FOT Semester Exam Wednesday, May 25 -Free Response Thursday, May 26 - Multiple choice You must have a calculator for free response – NO SHARING and NO CELL PHONES Semester Exam is worth 1/6 th of your FOT final grade REVIEW For each problem: 1) List all given information 2) Sketch a diagram if required 3) Write the applicable formula and rearrange if necessary 4) Substitute the known values and solve for unknown 5) Show correct units 6) Circle/ Box the correct answer.

1. You carry a basket of laundry weighing 25 pounds up a flight of stairs with a total height of 9 feet. How much work did you do (keep all units)? REVIEW W = ? F = 25 lbs D = 9 ft List Given Information Write Formula W = F x D Substitute Values W = 25 lbs x 9 ft Solve W = 225 ft-lbs

Review 2010 Hummer H2 Output = 320 miles Input = 32 gallons Efficiency = ? 2010 Toyota Prius Output = 500 miles Input = 10 gallons Efficiency = ? Eff=Wo / Wi Eff= 500 mls / 10 gal Eff = 50 mpg Eff=Wo / Wi Eff= 320 miles / 32 gal Eff = 10 mpg

3. A hot air balloon carries 300 lbs cargo, 250 lbs human, and 450 lbs materials up a distance of 2,000 feet. How much work did the balloon do (keep all units)? Review W = ? F = 300 lbs+ 250 lbs +450lbs D = 2,000 ft List Given Information Write Formula W = F x D Substitute Values W = 1,000 lbs x 2,000 ft Solve W = 2,000,000 ft-lbs

Review 4.A physical therapy doctor told his 200-lb patient to do 30,000 ft-lbs of work each day to rehabilitate his leg. The patient decides to climb a hill to perform this work. How high does the patient need to climb in order to meet his goal? W = 30,000 ft-lbs F = 200 lbs D = ?? List Given Information Write Formula W = F x D Substitute Values 30,000 ft-lbs 200 lbs x D Solve D = 150 ft

Review 5.A 1 st class lever is used to lift a fallen log that weighs 120 lbs. The log is located 3 ft from the fulcrum. A child can apply a 12 lb force on the other side. How far from the fulcrum should the child stand? 120 lbs 3 ft.DF = ? F = 12lbs L = 120 lbs DL = 3 ft F = 12 lbs DF = ??? List Given Information Write Equation Sketch Diagram LxDL=FxDF Substitute and Solve 120lbs x 3 ft = 12 lbs x DF DF = 30 ft

Review 6.A gardener is capable of applying 50 lbs to lift a wheelbarrow. His hands are placed 4 ft from the axle. If the dirt is located 2 ft from the axle, how much dirt can the gardener carry? 2ft DF = 4ft F = 50lbs L = ? DL = 2 ft F = 50 lbs DF = 4ft List Given Information Write Equation Sketch Diagram LxDL=FxDF Substitute and Solve L x 2 ft = 50 lbs x 4ft L = 100lbs

Review 6. A 3 rd class mechanical lever is used to remove snow without damaging the pavement. The machine can apply 600 lbs of fore. The distance from the load to the fulcrum is 8 ft. The distance to the applied force is 4 ft. What is the maximum amount of snow removed, what is the mechanical advantage? DF= 4ft DL = 8ft F = 600lbs L = ? DL = 8 ft F = 600 lbs DF = 4ft List Given Information Write Equation Sketch Diagram LxDL=FxDF Substitute and Solve L x 8 ft = 600 lbs x 4ft L = 300lbs M.A. =1/2

Review 8.A fixed pulley system is used to lift a bucket from a well. How many pounds are required to lift 60 lbs of water. MA = 1 L = 60 lbs F = ?? List Given Information Write Equation Sketch Diagram Substitute and Solve 1 = 60 lbs / F F = 60 lbs

Review 9.A movable pulley system is used to lift a bucket from a well. How many pounds are required to lift 60 lbs of water. MA = 2 L = 60 lbs F = ?? List Given Information Write Equation Sketch Diagram Substitute and Solve 2 = 60 lbs / F L = 60lbs F = 30 lbs

