The Lorentz Transformation Section 4. An event has coordinates x,y,z,t in the K system x’,y’,z’,t’ in the K’ system What is the formula that transforms.

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Presentation transcript:

The Lorentz Transformation Section 4

An event has coordinates x,y,z,t in the K system x’,y’,z’,t’ in the K’ system What is the formula that transforms from one set to the other?

Transformation must leave interval s unchanged. s = interval between world points (events) in 4 space. Such transformation is a rotation in 4-D x,y,z,ct coordinate system. Every rotation can be resolved into six rotations in planes xy, yz, zx, tx, ty, tz.

Consider tx plane y,z, coordinates don’t change. Transform must leave (ct) 2 – x 2 unchanged That is the square of interval from origin in tx plane to point (ct,x) x ct

Formula for rotation or

 = “angle” of rotation (or boost parameter, or rapidity) This transformation conserves the interval Hyperbolic functions appear instead of trig functions because 4-space is pseudo-Euclidean

If two frames move relative to each other along their mutual x axes… …then only x and t are subject to transformation.

We already have the transformation formula, but we don’t know  in terms of V. The motion of the origin of K’ (x’ = 0) with respect to the lab frame K is given by Since x/t = V, tanh  = V/c.

Lorentz transformation Inverse formulae: V-> -V swap primes

Limit c  gives Galileo transform with absolute time.

For V > c, coordinates and time are imaginary. Denominators go to zero if V = c.

Small velocities, V<<c Gallilean transform for x But non-absolute time

Suppose a rod is at rest and parallel to X-axis in frame K. The length in K is  x = (x 2 – x 1 ) = proper length of rod. x 2 x 1 Coordinates of the ends of the rod. What is the length of the same rod in K’? First find the coordinates x1’ and x2’ at the same instant t’.

Let proper length  x = l 0. (Proper length is always measured in the rest frame of the object.) LORENTZ CONTRACTION.

Lorentz Contraction If rod is moving, it will appear shorter to an observer at rest.

Since  y and  z don’t change, volume transforms according to Proper volume

On a clock at rest in K’, two events at the same location x’, y’, z’ are separated by a time interval  t’ = t 2 ’ – t 1 ’ What is the time interval between the same two events in the K system? Proper time interval for the events Time dilation

The Gallilean transform is commutative. The combined result of two successive tranforms V 1 and V 2 does not depend on the order. Lorentz transforms do not commute, unless V 1 || V 2. Rotations about different axes depend on the order, unless they are about the same axis.

What do we do if V is not in the X direction?