Wind Energy Conversion Systems April 21-22, 2003 K Sudhakar Centre for Aerospace Systems Design & Engineering Department of Aerospace Engineering
Horizontal Axis WECS Energy extraction at a plane normal to wind stream. Rotor plane - a disc
Aerodynamics of Wind Turbines Aerodynamics Forces and Moments on a body in relative motion with respect to air Topics of intense study aerospace vehicles, road vehicles, civil structures, wind turbines, etc.
Atmosphere International Standard Atmosphere –Sea level pressure = Pa –Sea level temperature= K (IRA ) –Sea level density= kg/m^3 (IRA 1.164) –dt/dh= K/m –p/p SL = (t/t SL ) Planetary boundary layer extends to 2000m V(50 m) / V(20 m) = 1.3 city = 1.2 grassy = 1.1 smooth
Bernoulli Equation p V 2 = constant Incompressible flows; along a streamline,.. A 1, V 1 A 2, V 2 Internal flows: Conservation of mass; A V = constant If is constant, A 1 V 1 = A 2 V 2
Actuator Disc Theory A V p A d V d A 1 V 1 p pd-pd- pd+pd+ A V = A d V d =A 1 V 1 ; mass flow rate, m = A d V d P = 0.5 m (V 2 - V 1 2 ) = 0.5 A d V d (V 2 - V 1 2 ) T = m (V - V 1 ) = A d V d (V - V 1 ) = A d ( p d - - p d + ) p d - - p d + = V d (V - V 1 )
Actuator Disc Theory A V p A d V d A 1 V 1 p pd-pd- pd+pd+ p V 2 = p d V d 2 p V 1 2 = p d V d 2 p d - - p d + = 0.5 (V 2 - V 1 2 ) = V d (V - V 1 ) V d = 0.5 (V + V 1 ) ; V d = V ( 1 - a); V 1 = V ( a) P = 0.5 A d V d (V 2 - V 1 2 ) = 0.5 A d V d 2 V d (V - V 1 ) = A d V d 2 (V - V 1 ) = A d V 2 (1 - a) 2 2aV = 2 A d V 3 a (1 - a) 2
Actuator Disc Theory P = 2 A d V 3 a (1 - a) 2 Non-dimensional quantities, C P = P / (0.5 A d V 3 ) ; C Q = Q/ (0.5 A d R V 2 ) C T = T/ (0.5 A d V 2 ) ; = r / V C P = 4 a (1 - a) 2 ; C T = 4 a (1 - a) dC P /da = 0 a = 1/3 C P-max = 16/27 ; C C P-max = 8/9 a = 1/3 C T-max = 1 ; C C T-max = 1/2 a = 1/2
Rotor & Blades Energy extraction through cranking of a rotor Cranking torque supplied by air steam Forces / moments applied by air stream? Blade element theory of rotors?
Aerodynamics Aerodynamics - Forces and Moments on a body in relative motion with respect to air VV F M PoPo * P 1
Forces & Moments Basic Mechanisms –Force due to normal pressure, p = - p ds n –Force due to tangential stress, = ds ( n = 0) u y VV ds n r MRP
Drag & Lift D - Drag is along V L - Lift is the force in the harnessed direction How to maximise L/D VV drag
Drag For steam lined shapes D f >> D P For bluff bodies D P >> D f Pressure drag, D P Skin friction drag, D f
Streamlining! Equal Drag Bodies 1 mm dia wire Airfoil of chord 150 mm
Wind Turbine Typical Vertical Axis WECS - Rotor with n-blades Cranked by airflow. Cranking torque? Tower loads VV ,Q r
Wind Turbine Rotor How to compute Q = Torque, T = Tower load VV drag Lift
Why non-dimensional Coefficients With dimensional values –At each ( , , , V , a, c) measure L, D, M –Many tests required With non-dimensional coefficients –At desired Re, M, and V –for each measure L, D, M –Convert to C L, C D, C M –At any other and V compute L, D M
Airfoil Characteristics h t VV C Camber line h(x) 0 camber symmetric airfoil (h/c)max and (h/C)max (t/c)max and (t/c)max Leading edge radius
Airfoil Characteristics C L = dC L /d = 2 rad -1 = 0.11 deg -1 C Lo = f (h/c) max i = f(h/c) max C M = constant = f(h/c) max CLCL CDCD CMCM Moment Ref Pt = 0.25 c 13 o ii stall Special airfoils for wind turbines with high low Re SERI / NREL
Cranking Torque? Air cranks rotor equal, opposite reaction on air Rotor angular velocity, Torque on rotor Q , Q Angular velocity of air downstream of rotor, = 2a’ Angular velocity at rotor mid-plane, 0.5 = a’ a’- circumferential inflow
Cranking Torque? = 2a’ , Q r dr
Flow velocities VV a V r r a’ W = - C L, C D = f ( ) CLCL CDCD C x = C L Sin - C D Cos = C L Sin ( 1 - Cot ) C T = C L Cos +C D Sin = C L Cos ( 1+ Tan )
CPCP 16/27 Betz C pi - Energy extraction is through cranking