Mid Term Physics Review

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Gravity and Graphs

Momentum and Acceleration

Motion

Forces

Energy and Power

Gravity and Graphs Momentum and Acceleration MotionForces Energy and Power $100 $300 $200 $400 $500

Gravity and Graphs - $100 Gravity is A.Vector, units kg B.Vector, units N C.Scalar, units kg D.Scalar, units N

Gravity and Graphs - $200 The graph represents the relationship between the displacement of an object and its time travel along a straight line. What is the average speed of the object during the first 4.0 seconds? A. 0 m/s B. 2 m/s C. 8 m/s D. 4 m/s

Gravity and Graphs - $300 If the Earth were twice as massive as it is now, then the gravitational force between it and the Sun would be A. the same B. twice as great C. half as great D. four times as great

Gravity and Graphs - $400 What is the gravitational force of attraction between a planet and a 17kilogram mass that is falling freely toward the surface of the planet at 8.8 meters per second squared? a N b N c N d.8.8 N

Gravity and Graphs - $500 Gravitational force of attraction F exists between two point masses A and B when they are separated by a fixed distance. After mass A is tripled and mass B is halved, the gravitational attraction between the two masses is A.F B.6F C.3/2 F D.9F

- $100 Momentum and Acceleration - $100 A rocket with a mass of 1,000 kilograms is moving at a speed of 20 meters per second. The magnitude of the momentum is A. 50 kg.m/s B. 200 kg.m/s C. 20,000 kg.m/s D. 40,000 kg.m/s

- $200 Momentum and Acceleration - $200 The velocity of a car changes from 60. meters per second north to 45 meters per second north in 5.0 seconds. The magnitude of the car's acceleration is a) 9.8 m/s2 b) 15 m/s2 c) 3.0 m/s2 d) 53 m/s2

- $300 Momentum and Acceleration - $300 A 0.60-kilogram softball initially at rest is hit with a bat. The ball is in contact with the bat for 0.20 second and leaves the bat with a speed of 25 meters per second. What is the magnitude of the average force exerted by the ball on the bat? a) 15 N b)75 N c)125 N d)7500 N

- $400 Momentum and Acceleration - $400 A car moving at a speed of 8.0 meters per second enters a highway and accelerates at 3.0 meters per second 2. How fast will the car be moving after it has accelerated for 23 meters? a: 69 m/sb: 14.2 m/s c: 24 m/sd: 4 m/s

- $500 Momentum and Acceleration - $500 A 20-kilogram cart traveling east with a speed of 6 meters per second collides with a 30-kilogram cart traveling west. If both carts come to rest after the collision, what was the speed of the westbound cart before the collision? a)0 m/s b)9 m/s c)3 m/s d)4 m/s

- $100 Motion - $100 A runner completed the 100.-meter dash in 10.0 seconds. Her average speed was a)0.100 m/s b)10.0 m/s c)100. m/s d)1,000 m/s

- $200 Motion - $200 An object that is originally moving at a speed of 20. meters per second accelerates uniformly for 5.0 seconds to a final speed of 50. meters per second. What is the acceleration of the object? a:.3 m/s 2 b: 10 m/s 2 c: 6 m/s 2 d: 20 m/s 2

- $300 Motion - $300 The graph represents the relationship between distance and time for an object in motion. During which interval is the speed of the object changing? a)A to B b)B to C c)C to D d)D to E

- $400 Motion - $400 A 4.0-kilogram rock and a 1.0-kilogram stone fall freely from rest from a height of 100. meters. After they fall for 2.0 seconds, the ratio of the rock's speed to the stone's speed is a)1:1 b)2:1 c)1:2 d)4:1

- $500 Motion - $500 The graph represents the linear motion of a car. The average velocity of the car during interval DE is a)0 m/s b)10. m/s c)20. m/s d)40. m/s

Forces - $100 Which statement explains why a book resting on a table is in equilibrium? a) There is a net force acting downward on the book. b) The weight of the book equals the weight of the table. c) The acceleration due to gravity is 9.8 m/s2 for both the book and the table. d) The weight of the book and the table's upward force on the book are equal in magnitude, but opposite in direction.

Forces - $200 Which is the most likely mass of a high school student? a) 1 kg b) 5 kg c) 60 kg d) 250 kg

Forces - $300 Four forces are acting on an object as shown in the diagram. If the object is moving with a constant velocity, the magnitude of force F must be a)0 N b)10 N c)30 N d)40 N

Forces - $400 In the diagram, surface B of the wooden block has the same texture as surface A, but twice the area of surface A. If force F is required to slide the block at constant speed across the table on surface A, approximately what force is required to slide the block at constant speed across the table on surface B? a)4 F b)2 F c)F d)½ F

Forces - $500 A 2,400-kilogram car is traveling at a speed of 20. meters per second. Compared to the magnitude of the force required to stop the car in 12 seconds, the magnitude of the force required to stop the car in 6.0 seconds is a) half as great b) twice as great c) the same d) four times as great

Energy and Power - $100 A 10-kilogram cart moving with a energy of 5 J is brought to a stop in 2 seconds. What was the magnitude of the power used to stop the cart? a)0 watts b)2.5 watts c)5 watts d)25 watts

Energy and Power - $200 A 60 kg student running at 3.0 m/s has a kinetic energy of: a)180 J b)270 J c)540 J d)8100 J

