Objective - To solve equations with the variable in both sides.

Slides:

Advertisements

Similar presentations

Bkevil Solve Equations With Variables on Both Sides.

Advertisements

2.4 Solving Equations with Variables on Both Sides

Algebra 1 Chapter 3 Section 7.

Step 1: Simplify Both Sides, if possible Distribute Combine like terms Step 2: Move the variable to one side Add or Subtract Like Term Step 3: Solve for.

Warm Up Simplify. 1. 4x – 10x 2. –7(x – 3) 3. –6x – (x – 2)

1. solve equations with variables on both sides. 2. solve equations containing grouping symbols. 3.5 Objectives The student will be able to:

SOLVE EQUATIONS WITH VARIABLES ON BOTH RED CARD- NO SOLUTION YELLOW CARD- 1 SOLUTION GREEN CARD-INFINITE SOLUTIONS bkevil.

1.4 Solving Equations ●A variable is a letter which represents an unknown number. Any letter can be used as a variable. ●An algebraic expression contains.

Objective - To solve equations with the variable in both sides. Solve. 2x + 4 = 5x x 4 = 3x = 3x 3 7 = x -5x -3x + 4 =

Section 2.2 More about Solving Equations. Objectives Use more than one property of equality to solve equations. Simplify expressions to solve equations.

To solve an equation with variables on both sides, use inverse operations to "collect" variable terms on one side of the equation. Helpful Hint Equations.

Variables on Both Sides. Visual 5x + 6 = 3x + 12.

Math 021.  An equation is defined as two algebraic expressions separated by an = sign.  The solution to an equation is a number that when substituted.

TABLES AND VALUES Section 1.5. Open Sentence Equation.

Solving Systems Using Elimination

Review of Definitions.

Ch 2.5 Variable on Both Sides Objective: To solve equations where one variable exists on both sides of the equation.

5.2: Solving Systems of Equations using Substitution

1.3 Solving with Variables on Both Sides. What We Will Learn Solve linear equations that have variables on both sides Identify special solutions.

Solve the following system using the elimination method.

Lesson 1-8 Solving Addition and Subtraction Equations.

1.4 Solving Multi-Step Equations. To isolate the variable, perform the inverse or opposite of every operation in the equation on both sides of the equation.

One Answer, No Answers, or an Infinite Number of Answers.

Two Step Equation 2x + 6 = x = x = 5.

to one side of an equation, When you do something.

3.4 Solving Equations with Variables on Both Sides Objective: Solve equations that have variables on both sides.

Solving Equations. To solve an equation, you must isolate the variable (get the letter by itself). You do this by using opposite operations to undo what’s.

Copyright © 2011 Pearson Education, Inc. Equations Involving Absolute Value Solve equations involving absolute value.

Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Chapter 2 Equations, Inequalities and Problem Solving.

Sec. 1-5 Day 1 HW pg (16-26 even, 33-36). An identity is an equation that is true for all values of the variable. An equation that is an identity.

Holt McDougal Algebra Solving Equations with Variables on Both Sides 1-5 Solving Equations with Variables on Both Sides Holt Algebra 1 Warm Up Warm.

Solve 7n – 2 = 5n + 6. Example 1: Solving Equations with Variables on Both Sides To collect the variable terms on one side, subtract 5n from both sides.

Solving Systems by Elimination 5.4 NOTES, DATE ____________.

2-4 Solving Equations with Variables on Both Sides.

2.4 Equations with Variables on Both Sides To solve an equation with variables on both sides, you must use the Addition or Subtraction Properties of Equality.

4.3 Notes : Solving Radical Equations A radical equation is an equation that contains a variable under a radical symbol The parent radical function is.

SOLVING SYSTEMS OF EQUATIONS BY SUBSTITUTION. #1. SOLVE one equation for the easiest variable a. Isolated variable b. Leading Coefficient of One #2. SUBSTITUTE.

Objective - To solve simple, one- step variable equations What is an equation? Equation - a balanced statement of equality between two quantities. 4 +

Solving equations with variable on both sides Part 1.

Lesson 8.1. » A statement where two mathematical expressions are. » Think of an equation as a balance scale or teeter-totter. The left side must always.

Lesson 2.8 Graph Linear Inequalities in Two Variables.

