Review SYNTHETIC DIVISION to find roots of third degree characteristic polynomial Pamela Leutwyler
(2x – 5)(x + 3)(7x – 2) =
14x 3 + 3x 2 – 107x + 30 = 0
(2x – 5)(x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3
(2x – 5)(1x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3
(2x – 5)(1x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3
(2x – 5)(1x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3 If is a root of the polynomial equation
(2x – 5)(1x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3 If is a root of the polynomial equation Then q is a factor of
(2x – 5)(1x + 3)(7x – 2) = 14x 3 + 3x 2 – 107x + 30 = 0 The roots are: -3 If is a root of the polynomial equation Then q is a factor of 14 and p is a factor of
A characteristic polynomial will always have lead coefficient = 1. Rational eigenvalues will be integral factors of the constant coefficient of the characteristic polynomial. example: find the eigenvalues for the matrix potential rational roots are factors of , -1, +2, -2, +7, -7, +14, -14
potential rational roots are factors of , -1, +2, -2, +7, -7, +14, -14 Test the potrats using synthetic division:
potential rational roots are factors of , -1, +2, -2, +7, -7, +14, -14 Test the potrats using synthetic division: +1 The remainder is NOT ZERO. +1 is not a root.
potential rational roots are factors of , -1, +2, -2, +7, -7, +14, -14 Test the potrats using synthetic division: +7 The remainder is ZERO. +7 is a root.
potential rational roots are factors of , -1, +2, -2, +7, -7, +14, -14 Test the potrats using synthetic division: +7 The remainder is ZERO. +7 is a root. factor this or use quadratic formula or continue with synthetic division to get the other roots.