Over Chapter 7 A.A B.B C.C D.D 5-Minute Check 6 A.26 B.52 C.78 D.156 The circle graph shows the results of a middle school survey about favorite lunch.

Slides:



Advertisements
Similar presentations
Over Lesson 8–2 A.A B.B C.C D.D 5-Minute Check 1 Which equation best describes the sequence 9, 10, 11, 12, …? Find the 22nd term of the sequence 7, 10,
Advertisements

Lesson 4-4 Example Solve. DRINKS It costs $3 per bottle of orange drink. Graph an equation to represent the cost of purchasing x bottles of orange.
Over Lesson 8–6 A.A B.B C.C D.D 5-Minute Check 1 Find the slope of the line that passes through E(1, 4) and F(5, –2). Find the slope of the line that passes.
Splash Screen Chapter 9 Lesson A 2.B 3.C 4.D Solve the inequality –2x ≤ 5. Then check your solution. (over Chapter 8) A. B. C. D.
Over Lesson 8–7 A.A B.B C.C D.D 5-Minute Check 1 Find the slope and y-intercept for the graph of y = x + 5. Find the slope and y-intercept for.
Math 015 Section 6.6 Graphing Lines. Objective: To check solutions of an equation in two variables. Question: Is (-3, 7) a solution of y = -2x + 1 ? y.
RELATIONS AND FUNCTIONS
Vocabulary Analyze the Graph Relations vs. Functions.
Warm Up 1. 5x – 2 when x = – t 2 when 3. when x = Give the domain and range for this relation: {(1, 1), (–1, 1), (2, 4), (–2, 4),
Splash Screen. Vocabulary function discrete function continuous function vertical line test non linear function.
2.3) Functions, Rules, Tables and Graphs
Over Lesson 4–3 A.A B.B C.C D.D 5-Minute Check 1 x = -3 Solve x – 3 = –6. Check your solution. Solve y + 9 = 7. Check your solution. y = -2 Solve –13 =
4-1: Relations and Functions
Over Lesson 1–3 A.A B.B C.C D.D 5-Minute Check 1 A.Multiplicative Identity B.Additive Identity C.Associative Property of Addition D.Associative Property.
Splash Screen. Lesson Menu Five-Minute Check (over Lesson 1–5) Then/Now New Vocabulary Example 1:Representations of a Relation Example 2:Real-World Example:
Splash Screen. Lesson Menu Five-Minute Check (over Lesson 8–1) Then/Now New Vocabulary Example 1:Describe an Arithmetic Sequence Example 2: Find a Term.
Over Lesson 8–9 A.A B.B C.C D.D 5-Minute Check 1 Which is an equation for the line of best fit for the scatter plot where x is the years since 1998 and.
Then/Now You recognized arithmetic sequences and related them to linear functions. (Lesson 3–5) Write an equation for a proportional relationship. Write.
Representing Functions
What is the domain of the following relation? (use correct notation) { (1, 3), (4, 5.5), (6, 9), (10, 0) }
Lesson 3.1 Objective: SSBAT define and evaluate functions.
Formalizing Relations and Functions
Splash Screen. Concept 1 Example 1 Domain and Range State the domain and range of the relation. Then determine whether the relation is a function. If.
Splash Screen. Lesson Menu Five-Minute Check (over Chapter 1) CCSS Then/Now New Vocabulary Key Concept: Functions Example 1:Domain and Range Key Concept:
Identifying Relations and Functions A relation is a set of ordered pairs. The domain of the relation is x-coordinate of the ordered pair. It is also considered.
Over Lesson 12–3 A.A B.B C.C D.D 5-Minute Check 2 Find the volume of the cylinder.
Splash Screen. Lesson Menu Five-Minute Check (over Chapter 2) Then/Now New Vocabulary Example 1:Solve by Using a Table Example 2:Solve by Graphing Example.
Bell Quiz.
Relations and Functions. Review A relation between two variables x and y is a set of ordered pairs An ordered pair consist of a x and y-coordinate A relation.
Vocabulary independent variable dependent variable vertical line test function notation.
Over Lesson 1–1 A.A B.B C.C D.D 5-Minute Check 4 A.13 × 8 B C.13 > 8 D.13 – 8 1. Write a numerical expression for thirteen more than eight. A. B.
Then/Now You graphed ordered pairs in the coordinate plane. (Lesson 1–6) Use rate of change to solve problems. Find the slope of a line.
Relations Relation: a set of ordered pairs Domain: the set of x-coordinates, independent Range: the set of y-coordinates, dependent When writing the domain.
Over Lesson 6–3 A.A B.B C.C D.D 5-Minute Check 6 I drive to Philly, a 300 mile trip, in 6 hours. What is my unit rate of speed, in simplest form. Bob wants.
Then/Now You found rates of change of linear functions. (Lesson 3–3) Write and graph direct variation equations. Solve problems involving direct variation.
Splash Screen. Lesson Menu Five-Minute Check (over Lesson 2–3) Then/Now New Vocabulary Key Concept:Slope-Intercept Form Example 1:Write an Equation in.
Concept 1. Example 1 Identify Functions A. Determine whether the relation is a function. Explain. Answer: This is a function because the mapping shows.
LESSON 7.4 Function Notation To learn function notation To evaluate functions by substitution, by using the graphs drawn by hand, and on the graphing calculator.
Then/Now You represented relationships among quantities using equations. (Lesson 2–1) Graph linear equations. Identify linear equations, intercepts, and.
By: Jared Martin 6 th period. Real world problem  Josh got $ for his birthday, and he bought x pair of shoes with it.
Then/Now You solved equation with elements from a replacement set. (Lesson 1–5) Determine whether a relation is a function. Find function values.
Over Lesson 3–5. Splash Screen Proportional and Non- Proportional Relationships Lesson 3-6.
Splash Screen. Lesson Menu Five-Minute Check (over Chapter 1) Then/Now New Vocabulary Key Concept: Functions Example 1:Domain and Range Key Concept: Vertical.
Objectives The student will be able to:
I CAN DETERMINE WHETHER A RELATION IS A FUNCTION AND I CAN FIND DOMAIN AND RANGE AND USE FUNCTION NOTATION. 4.6 Formalizing Relations and Functions.
Holt CA Course Functions Warm Up Warm Up California Standards California Standards Lesson Presentation Lesson PresentationPreview.
5.2 Relations and Functions. Identifying Relations and Functions Relation: A set of ordered pairs. You can list the set of ordered pairs in a relation.
CCSS Content Standards F.IF.4 For a function that models a relationship between two quantities, interpret key features of graphs and tables in terms of.
Over Lesson 1–4 A.A B.B C.C D.D 5-Minute Check 1 A.V B.P C.Q D.R E.T F.S G.U Name the coordinates of the following points (1, 3) (2, 5) (3, 2) (4, 3) (6,
Section 1-1: Relations and Functions *Relation: *Domain: *Range: *Function: Example 1: State the domain and range of each relation. Then state whether.
Splash Screen. Over Lesson 1–6 5-Minute Check 1 Which expresses the relation {(–1, 0), (2, –4), (–3, 1), (4, –3)} correctly? A.B. C.
Splash Screen. Lesson Menu Five-Minute Check (over Lesson 1–6) Then/Now New Vocabulary Key Concept: Function Example 1:Identify Functions Example 2:Draw.
Algebra 2 Foundations, pg 64  Students will be able to graph relations and identify functions. Focus Question What are relations and when is a relation.
Functions Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day Lesson Quizzes Lesson Quizzes.
Splash Screen.
2.1 – Represent Relations and Functions.
VOCABULARY! EXAMPLES! Relation: Domain: Range: Function:
Lesson 1-7 Glencoe Algebra 1 FUNCTIONS Lesson 1-7 Glencoe Algebra 1.
Proportional and Non-Proportional Relationships
Relations and Functions
5.2 Relations and Functions
2-1 Relations and Functions
Splash Screen.
Introduction to Functions
Splash Screen.
UNDERSTANDING FUNCTIONS
Formalizing Relations and Functions
Relations and Functions
Splash Screen.
Presentation transcript:

Over Chapter 7 A.A B.B C.C D.D 5-Minute Check 6 A.26 B.52 C.78 D.156 The circle graph shows the results of a middle school survey about favorite lunch foods. Suppose 650 students were surveyed. How many more students favor salad than hoagies?

Splash Screen

Then/Now You have already learned how to find function rules and create function tables. (Lesson 1–5) Determine whether a relation is a function. Write a function using function notation.

Vocabulary independent variable dependent variable vertical line test function notation The variable in a function with a value that is subject to choice (you pick it) The variable in a relation with a value that depends on the value of the independent variable If any vertical line drawn on the graph of a relation passes through no more than one point on the graph for each value of x in the domain, then the relation is a function A way to name a function that is defined by an equation. In function notation, the equation y=3x-8 is written as f(x) = 3x - 8

Example 1A Determine Whether a Relation is a Function A. Determine whether the relation is a function. Explain.  (3, 48), (7, 21), (5, 15), (1, 13), (2, 12)  Answer: Yes; this is a function because each x-value is paired with only one y-value.

Example 1B Determine Whether a Relation is a Function B. Determine whether the relation is a function. Explain. Answer: No; this is not a function because 3 in the domain is paired with more than one value in the range.

A.A B.B C.C D.D Example 1 CYP A A.It is a function because each x-value is paired with only one y-value. B.It is a function because each y-value is paired with only one x-value. C.It is not a function because an x-value is paired with more than one y-value. D.It is not a function because a y-value is paired with more than one x-value. A. Determine whether the relation is a function. Explain. {(1, 5), (–2, 7), (3, 8), (4, 5)}

A.A B.B C.C D.D Example 1 CYP B B. Determine whether the relation is a function. Explain. A.It is a function because each x-value is paired with only one y-value. B.It is a function because each y-value is paired with only one x-value. C.It is not a function because an x-value is paired with more than one y-value. D.It is not a function because a y-value is paired with more than one x-value.

Example 2 Use a Graph to Identify Functions Determine whether the graph is a function. Explain your answer. Answer: No; The graph is not a function because it does not pass the vertical line test. When x = 7, there are two different y-values.

A.A B.B C.C D.D Example 2 Determine whether the graph is a function. Explain. A.It is a function because each domain value is paired with only one range value. B.It is a function because each range value is paired with only one domain value. C.It is not a function because a domain value is paired with more than one range value. D.It is not a function because a range value is paired with more than one domain value.

Example 3A Find a Function Value A. If f(x) = 6x + 5, what is the function value of f(5)? f(x)=6x + 5Write the function. f(5)=6 ● 5 + 5Replace x with 5. f(5)=35Simplify. Answer:35

Example 3B Find a Function Value B. If f(x) = 6x + 5, what is the function value of f(–4)? f(x)=6x + 5Write the function. f(–4)=6 ● (–4) + 5Replace x with –4. f(–4)=–19Simplify. Answer:–19

A.A B.B C.C D.D Example 3 CYP A A.–5 B.–1 C.1 D.5 A. If f(x) = 2x – 7, what is the value of f(4)?

A.A B.B C.C D.D Example 3 CYP B A.–13 B.–10 C.10 D.13 B. If f(x) = 2x – 7, what is the value of f(–3)?

Example 4A Use Function Notation A. GREETING CARDS Ms. Newman spent $8.82 buying cards that sold for $0.49 each. Use function notation to write an equation that gives the total cost as a function of the number of cards purchased. Answer:t(c) = 0.49c

Example 4B Use Function Notation B. GREETING CARDS Ms. Newman spent $8.82 buying cards that sold for $0.49 each. Use the equation to determine the number of cards purchased. t(c)=0.49cWrite the function. 8.82=0.49cReplace t(c) with =cDivide each side by Answer:So, Mrs. Newman bought 18 cards.

A.A B.B C.C D.D Example 4 CYP A A.t(c) = 0.59c B.c = 0.59 ● t(c) C.t(c) = c D.c = t(c) A. CANDY BARS Erik bought candy bars that cost $0.59 cents each. Which function describes his purchase if t(c) = total cost and c = the number of candy bars?

A.A B.B C.C D.D Example 4 CYP B A.5 candy bars B.6 candy bars C.8 candy bars D.9 candy bars B. CANDY BARS Erik bought candy bars that cost $0.59 cents each and spent $4.72. If t(c) = total cost and c = the number of candy bars, use the function t(c) = 0.59c to find the number of candy bars purchased.

End of the Lesson