FIRE UP!! Turn in your signed syllabus to the front basket. Welcome BACK!  Turn in your signed syllabus to the front basket. Pickup from Front Desk: Parent Function Packet ½ Page sheet

Warm-up Distributive Property Simplify the following expression. Discuss with your neighbor. -2(3x – 5) -6x + 10

Discuss with your neighbor reasons you should learn math! http://youtu.be/yir86f0Uulw

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Parent Function Project 7 Functions to graph and find key information Due on test day (9-19/20) Counts ½ of the test grade Lots of resources Websites Youtube Videos Textbook Some time will be given to work on these in class and also ask questions.

Solving Linear Equations Unit 1 Solving Linear Equations

I can solve equations with one variable Objectives I can solve equations with one variable

Vocabulary Terms Variable Like Terms

Any letter or symbol used to represent a number that is not known Variable Any letter or symbol used to represent a number that is not known

Terms that have the same variables raised to the same powers Like Terms Terms that have the same variables raised to the same powers

Think of Money

Like Term Activity -1 2x2 -3y 12x 3 5y 2 3x2 9y -x2 17 9 -1 2x2 -3y 12x 3 -7x 5y 2 3x2 9y -x2 Group the like terms together in your notes. Now that they are grouped, COMBINE your LIKE Terms.

Like Term Activity x 2y -x y 17 9 -1 2x2 -3y 12x 3 -7x 5y 2 3x2 9y -x2

Combining Like Terms

Solving Equations Let’s see what we recall from Algebra-1 to solve an equation for a missing variable??

Alg-1 Recall

What really Happened? What steps really happen to solve that equation?

Equations?? What happens to a term anytime you move it to the other side of the = ?

Solving Equations Get the variable terms together on the left side of the equation Move all the numbers to the other side of the equation. LAST step is always DIVISION (or Multiply by a reciprocal)

Example 1

Example 2

What about FRACTIONS??

GUIDED PRACTICE Solve the equation. 3 5 – 2. x + 1 = 4 SOLUTION 3 5 – Write original equation. 3 5 – x = 3 Subtract 1 from each side. x = – (3) 5 3 Multiply each side by , the reciprocal of . 5 3 – x = – 5 Simplify. ANSWER The solution is 5.

In Class Practice Work with your partner and solve the first 4 problems on the activity. Check your answers on the website.

Word Problems The bill for the repair of a car was $420. The cost of parts was $240. The cost of labor was $45 per hour. Write an equation and then solve for how many hours the repair took.

Solution: Total cost: $420 Parts: $240 Labor: $45 per hour Possible Equation: Let “x” represent the # of hours 240 + 45x = 420 x = 4 hours

In Class Practice Work with your partner and solve the last word problem on the activity. Check your answer on the website.

No Variables Left

No Variables No Solution All Real Numbers 2x + 4 = 2x – 3 When you subtract the 2x you end up with 4 = -3 This is not true Meaning, there is no value for “x” to make this equation valid. 2x + 4 = 2x + 4 When you subtract the 2x you end up with 4 = 4 This is true Meaning, that every value of “x” will make this equation valid

Homework WS 1-1: Solving Equations Signed Syllabus if not already returned Work on Parent Function Project