Identities, Contradictions and Conditional Equations.

Equations with Variables on Both Sides Chapter 3 Section 3.

3. 3 Solving Equations Using Addition or Subtraction 3

3/1/2016 Algebra Ms. Narczewski

EQUATION IN TWO VARIABLES:

Example: Solve the equation. Multiply both sides by 5. Simplify both sides. Add –3y to both sides. Simplify both sides. Add –30 to both sides. Simplify.

Cell phone use is prohibited.

Algebra Bell-work 9/13/17 Turn in your HW! 1.) 7x – 6 = 2x + 9

6-2 Solving Systems using Substitution

Solving Equations with variables on each side

Solving Algebraic Equations

Objective Solve equations in one variable that contain variable terms on both sides.

Equations with Variables on Both Sides Day 2

Solving Equations with Variables on Both Sides Day 2

6.1 to 6.3 Solving Linear Inequalities

6.1 to 6.3 Solving Linear Inequalities

Solving Equations with Variables on Both Sides

- Finish Unit 1 test - Solving Equations variables on both sides

Question How do you solve a system of simultaneous equations by substitution?

SECTION 2-4 : SOLVING EQUATIONS WITH THE VARIABLE ON BOTH SIDES

Objective Solve equations in one variable that contain variable terms on both sides.

Solve Equations With Variables on Both

Solving Equations with Variables on Both Sides

Solving Equations with Variables on Both Sides

Key Points (3-1) Add or Subtract to Solve Equations Introduction

Exercise Solve x – 14 = 35. x = 49.

Lesson Objective: I will be able to …

2 Chapter Chapter 2 Equations, Inequalities and Problem Solving.

Solving Equations with Variables on Both Sides Day 2

Presentation transcript:

Objective - To solve equations with the variable in both sides. 2x + 4 = 5x - 17 2x + 4 = 5x - 17 2x + 4 = 5x - 17 -2x -2x -5x -5x 4 = 3x - 17 -3x + 4 = -17 +17 +17 -4 -4 21 = 3x -3x = -21 3 3 -3 - 3 7 = x x = 7

Rules for Solving Equations 1) Goal: Isolate the variable on one side of the equation. 2) Undo operations with their opposite operation. 3) Always do the same thing to both sides of the equation. 4) Easiest to undo add/subtract before multiply/divide.

Solve. 1) 4(x - 2) - 2x = 5(x - 3) 4x - 8 - 2x = 5x - 15 2x - 8 = 5x - 15 -2x -2x -8 = 3x - 15 +15 +15 7 = 3x 3 3

2) 3(x + 2) - (2x - 4) = - (4x + 1) 3x + 6 - 2x + 4 = - 4x - 1 x + 10 = - 4x - 1 + 4x + 4x 5x + 10 = -1 - 10 -10 5x = -11 5 5 x = =

3) 5(m - 6) = 10 - 4[2(m - 7) - 5m] 5m - 30 = 10 - 4[2m - 14 - 5m] 5m - 30 = 10 - 4[-3m - 14] 5m - 30 = 10 + 12m + 56 5m - 30 = 12m + 66 -5m -5m -30 = 7m + 66 -66 -66 -96 = 7m 7 7

Solve each equation below. a) 3x - 5 = 2x + 12 b) 3x + 8 = 2(x + 4) + x -2x -2x 3x + 8 = 2x + 8 + x x - 5 = 12 3x + 8 = 3x + 8 +5 +5 -3x -3x x = 17 8 = 8 True ! One Solution Identity x = any real number c) 3x + 2 = 2(x - 1) + x 3x + 2 = 2x - 2 + x 3x + 2 = 3x - 2 -3x -3x 2 = -2 False ! No Solution

Solve. 4) 4(y - 2) + 6y = 7(y - 8) - 3(10 - y) -8 = -86 False Statement No Solution

5) 3(4 + k) - 2(3k + 4) = 5(k - 3) - (8k - 19) Solve. 5) 3(4 + k) - 2(3k + 4) = 5(k - 3) - (8k - 19) 12 + 3k - 6k - 8 = 5k - 15 - 8k + 19 -3k + 4 = -3k + 4 +3k +3k 4 = 4 True Statement Infinitely Many Solutions x = any real number