Energy and Power - $300 If a 5 Kg Object is raised 2 meters from the surface in 10 s, its gain in potential energy is: a)0 J b)10 J c)20 J d)100 J

Energy and Power - $400 The diagram below which represents a 3.0-kilogram mass being moved at a constant speed by a force of 6.0 newtons.The magnitude of the work done on the mass is: a: 54 Jb: 24 J c: 18 Jd: 180 J

Energy and Power - $500 In the diagram, 55 joules of work is needed to raise a 10 N weight 5.0 meters in 5 s. How much work is need to overcome friction? a: 1 J b: 5 J c: 50 J d: 55 J 5 m F 10 N

Gravity and Graphs- $100 b Vector, Newtons Gravity is a Force (Vector) and uses Newtons for a Unit

Gravity and Graphs - $200 B. 2 m/s v = d / t v = 8 m / 4s v = 2m/s

Gravity and Graphs - $300 B: Twice as great Using the Gravitational formula Mass is directly proportional to the Gravitational force between the Objects

Gravity and Graphs - $400 B: N F = ma = 17 kg 8.8 m/s2 = N

Gravity and Graphs - $500 If the mass of A increases by a factor of 3, the force F also increases by a factor of 3. If the mass of B is halved, the force F is also halved. Increases by a factor of 3/2. Mass AMass B Mass A 3X Mass B 1/2 3m

- $100 Momentum and Acceleration - $100 C: C: 20,000 kg-m/s P = mv = 1000Kg ( 20 m/s) = 1000Kg ( 20 m/s) = 20,000 kg-m/s = 20,000 kg-m/s

- $200 Momentum and Acceleration - $200 c: 3.0 m/s 2 a =  v /  t a = 60 m/s – 45 m/s / 5.0 s a = 15 m/s / 5.0 s a = 3.0 m/s 2

- $300 Momentum and Acceleration - $300 B: 75 N F = ma = ( 0.60 kg)(125 m/s2) = 75 N

- $400 Momentum and Acceleration - $400 b: 14.2 m/s V f 2 = V i 2 + 2ad = ( 8m/s ) ( 3m/s 2 ) ( 23m) = 64 m 2 /s m 2 /s 2 V f 2 = 202 m 2 /s 2 V f = 14.2 m/s

- $500 Momentum and Acceleration - $500 d: 4 m/s P before = P after m 1 v 1 + m 2 v 2 = m 1 v 1 / + m 2 v 2 / 20kg (6 m/s)- 30kg (v 2 ) = kg (v 2 ) = -120 kg-m/s (v 2 ) = 4 m/s

- $100 Motion - $100 b: 10 m/s v = d/t v = 100 m / 10.0 s v = 10 m/s

- $200 Motion - $200 c: 6.0 m/s 2 a =  v / t a = (50 m/s – 20 m/s) / 5.0 s a = 30 m/s / 5.0 s m/s 2 a = 6.0 m/s 2

- $300 Motion - $300 d: D to E On a distance – time graph, a curve line is changing speed ( acceleration) ( acceleration)

- $400 Motion - $400 a: 1:1 All Objects fall at the same rate!

- $500 Motion - $500 c: 20 m/s  n a Velocity time graph, the average velocity is mathematical average of the two points D and E. v = 20 m/s + 20 m/s /2

- $100 Forces - $100 c: 60 kg 1kg = 2.2 pounds 60 kg = 132 pounds

- $200 Forces - $200 d: d: The weight of the book and the table's upward force on the book are equal in magnitude, but opposite in direction. For every action there is an equal and opposite reaction, Newton’s 3 rd Law

- $300 Forces - $300 C: 40 N If an object is moving at a constant velocity, then forces must be equal and opposite.

- $400 Forces - $400 c: F If the surface area doubles (B), but the force is ½ because of the weight distribution, then the friction will not change!

$500 Forces $500 b : twice as great J = F (t) 2400 N-s = F (12 m/s) 2400 N-s = 2F (6 m/s)

Energy and Power - $100 B: 2.5 watts P = W / t = 5 J / 2s =2.5 watts

Energy and Power - $200 b: 270 J Ke = ½ mv 2 = ½ 60 kg (3.0 m/s) 2 = ½ 60 kg (3.0 m/s) 2 = 30 kg (9 m 2 /s 2 ) = 30 kg (9 m 2 /s 2 ) = 270 J = 270 J

Energy and Power - $300 d: 100 J Pe = mgh = (5 kg) (10 m/s 2 ) (2 m) = 100 J

Energy and Power - $400 b: 24 J b: 24 J W = F x D = 6 N ( 4 m) = 6 N ( 4 m) = 24 J = 24 J

Energy and Power - $500 b: 5 J W = F x d W = 10 N (5.0 m) = 50 J, If the total work = 55 J, therefore 5 J to overcome friction

FINAL CATEGORY: Momentum Place you Bet now

FINAL CATEGORY A Cart has a mass M on a frictionless track starts from rest at the top of the hill having a height h 1, Express the kinetic energy when it reaches the top of the next hill, having h 2 ? (in terms of M, g, h 1, h 2, or h 3 )

Answer: Ke (h 2 ) = mg (h 1 - h 2 ) The difference in height will divide the total energy Ke max = ½ mv 2 = mgh 1 FINAL CATEGORY $

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