Stoichiometry

Stoichiometry Stoy – key – ohm – e - tree

9.1 Introduction to Stoichiometry 1. Define Stoichiometry. 2. Describe the importance of the mole ratio in stoichiometric calculations. 3. Write a mole ratio relating two substances in a chemical equation. 4. Calculate the amount in moles of a reactant or product from the amount in moles of a different reactant or product.

Obj 1: What is Stoichiometry? Stoichiometry means Stoicheio = element Metron = measure Stoichiometry is the quantitative study of chemical reactions using balanced equations.

Obj 2: Mole Ratio Mole Ratios come from the coefficients in a balanced equation. Mole Ratios are used to convert moles of one substance (X) into moles of another substance (Y).

Obj 3: Mole Ratios from Balanced Equations 1 N2 + 3 H2  2 NH3 The Possible Mole Ratios are:

Obj 3: Mole Ratios from Balanced Equations 1 N2 + 3 H2  2 NH3 The Possible Mole Ratios are: 1 mol N2 1 mol N2 3 mol H2 3 mol H2 2 mol NH3 2 mol NH3

Obj 3: Mole Ratios from Balanced Equations 1 N2 + 3 H2  2 NH3 Other Possible Mole Ratios: 1 mol N2 1 mol N2 3 mol H2 3 mol H2 2 mol NH3 2 mol NH3 3 mol H2 2 mol NH3 2 mol NH3 1 mol N2 1 mol N2 3 mol H2

Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3 7.5 mol N2 ? mol H2 ? mol NH3

Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3 7.5 mol N2 ? mol H2 ? mol NH3 7.5 mol N2 (3 mol H2 ) = ? (1 mol N2 )

Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3 7.5 mol N2 ? mol H2 ? mol NH3 7.5 mol N2 (3 mol H2 ) = 22.5 mol H2 (1 mol N2 )

Using a Mole Ratio 1 N2 + 3 H2  2 NH3 7.5 mol N2 22.5 mol H2 ? mol NH3 7.5 mol N2 (2 mol NH3) = ? (1 mol N2 )

Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3 7.5 mol N2 22.5 mol H2 ? mol NH3 7.5 mol N2 (2 mol NH3) = 15.0 mol NH3 (1 mol N2 )

Obj 4: Cookie Stiochiometry One Batch: 1 N2 + 3 H2  2 NH3 Double Batch: _ N2 + _ H2  _ NH3

Obj 4: Cookie Stiochiometry One Batch: 1 N2 + 3 H2  2 NH3 Double Batch: 2 N2 + 6 H2  4 NH3

Obj 4: Cookie Stiochiometry One Batch: 1 N2 + 3 H2  2 NH3 Double Batch: 2 N2 + 6 H2  4 NH3 Triple Batch: _ N2 + _ H2  _ NH3

Obj 4: Cookie Stiochiometry One Batch: 1 N2 + 3 H2  2 NH3 Double Batch: 2 N2 + 6 H2  4 NH3 Triple Batch: 3 N2 + 9 H2  6 NH3

Obj 4: Cookie Stiochiometry One Batch: 1 N2 + 3 H2  2 NH3 Double Batch: 2 N2 + 6 H2  4 NH3 Triple Batch: 3 N2 + 9 H2  6 NH3 Half Batch: _ N2 + _ H2  _ NH3

Obj 4: Cookie Stiochiometry One Batch: 1 N2 + 3 H2  2 NH3 Double Batch: 2 N2 + 6 H2  4 NH3 Triple Batch: 3 N2 + 9 H2  6 NH3 Half Batch: 0.5 N2 + 1.5 H2  1 NH3

Lets Look at Our Problem Again We want 7.5 batch ! 1 N2 + 3 H2  2 NH3 __ mol N2 ___ mol H2 __ mol NH3

Lets Look at Our Problem Again We want 7.5 batch ! 1 N2 + 3 H2  2 NH3 7.5 mol N2 22.5 mol H2 15.0 mol NH3

The End The Final Curtain