Review 10.A block and tackle pulley system is used to lift a bucket from a well. How many pounds are required to lift 60 lbs of water. MA = 3 L = 60 lbs F = ?? List Given Information Write Equation Sketch Diagram Substitute and Solve 3 = 60 lbs / F F = 20 lbs

11. A Lexus RX400h hydrid carries a 288-volt battery stystem. The batteries power electric motors that use 44.8 kW of power. What is the current traveling through this high voltage current. What is the resistance? REVIEW P = 44,800 W I = ? V = 288 V List Given Information Write Formula P = I x V V = 288V I = ? - + P = 44,800 W 44,800 W = I x 288 V I = 156 A

11. A Lexus RX400h hydrid carries a 288-volt battery stystem. The batteries power electric motors that use 44.8 kW of power. What is the current traveling through this high voltage current. What is the resistance? REVIEW V = 288 V I = 156 A R = ?? List Given Information Write Formula V = I x R V = 288V I = ? - + P = 44,800 W 288 V = 156 A x R I = 1.85 Ohm

U3e-L3 12. Use the Schematic to solve for R A, R B, and R T 4  12  10  40 

U3e-L3 12. Use the Schematic to solve for R A, R B, and R T 4  12  10  40 

U3e-L3 13. Use the Schematic to find the total resistance of the circuit 1.5  7  6 

U3e-L3 14. Use the Schematic to solve for R 4  120V R=? 40  5 Amp V = 120V I = 5 A R = ?? V = IxR List Given Information 120 V = 5A x R R = 24 Ohm

U3e-L3 14. Use the Schematic to solve for R 4  120V R=? 40  5 Amp R = 60 Ohm

U3f – L3 15.A sample of hydrogen gas is compressed from 300 cm 3 to 2 cm 3. Its pressure is now 5 psi. What was the original pressure of the helium? Step 1: Write given information P1 = ? V1 = 300 cm 3 P2 = 5 psi V2 = 2 cm 3 Step 2: Write the formula and solve P 1 V 1 = P 2 V 2 P1 x (300 cm 3 ) = 5 psi x (2 cm 3 ) P1 x (300 cm 3 ) = 10 psi* cm cm cm 3 P1 = psi

U3f – L3 16. The surface of a concrete block that touches the ground is 1.5 ft^2. What is the pressure on the ground if the block weighs 25 lbs Step 1: Write given information P = ? F = 25 lbs A= 1.5 ft 2 Step 2: Write the formula and solve P=F/A P = 25 lbs/1.5 ft^2 P = 16.7 psf

U3f – L3 17. What would hurt more: 25 lbs against 1 square inch of your body or 5 pounds against 0.01 square inches Step 1: Write given information P1 = ?P2 = ? F1 = 25 lbs F2 = 5 lbs A1= 1 in 2 A2= 0.1 in 2 Step 2: Write the formula and solve P1=F1/A1P2 = F2/A2 P1= 25 lbs/1 in^2P2 = 5 lbs/0.01 in^2 P1 = 25 psiP2 = 500 psi

U3f – L3 The diagram below illustrates how hydraulic brakes in a car work. The pedal must be pressed with a force of 10 lbs. The surface area of the piston connected to the pedal is 1 square inch. If the surface area of the piston connected to the other end of the brake line is 2.5 square inch, what is the force applied to that piston? P 1 = P 2 Problem 18 P1 = F1 / A1P2 = F2 / A2

U3f – L3 Problems Solution: Step 1: Write given information P1 = ?P2 = ? F1 = 10 lbs.F2 = ? A1 = 1 in 2 A2 = 2.5 in 2 Step 2: Write the formula and solve for the unknowns P1 = F1 / A1 P1 = (10 lbs) / (1 in 2 ) P1 = 10 psi P1 = P2 = 10 psi F2 = 10 psi x 2.5 in 2 = 25 lbs. P2 = F2 / A2 F2 = P2 x A2