A.A B.B C.C D.D Lesson 1 CYP1 A.–19 B.–11 C.–13 D.13 A. What is the value of (y – x) 3 – 12 if x = –3 and y = –4?

A.A B.B C.C D.D Lesson 1 CYP1 A.–110 B.–98 C.–54 D.–25 B. What is the value of x – y 2 (x + 5) if x = 2 and y = 4?

A.A B.B C.C D.D Lesson 1 CYP1 A.–23 B.–19 C.19 D.23 C.

Lesson 1 CYP2 1.A 2.B 3.C 4.D A.450 cm 3 B.75 cm 3 C.50 cm 3 D.10 cm 3

A.A B.B C.C D.D Lesson 2 CYP4 A.$2.86 B.$4.44 C.$4.48 D.$7.48 CHOCOLATE Joel went to the grocery store and bought 3 plain chocolate candy bars for $0.69 each and 3 chocolate-peanut butter candy bars for $0.79 each. How much did Joel spend altogether on candy bars?

A.A B.B C.C D.D Lesson 2 CYP5 A.14x + 10y B.14x + 2y C.14x + y D.11x + 2y Which expression is equivalent to 2(3x – y) + 4(2x + 3y)?

1.A 2.B 3.C 4.D Lesson 3 CYP1 A. Write an algebraic expression to represent the verbal expression 6 more than a number. A.6x B.x + 6 C.x 6 D.x – 6

1.A 2.B 3.C 4.D Lesson 3 CYP1 B. Write an algebraic expression to represent the verbal expression 2 less than the cube of a number. A.x 3 – 2 B.2x 3 C.x 2 – 2 D.2 + x 3

Lesson 3 CYP2 1.A 2.B 3.C 4.D A.The difference between a number and 3 is 7. B.The sum of a number and 3 is 7. C.The difference of 3 and a number is 7. D.The difference of a number and 7 is 3. A. What is a verbal sentence that represents the equation n – 3 = 7?

Lesson 3 CYP2 1.A 2.B 3.C 4.D A.Five is equal to the difference of 2 and a number. B.Five is equal to twice a number. C.Five is equal to the quotient of 2 and a number. D.Five is equal to the sum of 2 and a number. B. What is a verbal sentence that represents the equation 5 = 2 + x?

A.A B.B C.C D.D Lesson 3 CYP4 A.–8 B.–2 C.2 D.8 A. What is the solution to the equation x + 5 = 3?

A.A B.B C.C D.D Lesson 3 CYP4 A.5 B. C.15 D.30 B. What is the solution to the equation

A.A B.B C.C D.D Lesson 3 CYP5 What is the solution to 25 = 3(2x + 2) – 5(2x + 1)? A.–6 B. C. D.6

A.A B.B C.C D.D Lesson 3 CYP6 GEOMETRY The formula for the perimeter of a rectangle is where P is the perimeter, and w is the width of the rectangle. What is this formula solved for w? A. B. C. D.

A.A B.B C.C D.D Lesson 3 CYP7 A.12 B.6 C.–6 D.–12 If 2x + 6 = –3, what is the value of 2x –3?

A.A B.B C.C D.D Lesson 3 CYP8 A.100 ft 2 B.10 ft 2 C.8 ft 2 D.4.5 ft 2 HOME IMPROVEMENT Kelly wants to repair the siding on her house. Her contractor will charge her $300 plus $150 per square foot of siding. How much siding can she repair for $1500?

A.A B.B C.C D.D Lesson 4 CYP1 A.18.3 B.1.7 C.–1.7 D.–13.7

Lesson 4 CYP2 1.A 2.B 3.C 4.D A.  5  B.  –10, 5  C.  –5, 10  D.  –5  What is the solution to |2x + 5| = 15?

1.A 2.B 3.C 4.D Lesson 4 CYP3 A. B. C. D.

A.A B.B C.C D.D Lesson 4 CYP4 A. B. C. D.

