Understanding the rules for indices Applying the rules of indices

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Presentation transcript:

Understanding the rules for indices Applying the rules of indices

subtract am × an = am + n negative Starter Copy and complete the following filling in the missing words by using the words in the box below: To multiply numbers with indices we ______ the powers. As a formula this can be written as ______. To divide numbers with indices we ______ the powers. As a formula this can be written as ______. It is not possible to simplify powers if they have different ______. I need to be especially careful when there are ______ numbers involved. bases add am ÷ an = am - n subtract am × an = am + n negative

Use your knowledge of laws of indices to simply the following Quick Recap! Use your knowledge of laws of indices to simply the following x6 × x4 x3 × x-2 3x × 2x2 5y-2 × 4y-2 y8 ÷ y4 y-4 ÷ y5 4y6 ÷ 2y3 9x-3 ÷ 3y-2 8y6 ÷ 8y6

What happens when you get x0? Special Rule What happens when you get x0? x0 = 1 Anything to the power of 0… 80 = 1 = 1 30 = 1 (monkey)0 = 1 (xy)0 = 1 20000 = 1

Brackets - A power to a power When we have a question involving brackets, we MULTIPLY the indices. Can you work out why using this example: (x4)2 = x8 What should we do if we have (2b3)3? How could you write this rule using algebra?

Brackets – A power to a power For a question involving brackets multiply the indices Try these questions: (f 6)2 (h3)4 (e5)2 (k3)-4 (y2)-4 (x-3)-5 (d-4)-6 [(y3)-2]5 Now try these harder questions: (2t2)3 (3y2)2 (6m7)2 (2z-3)4 (3t4)3 (3x2y4)3 (4c-2d6)3 (5e4f6g-4)3

How much have you learnt? Can you cope answering mixed questions? y6 × 2y 3x2 × 4y4 y ÷ 3y2 2x2y-4 × 5xy6 (3x3y)2 25x-2y3 ÷ 5x4y-2 40 20x4 ÷ 20y4 Don’t forget the monkey!!!

Spot the odd one out timed quiz (part 2) Plenary Spot the odd one out timed quiz (part 2) Just because you were so bad at it last time……