34 Chapter 11 – Section 2 ●For n = 10 and p =.8 (skewed left) Mean = 8 Standard deviation =.4
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 62 of 34 Chapter 11 – Section 2 ●Despite binomial distributions being skewed, the histograms appear more and more bell shaped as n gets larger ●This will be important!
Sullivan – Fundamentals of Statistics – 2 nd Edition – Chapter 11 Section 1 – Slide 63 of 34 Summary: Chapter 11 – Section 2 ●Binomial random variables model a series of independent trials, each of which can be a success or a failure, each of which has the same probability of success ●The binomial random variable has mean equal to np and variance equal to np(1-p)