Electrochem Homework 3, 15, 17, 23, 27, 29, 35, 37, 41, 44, 49, 51, 53, 59, 63, 89, 91, 97a, 99, 117
Oxidation Numbers # of e- gained or lost when forming a compound If ion, actual charge Use the Periodic Table!
General Rules Free uncombined state of atoms -> 0Ex. Na, K, S 8, Cl 2 Sum of oxidation #’s in neutral compound is zero Polyatomic ions, oxidation #’s add up to the charge on the ion F has a -1 ox. state
General Rules Continued H usually has an ox. state of +1 Exception: NaH where H is -1 O usually has an ox. State of -2 Exceptions: O -1 and O -1/2 Use the Periodic Table to find the location of the element
Examples HNO 3 NO 3 -1
New Method # of valence electrons - # of unshared electrons Midway number - # of bonding electrons assigned to it * oxidation number * Higher electronegative atom gets the e-
Examples NH 3 CH 3 OH
Why do we need a new method? SO 4 -2 vs. S 2 O 3 -2
Electrochemistry Study of the relationship between chemical change and electrical work Application of thermodynamics in everyday applications Ex. Radios, iPods, calculators Battery houses a spontaneous chemical reaction that releases free energy to produce electricity
Electrochemistry cont. 2 nd type of reaction: Nonspontaneous and absorbs free energy from an external source of electricity Ex. Electroplating, recovery of metals from ores
Electrochemistry cont. Amount of energy (electrical) consumed or produced in chemical reactions can be accurately measured All electrochemical reactions involve the transfer of electrons Redox reactions! The electrochemical cell contains the reacting system
Electrochemistry cont. Sites of oxidation and reduction separated physically so that reduction occurs at one electrode and oxidation occurs at the other electrode Red Cat and An Ox
Examples of Redox reactions 4 Al(s) + 3 O 2 (g) ---> 2 Al 2 O 3 (s)
Balancing redox reactions 1.Write the unbalanced equation 2.Assign oxidation numbers 3.Choose coefficients that make the transfer of electrons the same 4.Balance the charge 5.Balance remaining elements if necessary
Balancing In Acidic Media Add H + and H 2 O to balance charge Ex. Cr 2 O I - Cr +3 + IO 3 -
Balancing In Basic Media Balance charge by adding OH - and H 2 O Ex. Cr 2 O I - Cr +3 + IO 3 -
Balance in Acid MnO Br - MnO 2 + BrO 2 -1
Balance in Base (Drano) Al + H 2 O [Al(OH) 4 ] - + H 2
Balance in Acid Cu + NO 3 - Cu +2 + NO
Half Rxn Method for balancing redox equations Overall reaction split into two half reactions Separates oxidation and reduction half reactions Easy to balance redox reactions occurring in acidic or basic solutions
How? 1. Divide equation into two half reactions 2. Balance the atoms and charges in each half reaction - e- added to left is reduction - e- added to right is oxidation 3. Multiply by integer so e- lost = e- gained 4. Add balanced equations
Ex. Balance in acidic media Ex. Cr 2 O I - Cr +3 + I 2
Ex. Balance in basic media MnO C 2 O 4 -2 MnO 2 + CO 3 -2
Breathalyzer reaction Cr 2 O C 2 H 5 OH + H + Cr +3 + C 2 H 4 O + H 2 O
Equivalents Acids and Bases Just deal with the number of H + or OH - being donated Ex. HCl -> 1 equivalent H 3 PO 4 -> 3 equivalents NaOH -> 1 equivalent Ca(OH) 2 -> 2 equivalents
Acid Reaction H 2 SO 4 + H 2 O 2 H + + SO mol 2 mol 1 mol 98.0 g/mol 2.0 g/mol 96.0 g/mol 2 equivalents 1 equivalent HNO 3 – g 1 equiv. CH 3 COOH – g 1 equiv. H 2 SO g 1 equivalent of Ca(OH) g
Normality Molarity = moles of solute Liters of solution Normality = equivalents of solute Liters of solution N = M x #equivalents
Equivalents and Redox Not only do equivalents pertain to # H + or # OH - but also to electrons Equivalent – mass of oxidizing or reducing substance that gains or loses 1 mole of electrons 1 mole of electrons equals 1 equivalent of electrons
Equivalents One equiv. oxidized reacts with one equiv. reduced 1 eq. ox. = 1 eq. red. If redox equation is balanced – mole ratios can be used in stoichiometry If NOT balanced – equivalents can be used
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