Solving Linear Systems by Elimination Math Tech II Everette Keller.

Slides:



Advertisements
Similar presentations
8.3 Solving Systems of Linear Equations by Elimination
Advertisements

Solve each with substitution. 2x+y = 6 y = -3x+5 3x+4y=4 y=-3x- 3
Solving a System of Equations by ELIMINATION. Elimination Solving systems by Elimination: 1.Line up like terms in standard form x + y = # (you may have.
Drill Solve the linear system by substitution. 1.y = 6x – 11 -2x – 3y = x + y = 6 -5x – y = 21.
Do Now Pass out calculators. Solve the following system by graphing: Graph paper is in the back. 5x + 2y = 9 x + y = -3 Solve the following system by using.
Algebra II w/ trig. Substitution Method: 1. Solve an equation for x or y 2. Substitute your result from step 1 into the other equation and solve for the.
Solving Systems of Equations: Elimination Method.
Solving Systems of Linear Equations
Solving Linear Systems by Linear Combinations
Solving Linear Systems using Linear Combinations (Addition Method) Goal: To solve a system of linear equations using linear combinations.
Solving Systems of Equations
Do Now 1/13/12  In your notebook, list the possible ways to solve a linear system. Then solve the following systems. 5x + 6y = 50 -x + 6y = 26 -8y + 6x.
Integrated Math 2 Lesson #7 Systems of Equations - Elimination Mrs. Goodman.
Goal: Solve systems of linear equations using elimination. Eligible Content: A / A
Goal: Solve a system of linear equations in two variables by the linear combination method.
Lesson 4-2: Solving Systems – Substitution & Linear Combinations
Solving a System of Equations in Two Variables By Elimination Chapter 8.3.
Bell Ringer 2x – 3y = 4 5x + 3y = 10. HW Check Check elimination part 1 practice.
Graphing Linear Systems Math Tech II Everette Keller.
What is a System of Linear Equations? A system of linear equations is simply two or more linear equations using the same variables. We will only be dealing.
Solving by Elimination Example 1: STEP 2: Look for opposite terms. STEP 1: Write both equations in Standard Form to line up like variables. STEP 5: Solve.
3-2 Solving Linear Systems Algebraically Objective: CA 2.0: Students solve system of linear equations in two variables algebraically.
Elimination Method: Solve the linear system. -8x + 3y=12 8x - 9y=12.
7.4. 5x + 2y = 16 5x + 2y = 16 3x – 4y = 20 3x – 4y = 20 In this linear system neither variable can be eliminated by adding the equations. In this linear.
Do Now (3x + y) – (2x + y) 4(2x + 3y) – (8x – y)
Lesson 7.4A Solving Linear Systems Using Elimination.
6.2 Solve a System by Using Linear Combinations
Bell Ringer: Combine like terms 1)4x + (-7x) = 2)-6y + 6y = 3)-5 – (-5) = 4)8 – (-8) =
SOLVING SYSTEMS USING ELIMINATION 6-3. Solve the linear system using elimination. 5x – 6y = -32 3x + 6y = 48 (2, 7)
Multiply one equation, then add
Slide Copyright © 2009 Pearson Education, Inc. 7.2 Solving Systems of Equations by the Substitution and Addition Methods.
Solving Systems by Elimination 5.4 NOTES, DATE ____________.
Lesson 4-2: Solving Systems – Substitution & Linear Combinations Objectives: Students will: Solve systems of equations using substitution and linear combinations.
Elimination using Multiplication Honors Math – Grade 8.
3.3 Solving Linear Systems by Linear Combination 10/12/12.
3.2 Solve Linear Systems Algebraically Algebra II.
Chapter 5: Systems of Linear Equations Section 5.1: Solving Systems of Linear Equations by Elimination.
WARM-UP. SYSTEMS OF EQUATIONS: ELIMINATION 1)Rewrite each equation in standard form, eliminating fraction coefficients. 2)If necessary, multiply one.
Elimination Method - Systems. Elimination Method  With the elimination method, you create like terms that add to zero.
Solving a System of Equations by ELIMINATION. Elimination Solving systems by Elimination: 1.Line up like terms in standard form x + y = # (you may have.
Warm Up Find the solution to linear system using the substitution method. 1) 2x = 82) x = 3y - 11 x + y = 2 2x – 5y = 33 x + y = 2 2x – 5y = 33.
Solve Linear Systems By Multiplying First
6) x + 2y = 2 x – 4y = 14.
5.3 Solving Systems of Linear Equations by Elimination
Solving Systems of Linear Equations in 3 Variables.
Solving Linear Systems by Linear Combinations
3-2: Solving Linear Systems
Solving Systems Using Elimination
5.3 Solving Systems of Linear Equations by Elimination
REVIEW: Solving Linear Systems by Elimination
Solve Systems of Equations by Elimination
Coordinate Algebra Day 26
Solve Linear Equations by Elimination
Solving Linear Equations
Notes Solving a System by Elimination
Notes Solving a System by Elimination
SOLVING SYSTEMS USING ELIMINATION
3-2: Solving Linear Systems
Solving Linear Systems by Linear Combinations (Elimination)
Solving a System of Equations in Two Variables by the Addition Method
Solving Systems of Equations by the Substitution and Addition Methods
Solving Systems of Linear Equations in 3 Variables.
Section Solving Linear Systems Algebraically
Solve the linear system.
3-2: Solving Linear Systems
Example 2B: Solving Linear Systems by Elimination
3-2: Solving Linear Systems
The Substitution Method
Solving Linear Equations
Solving Systems of Linear Equations by Elimination
Presentation transcript:

Solving Linear Systems by Elimination Math Tech II Everette Keller

Two of more linear equations in the same variable form a system of linear equations, or simply a linear system.

y = 3x y = x + 4

To eliminate: To get rid of; remove. To remove (an unknown quantity) by combining equations.

The elimination method can be obtained by (1) multiplying one or both equations by a constant if necessary and (2) adding the resulting equations to eliminate one of the variables

Solve by elimination: Just add the equations 4x + 3y = 16 2x – 3y = 8

Solve by elimination: Multiply First, Then Add 2x + 3y = 3 4x – 6y = 4

Step 1 – Arrange the equations with like terms in columns Step 2 – Multiply, if necessary, the equations by numbers to obtain coefficients that are opposites for one of the variables Step 3 – Add the equations from Step 2. Combining like terms with opposite coefficients will eliminate one variable. Solve for the remaining variable. Step 4 – Substitute the value obtained in Step 3 into either of the original equations and solve for the other variable Step 5 – Check the solution in each of the original equations

Find the solution to the linear system by elimination 5x + 2y = -4 -5x + 3y = 19

Find the solution to the linear system by elimination 3x + 5y = 6 -4x + 2y = 5

1.What does elimination mean in the definitive sense? 2.What does elimination mean for us when working with linear systems? 3.What does the solution that we find through elimination mean? 4.When is it easier to solve by elimination? 5.When is it difficult to solve by this method?

What are the benefits and limitations of solving linear systems through elimination?

Find a real life problem that relates to solving linear systems by elimination and state it for the next class period Problems 1 – 10 on the Handout