A.A B.B C.C D.D Lesson 5 CYP1 Which graph represents the solution to 6x – 2 < 5x + 7? A. B. C. D.

Lesson 5 CYP2 1.A 2.B 3.C 4.D What is the solution to –3x  21? A.  x | x  –7  B.  x | x  –7  C.  x | x  7  D.  x | x  7 

1.A 2.B 3.C 4.D Lesson 5 CYP3 A. B. C. D.

A.A B.B C.C D.D Lesson 5 CYP4 A.up to 700 miles B.up to 800 miles C.more than 700 miles D.more than 800 miles RENTAL COSTS Jeb wants to rent a car for his vacation. Value Cars rents cars for $25 per day plus $0.25 per mile. How far can he drive for one day if he wants to spend no more that $200 on car rental?

A.A B.B C.C D.D Lesson 6 CYP1 What is the solution to 11  2x + 5 < 17? A. B. C. D.

Lesson 6 CYP2 1.A 2.B 3.C 4.D What is the solution to x + 5 < 1 or –2x  –6? Graph the solution set on a number line. A. B. C. D.

1.A 2.B 3.C 4.D Lesson 6 CYP3 What is the solution to |x| < 5? A.{x|x > 5 or x < –5} B.{x|–5 < x < 5} C.{x|x < 5} D.{x|x > –5}

A.A B.B C.C D.D Lesson 6 CYP4 What is the solution to |x| > 5? A. B. C. D.

A.A B.B C.C D.D Lesson 6 CYP5 What is the solution to |3x – 3| > 9? Graph the solution set on a number line. A. B. C. D.

Lesson 3-1 CYP 1 A. A B. B C. C D. D What is the solution of the system of equations? x + y = 2 x – 3y = –6 A.(1, 1) B.(0, 2) C.(2, 0) D.(–4, 6)

A.A B.B C.C D.D Which graph shows the solution to the system of equations below? x + 3y=7 x – y=3 A.C. B.D. Lesson 3-1 CYP 2

Lesson 3-1 CYP 4 A. A B. B C. C D. D Graph the system of equations below. What type of system of equations is shown? x + y = 5 2x = y – 11 A.consistent and independent B.consistent and dependent C.consistent D.none of the above

Lesson 3-1 CYP 5 A. A B. B C. C D. D Graph the system of equations below. What type of system of equations is shown? x + y = 3 2x = –2y + 6 A.consistent and independent B.consistent and dependent C.inconsistent D.none of the above

Lesson 3-1 CYP 6 A. A B. B C. C D. D Graph the system of equations below. What type of system of equations is shown? y = 3x + 2 –6x + 2y = 10 A.consistent and independent B.consistent and dependent C.inconsistent D.none of the above

Lesson 3-2 CYP 1 A. A B. B C. C D. D Solve the system of equations using substitution. What is the solution to the system of equations? x – 3y = 2 x + 7y = 12 A.(1, 5) B. C.(8, 2) D.(5, 1)

Lesson 3-2 CYP 2 A. A B. B C. C D. D A.210 adult; 120 children B.120 adult; 210 children C.300 children; 30 adult D.300 children; 30 adult AMUSEMENT PARKS At Amy’s Amusement Park, tickets sell for $24.50 for adults and $16.50 for children. On Sunday, the amusement park made $6405 from selling 330 tickets. How many of each kind of ticket was sold?

Lesson 3-2 CYP 3 A. A B. B C. C D. D A.(2, –1) B.(17, –4) C.(2, 1) D.no solution Use the elimination method to solve the system of equations. What is the solution to the system? x + 3y = 5 x + 5y = –3

Lesson 3-2 CYP 4 A. A B. B C. C D. D Use the elimination method to solve the system of equations. What is the solution to the system of equations? x + 3y = 7 2x + 5y = 10 A. B.(1, 2) C.(–5, 4) D.no solution

Lesson 3-2 CYP 5 A. A B. B C. C D. D A.(1, 3) B.(–5, 0) C.(2, –2) D.no solution Use the elimination method to solve the system of equations. What is the solution to the system of equations? 2x + 3y = 11 –4x – 6y = 20

Lesson 3-5 CYP 1 A. A B. B C. C D. D What is the solution to the system of equations shown below? 2x + 3y – 3z = 16 x + y + z = –3 x – 2y – z = –1 A. B.(–3, –2, 2) C.(1, 2, –6) D.(–1, 2, –4)

1.A 2.B 3.C 4.D Lesson 1 CYP1 Which graph is the graph of f(x) = 2x 2 + 3x + 2? A.B. C.D.

