Review SYNTHETIC DIVISION to find roots of third degree characteristic polynomial Pamela Leutwyler.

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Presentation transcript:

Review SYNTHETIC DIVISION to find roots of third degree characteristic polynomial Pamela Leutwyler

(2x – 5)(x + 3)(7x – 2) =

14x 3 + 3x 2 – 107x + 30 = 0

(2x – 5)(x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3

(2x – 5)(1x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3

(2x – 5)(1x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3

(2x – 5)(1x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3 If is a root of the polynomial equation

(2x – 5)(1x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3 If is a root of the polynomial equation Then q is a factor of

(2x – 5)(1x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3 If is a root of the polynomial equation Then q is a factor of 14 and p is a factor of

A characteristic polynomial will always have lead coefficient = 1. Rational eigenvalues will be integral factors of the constant coefficient of the characteristic polynomial. example: find the eigenvalues for the matrix potential rational roots are factors of , -1, +2, -2, +7, -7, +14, -14

potential rational roots are factors of , -1, +2, -2, +7, -7, +14, -14 Test the potrats using synthetic division: 

potential rational roots are factors of , -1, +2, -2, +7, -7, +14, -14 Test the potrats using synthetic division: +1  The remainder is NOT ZERO. +1 is not a root.

potential rational roots are factors of , -1, +2, -2, +7, -7, +14, -14 Test the potrats using synthetic division: +7  The remainder is ZERO. +7 is a root.

potential rational roots are factors of , -1, +2, -2, +7, -7, +14, -14 Test the potrats using synthetic division: +7  The remainder is ZERO. +7 is a root. factor this or use quadratic formula or continue with synthetic division to get the other roots.