November 2010 Paper 3
1)a) Milk : Dark 2 : 1 24 : 12 There are 36 chocolates in total
2) a)p x p x p x p = p 4 b) 2c x 3d = 6cd
3)a) b) (2, 9) (4, 7) (6, 5) (8, 3) c) P(less than 6) = 3 /
4)a) n – 2 b) 10 – n 2 i) 3 rd term = 10 – 3 2 = 1 ii) 5 th term = 10 – 5 2 = -15
5) Area of circle = π x radius 2 Area = π x 10 2 = 314cm 2
6) x (1 mark for any 200 x 5 one of these) (1 mark for any answer between 3 and 4)
7)175 x 37 = 6475 £64.75
8)Line drawn through (−2, 6) (−1, 5) (0, 4) (1, 3) (2, 2) (3, 1) (4, 0), (5, − 1)
9) Equilateral triangle so all angles are 60° x = 120° Angles on a straight line add up to 180 °
10)a) Key9|1 = 91 b)Mode =
11)17.5% of 6000 = 1050(1 mark) (1 mark) = 7050(1 mark) 7050 – 3000(1 mark) 4050 ÷ 10(1 mark) = 405(1 mark)
12) a)Rotation(1 mark) 180°(1 mark) Centre (0,0)(1 mark)
12)b)
13)t =v t – 2 =v 5 (t – 2) x 5 = v 5(t – 2) = v
14)Midpoint of PQ is (7, 5)
15) B and E
16) a) 3(x + 5) + 2(5x – 6) = 3x x – 12 = 13x + 3 b)2x + 4 = x c) 5x + 10 = 5(x + 2) d) x 2 y + xy 2 = xy(x + y)
17) AB
18)a) 2 17 / 20 – 1 2 / 5 17 _ 2or _ Answer = 1 9 / 20 or 29 / _ _
18)b) 2 2 / 3 x 1 3 / 4 8 x (or equivalent...e.g. 14 / 3 or 4 2 / 3
19)a) 10cm 5cm 8cm A E DC B 10cm 8cm 15cm x 1.5 or ÷ 2 then x 3 DC = 12cm
19)b) 10cm 5cm 8cm A E DC B Area of trapezium = ½ (a + b) x height Parallel sides 5cm 8cm 12cm Area of trapezium = ½ (8 + 12) x 5 = 50cm 2
20) a)13.2 b)13.8 – 12.6 = 1.2 c)IQR ignores extreme values/outliers
21) 6x + 2y = − 3(1) 4x − 3y = 11 (2) Make the ys the same (1)x 318x + 6y = -9 (2)x 2 8x – 6y = 22(1 mark) Signs Same Subtract 26x = 13(1 mark) x = ½(1 mark) Now find y 6x + 2y = y = -3 2y = -6 y = -3(1 mark)
22) a) A tangent is at right angles to a radius
22) b) OB 2 = OA 2 + AB 2 OB 2 = OB 2 = 100 OB = 10 BC = OB – 6 = 4cm
23) (x − 3)(x + 5) x 2 – 3x + 5x – 15 x 2 + 2x – 15 b)x 2 + 8x − 9 = 0 (x + 9)(x – 1) = 0 either x + 9 = 0orx – 1 = 0 x = -9 x = 1
24)a)
24)b) = 25
25) 180 x 50=9 1000
26) P is inversely proportional to V. When V = 8, P = 5 a)P = k V 5 =k 8 k = 40 P = 40 V
26)b) P = 40 V P = 40 2 P = 20
27)a) OP = a + b OM = ½a + ½b
27)b) TM = -a + ½a + ½b TM = -½a + ½b
28) (-1.6,2.6) (2.6,-1.6)