Lesson 1 CYP2 1.A 2.B 3.C 4.D A.y-intercept = 3, axis of symmetry : x = –3, x-coordinate = –3 B.y-intercept = –3, axis of symmetry : x = 3, x-coordinate = 3 C.y-intercept = 3, axis of symmetry : x = 3, x-coordinate = 3 D.y-intercept = –3, axis of symmetry : x = –3, x-coordinate = –3 A. Consider the quadratic function f(x) = 3 – 6x + x 2. Find the y-intercept, the equation of the axis of symmetry and the x-coordinate of the vertex.

1.A 2.B 3.C 4.D Lesson 1 CYP3 A.maximum B.minimum C.both D.none A. Consider the function f(x) = x 2 + 4x – 1. Determine whether the function has a maximum or a minimum value.

1.A 2.B 3.C 4.D Lesson 1 CYP3 A.–5 B.–1 C.5 D.none B. Consider the function f(x) = x 2 + 4x – 1. What is the maximum or minimum value of the function?

1.A 2.B 3.C 4.D Lesson 1 CYP3 A.domain: all real numbers; range: y ≥ –5 B.domain: all real numbers; range: y ≤ –5 C.domain: x ≥ –5; range: all real numbers D.domain: x ≤ –5; range: all real numbers C. Consider the function f(x) = x 2 + 4x – 1. What are the domain and range of the function?

A.A B.B C.C D.D Lesson 2 CYP1 Which answer choice shows the graph and the solution to x 2 + 2x – 3 = 0? A.B. C.D.

Lesson 2 CYP2 1.A 2.B 3.C 4.D Solve x 2 – 6x = –9 by graphing. A.B. C.D.

1.A 2.B 3.C 4.D Lesson 2 CYP3 A.7, 2 B.–7, –2 C.5, 2 D.no such numbers exist NUMBER THEORY What are two real numbers whose sum is 7 and whose product is 14?

A.A B.B C.C D.D Lesson 2 CYP4 A.0 and 1, 3 and 4 B.0 and 1 C.3 and 4 D.–1 and 0, 2 and 3 Solve x 2 – 4x + 2 = 0 by graphing. What are the consecutive integers between which the roots are located?

A.A B.B C.C D.D Lesson 3 CYP1 A. B. C. D.

1.A 2.B 3.C 4.D Lesson 3 CYP2 A. Factor the polynomial 2x 2 – 9x – 5. A.(2x – 1)(x – 5) B.(2x + 1)(x – 5) C.(2x + 1)(x + 5) D.(2x – 1)(x + 5)

1.A 2.B 3.C 4.D Lesson 3 CYP2 B. Factor the polynomial a 3 b A.(ab + 4)(a 2 b 2 – 4ab + 16) B.(ab – 4)(a 2 b 2 + 4ab + 16) C.(a 2 b 2 + 4)(a 2 b 2 – 4ab + 16) D.(a 2 b 2 – 4)(a 2 b 2 + 4ab + 16)

A.A B.B C.C D.D Lesson 3 CYP3 A.{0} B.{3} C.{0, 3} D.{1, 3} A. Solve x 2 = 3x by factoring.

A.A B.B C.C D.D Lesson 3 CYP3 B. Solve 6x x = –4 by factoring. A. B. C. D.

1.A 2.B 3.C 4.D Lesson 3 CYP4 A.{–5, 5} B.{–10} C.{5} D.{–5} Solve x x = –25 by factoring.