Splash Screen. Lesson Menu Five-Minute Check (over Lesson 3–2) Then/Now New Vocabulary Key Concept:Slope of a Line Example 1:Find the Slope of a Line.

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Presentation transcript:

Splash Screen

Lesson Menu Five-Minute Check (over Lesson 3–2) Then/Now New Vocabulary Key Concept:Slope of a Line Example 1:Find the Slope of a Line Concept Summary: Classifying Slopes Example 2:Real-World Example: Use Slope as Rate of Change Postulates:Parallel and Perpendicular Lines Example 3:Determine Line Relationships Example 4: Use Slope to Graph a Line

Over Lesson 3–2 A.A B.B C.C D.D 5-Minute Check 1 A.24 B.34 C.146 D.156 In the figure, m  4 = 146. Find the measure of  2.

Over Lesson 3–2 A.A B.B C.C D.D 5-Minute Check 2 A.24 B.34 C.146 D.156 In the figure, m  4 = 146. Find the measure of  7.

Over Lesson 3–2 A.A B.B C.C D.D 5-Minute Check 3 A.160 B.146 C.56 D.34 In the figure, m  4 = 146. Find the measure of  10.

Over Lesson 3–2 A.A B.B C.C D.D 5-Minute Check 4 A.180 B.160 C.52 D.34 In the figure, m  4 = 146. Find the measure of  11.

Over Lesson 3–2 A.A B.B C.C D.D 5-Minute Check 5 A.180 B.146 C.68 D.34 In the figure, m  4 = 146. Find m  11 + m  6.

Over Lesson 3–2 A.A B.B C.C D.D 5-Minute Check 6 A.76 B.75 C.53 D.52 In the map shown, 5 th Street and 7 th Street are parallel. At what acute angle do Strait Street and Oak Avenue meet?

Then/Now You used the properties of parallel lines to determine congruent angles. (Lesson 3–2) Find slopes of lines. Use slope to identify parallel and perpendicular lines.

Vocabulary slope rate of change

Concept

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Example 1 Find the Slope of a Line A. Find the slope of the line. Substitute (–3, 7) for (x 1, y 1 ) and (–1, –1) for (x 2, y 2 ). Answer:–4 Slope formula Substitution Simplify.

Example 1 Find the Slope of a Line B. Find the slope of the line. Substitute (0, 4) for (x 1, y 1 ) and (0, –3) for (x 2, y 2 ). Answer:The slope is undefined. Slope formula Substitution Simplify.

Example 1 Find the Slope of a Line C. Find the slope of the line. Answer: Slope formula Substitution Simplify. Substitute (–2, –5) for (x 1, y 1 ) and (6, 2) for (x 2, y 2 ).

Example 1 Find the Slope of a Line D. Find the slope of the line. Answer:0 Slope formula Substitution Simplify. Substitute (–2, –1) for (x 1, y 1 ) and (6, –1) for (x 2, y 2 ).

A. B. C. D. A.A B.B C.C D.D Example 1a A. Find the slope of the line.

A.0 B.undefined C.7 D. A.A B.B C.C D.D Example 1b B. Find the slope of the line.

A. B. C.–2 D.2 A.A B.B C.C D.D Example 1c C. Find the slope of the line.

A.0 B.undefined C.3 D. A.A B.B C.C D.D Example 1d D. Find the slope of the line.

Concept

Example 2 Use Slope as Rate of Change RECREATION In 2000, the annual sales for one manufacturer of camping equipment was $48.9 million. In 2005, the annual sales were $85.9 million. If sales increase at the same rate, what will be the total sales in 2015? Understand Use the data given to graph the line that models the annual sales y as a function of the years x since The sales increase is constant. Plot the points (0, 48.9) and (5, 85.9) and draw a line through them. You want to find the sales in 2015.

Example 2 Use Slope as Rate of Change Plan Find the slope of the line. Use this rate of change to find the amount of sales in Solve Use the slope formula to find the slope of the line. The sales increased at an average of $7.4 million per year.

Example 2 Use Slope as Rate of Change Use the slope of the line and one known point on the line to calculate the sales y when the years x since 2000 is 15. Slope formula m = 7.4, x 1 = 0, y 1 = 48.9, x 2 = 15 Simplify. Multiply each side by 15. Add 48.9 to each side.

Example 2 Use Slope as Rate of Change Answer:Thus, the sales in 2015 will be about $159.9 million. CheckFrom the graph we can estimate that in 2015, the sales will be a little more than $150 million. Since is close to 150, our answer is reasonable.

Concept

Example 3 Determine Line Relationships Step 1Find the slopes of and. Determine whether and are parallel, perpendicular, or neither for F(1, –3), G(–2, –1), H(5, 0), and J(6, 3). Graph each line to verify your answer.

Example 3 Determine Line Relationships Step 2Determine the relationship, if any, between the lines. The slopes are not the same, so and are not parallel. The product of the slopes is So, and are not perpendicular. Answer:The lines are neither parallel nor perpendicular. Check When graphed, you can see that the lines are not parallel and do not intersect in right angles.

A.A B.B C.C Example 3 A.parallel B.perpendicular C.neither Determine whether AB and CD are parallel, perpendicular, or neither for A(–2, –1), B(4, 5), C(6, 1), and D(9, –2)

Example 4 Use Slope to Graph a Line First find the slope of. Slope formula Substitution Simplify. Graph the line that contains Q(5, 1) and is parallel to MN with M(–2, 4) and N(2, 1).

Example 4 Use Slope to Graph a Line The slope of the line parallel to through Q(5, 1) is. The slopes of two parallel lines are the same. Graph the line. Draw. Start at (5, 1). Move up 3 units and then move left 4 units. Label the point R. Answer:

A.A B.B C.C D.D Example 4 Graph the line that contains R(2, –1) and is parallel to OP with O(1, 6) and P(–3, 1). A.B. C.D.none of these

Homework p. 192 – even

End of the Lesson