Writing Equations of Lines Exit Ticket
1) Write the equation of a line parallel to y=2x+9 that passes through (4,7). First find the slope!!!! The slope given is 2. Since the equation must be parallel the slope used must be 2.
1) Write the equation of a line parallel to y=2x+9 that passes through (4,7). Therefore m=2 and the point (4,7) are x and y respectively. Substitute y, m, and x in y=mx+b. 7=2(4)+b (Note that the letter b stays in the equation. 9 is not used.) Use this to find the new b!
1) Write the equation of a line parallel to y=2x+9 that passes through (4,7). Use this to find the new b! 7=2(4)+b (Note that the letter b stays in the equation. 9 is not used.) 7 = 8+b -8 -8 -1= b
1) Write the equation of a line parallel to y=2x+9 that passes through (4,7). What is our new b??? b=-1
b=-1 So our equation is… y= 2x+ -1 1) Write the equation of a line parallel to y=2x+9 that passes through (4,7). b=-1 So our equation is… y= 2x+ -1 m b
m= - ¼ perpendicular m= + 4 2) Write an equation that is perpendicular to y= -1/4 x+1 and goes through ( 4,2). First find the slope!!!! The given slope is -1/4. What is the perpendicular slope?????? m= - ¼ perpendicular m= + 4
With m= 4 and the point (4,2) we can write the equation. 2) Write an equation that is perpendicular to y= -1/4 x+1 and goes through ( 4,2). With m= 4 and the point (4,2) we can write the equation. Write the formula y=mx+b. Then substitute y, m, and x and then solve for the new b.
With m= 4 and the point (4,2) we can write the equation. 2) Write an equation that is perpendicular to y= -1/4 x+1 and goes through ( 4,2). With m= 4 and the point (4,2) we can write the equation. