Nitroglycerine 100 g Nitro 1mol Nitro 227 g Nitro 29 mol gas 4mol Nitro = 3.193 mol gas Or =.110 mol O 2 =.661 mol N 2 = 1.10 mol H 2 O = 1.32 mole CO.

Slides:



Advertisements
Similar presentations
Ch. 11 Molecular Composition of Gases
Advertisements

Three More Laws. A. Ideal Gas Law The 4 th variable that considers the amount of gas in the system is P 1 V 1 T 1 n = P 2 V 2 T 2 n Equal volumes of gases.
Gases Part
Ideal Gas Law & Gas Stoichiometry
Pressure Pressure: Force applied per unit area. Barometer: A device that measures atmospheric pressure. Manometer: A device for measuring the pressure.
Molecular Composition of Gases
Basic Stoichiometry Pisgah High School M. Jones Revision history: 5/16/03, 02/04/12, 04/27/12 With the Gas Laws.
The Ideal Gas Law and Stoichiometry Chemistry 142 B Autumn Quarter, 2004 J. B. Callis, Instructor Lecture #14.
Gas Stoichiometry A balanced equation shows the ratio of moles being used and produced Because of Avogrado’s principle, it also shows the ratio of volumes.
Mullis1 Gay Lussac’s law of combining volumes of gases When gases combine, they combine in simple whole number ratios. These simple numbers are the coefficients.
Pressure Partial Pressure Gas Stoichiometry Pressure = Force/Area Dalton’s Law of Partial Pressures Avogadro’s Law.
III. Ideal Gas Law Gases Gases. V n A. Avogadro’s Principle b Equal volumes of gases contain equal numbers of moles at constant temp & pressure true for.
Molecular Composition of Gases
What happens when we change the quantity of gas
Gases Chapter 5. What you need to know… PV = nRT for gas stoichiometry Partial pressures for kinetics and equilibrium later Water vapor pressure calculations.
Topic 10 Gases III. Ideal Gas Law.
Ideal Gas Law.
Ideal Gas Law & Gas Stoichiometry
Ideal Gas Law.
Ideal Gas Law & Gas Stoichiometry
III. Ideal Gas Law Gases. PV T VnVn PV nT A. Ideal Gas Law = k UNIVERSAL GAS CONSTANT R= L  atm/mol  K R=8.315 dm 3  kPa/mol  K = R You don’t.
Gas Laws By: Ms. Buroker. Gas Laws Gas Laws explores the relationships between: Volume, V … Liters Temperature, T … Kelvin Amount, n … moles Pressure,
Ideal Gas Law (Equation):
Chapter 10; Gases. Elements that exist as gases at 25 0 C and 1 atmosphere.
Chapter 11 Molecular Composition of Gases. Avogadro’s Law Equal Volumes of Gases at the Same Temperature & Pressure contain the Same Number of “Particles.”
To solve problems involving volumes of gases NOT at STP in chemical reactions: Combine PV = nRT and stoichiometry.
Chapter #11 Molecular Composition of Gases. Chapter 11.1 Gay-Lussac’s law of combining volumes of gases states that at constant temperature and pressure,
Sunday is Groundhog Day!. Enjoy the Super Bowl on Sunday!
Section 13.2 Using Gas Laws to Solve Problems. Section 13.2 Using Gas Laws to Solve Problems 1.To understand the ideal gas law and use it in calculations.
III. Ideal Gas Law (p , ) Ch. 10 & 11 - Gases.
Kp When the reactants and products are gases, we can determine the equilibrium constant in terms of partial pressures. Dalton’s Law of Partial Pressures.
C. Johannesson III. Ideal Gas Law (p , ) Ch. 10 & 11 - Gases.
III. Ideal Gas Law and Dalton’s Law of Partial Pressure Gases.
Stoichiometry Calculating Reactants and Products.
Gas Stoichiometry!. equal volumes of gases at the same temperature & pressure contain equal numbers of particles equal volumes of gases at the same temperature.
Chapter 14-3 I. Avogadro’s Principle A. Equal volumes of gases at same T and P contain equal #’s of molecules B. H 2 + Cl 2 → 2HCl 1 vol. 1 vol. 2 vol.
Gas Stoichiometry. We have looked at stoichiometry: 1) using masses & molar masses, & 2) concentrations. We can use stoichiometry for gas reactions. As.
Chapter 14-3 I. Avogadro’s Principle A. Equal volumes of gases at same T and P contain equal #’s of molecules B. H 2 + Cl 2 → 2HCl 1 vol. 1 vol. 2 vol.
Chapter 11 – Ideal Gas Law and Gas Stoichiometry.
Dalton’s Law of Partial Pressure
Molecular Composition of Gases
Dalton’s law of partial pressure At constant volume and temperature, the total pressure of a mixture of gases is the sum of the partial pressures of all.
Ideal gases and molar volume
Ideal Gases. Ideal Gas vs. Real Gas Gases are “most ideal”… at low P & high T in nonpolar atoms/molecules Gases are “real”… Under low T & high P when.
Stoichiometry Chemical Quantities Chapter 9. What is stoichiometry? stoichiometry- method of determining the amounts of reactants needed to create a certain.
Chapter 11: Molecular Composition of Gases. Sect. 11-1: Volume-Mass Relationships of Gases Gay-Lussac’s Law of combining volumes of gases – at constant.
Ch. 10 & 11 - Gases Ideal Gas Law C. Johannesson.
Honors Chemistry, Chapter 11 Page 1 Chapter 11 – Molecular Composition of Gases.
Daltons Law of Partial Pressures. Dalton’s Law of Partial Pressures The partial pressure of a gas is the pressure of that gas in a mixture. Dalton’s Law.
Molar Relations. Stoichiometry The mathematics of chemical formulas and chemical equations. Chemists use a mole to “count” atoms.
Charles’ Law V 1 = V 2 T 1 T 2 Volume is directly proportional to temp (Pressure constant) Boyle’s Law P 1 V 1 = P 2 V 2 Pressure is inversely proportional.
The Gas Laws Ch. 14- Gases. Boyle’s Law P V PV = k Pressure and Volume are inversely proportional. As Volume increased, pressure decreases.
Chapter Five Gases. Chapter Five / Gases Substances That Exist as Gases Element in blue are Gases Noble gases are monatomic All other gases (H 2, N 2,
Ideal Gas Law Ch. 10 & 11 - Gases. V n A. Avogadro’s Principle b Equal volumes of gases contain equal numbers of moles at constant temp & pressure true.
A helium-filled balloon at sea level has a volume of 2.10 L at atm and 36 C. If it is released and rises to an elevation at which the pressure is.
Ideal Gas Law & Gas Stoichiometry Work out each problem in the 3-step format. Gases notes #4 - Ideal Gas Law & Gas Stoichiometry.pptx.
Molar Relations. Stoichiometry The mathematics of chemical formulas and chemical equations. Chemists use a mole to “count” atoms.
Gases. Units of Pressure 1atm. = 760mm Hg (torr) = 101,325 pascals (Pa) = kPa = psi.
Gases.
Gases Chapter 5 Lesson 2.
Guy-Lussac’s Law P1 / T1 = P2 / T2
Ideal Gas Law PV=nRT.
Chem Get Gases MC Practice WS stamped off if you did not do so last class. Unit 5 Test Mon 1/29, Tues 1/30 Gas Laws Project due: Fri 2/2.
Guy-Lussac’s Law P1 / T1 = P2 / T2 Avogadro’s Law V1 / n1 = V2 / n2
Objectives To understand the ideal gas law and use it in calculations
Ch. 11 Molecular Composition of Gases
Stoichiometry.
The Combined Gas Law and the Ideal Gas Law
Gas Volumes and Ideal Gas Law
Chem Get Gases MC Practice WS stamped off if you did not do so last class. Unit 8 Test Fri 2/22.
Presentation transcript:

Nitroglycerine 100 g Nitro 1mol Nitro 227 g Nitro 29 mol gas 4mol Nitro = mol gas Or =.110 mol O 2 =.661 mol N 2 = 1.10 mol H 2 O = 1.32 mole CO 2

Nitroglycerine V = PV = nRT V = nRT/P mol ( L atm/mol K) 425 C 1atm 698 K V = 183 L

H 2 + Cl 2  2HCl(g) g of Cl 2 Limiting Reactant Problem – the hard way Moles HCl g of H 2 Moles Cl 2 Moles H 2 FW Balanced Eq Select limiting reagent Moles Cl 2 Moles H 2 used Final pressure = pressure of HCl + pressure of excess reagent Starting moles H 2 - Moles H 2 used Excess moles H 2 Moles HCl Moles H 2 xs Total moles of gas + PV = nRT P = 193 torr

H 2 + Cl 2  2HCl(g) g of Cl 2 Understanding Gases – the easy way Pressure Cl 2 Pressure H 2 g of H 2 Moles Cl 2 Moles H 2 FW PV = nRT Add to get Initial pressure Final pressure = Initial P = P Cl 2 + P H 2 Remember that the composition of a gas does NOT effect the pressure it exerts. So, since there is no change in the number of MOLES of gas during the reaction, there will be no change in the pressure. Thus the initial pressure equals the final pressure.

Stoichiometry ABCD + + Moles A Moles Cg of C FW Volume of C Molarity Molarity of C Volume Molecular weight # grams g of A FW Volume of A Molarity Molarity of A Volume Molecular weight Of A # grams Balanced Eq

Gases only!!!! Gas Stoichiometry ABCD + + Moles A Moles C g of A FW g of C FW Volume of A Molarity Volume of C Molarity Molarity of C Volume Molarity of A Volume Molecular weight # grams Molecular weight Of A # grams Balanced Eq (T and P/V same) Volume of A Pressure of A PV = nRT Pressure of C Volume of C PV = nRT

What is RMS for H 2 at room temp? =

=

= 2.0g/mol 1kg _ 1000g = 1.92 x 10 3 m/s ≈ 2000 m/s ≈ 4300 mi/hr

Why does it take so long to smell gas that is released in the same room?

Problems involving Gases PV=nRT can be used to get moles of gas from P, V and T. Once you have mole then it is just a normal limiting reagent or stoichiometry or titration or …. PV=nRT can be used to get moles of gas from P, V and T. Once you have mole then it is just a normal limiting reagent or stoichiometry or titration or ….

Gas Law Shortcuts All revolve around the fact that in gases, V and P does NOT depend on nature of gas. All revolve around the fact that in gases, V and P does NOT depend on nature of gas. Implications Implications Can sum moles of all products and then find P or V. (Dalton’s Law of Partial Pressures.) Can sum moles of all products and then find P or V. (Dalton’s Law of Partial Pressures.) Ratio of n:V or n:P is constant (at a given temp and P or V) So 2 moles of gas C takes up twice the volume of 1 mole of gas A at the same conditions. Ratio of n:V or n:P is constant (at a given temp and P or V) So 2 moles of gas C takes up twice the volume of 1 mole of gas A at the same conditions. Caution: Shortcuts are NOT always present. Caution: Shortcuts are NOT always present.

Polarity and IMF Polarity is the key to IMFs. Polarity is the key to IMFs. Select 2 molecules involved, find polarity of each. Select 2 molecules involved, find polarity of each. Polar/polar = dipole/dipole -strongest Polar/polar = dipole/dipole -strongest Nonpolar/nonpolar = induced/induced - strongest Nonpolar/nonpolar = induced/induced - strongest Polar / Nonpolar = dipole induced-dipole -strongest Polar / Nonpolar = dipole induced-dipole -strongest If dipole/dipole look for H-Bonding If dipole/dipole look for H-Bonding Requires: Requires:

Why don’t oil and water mix?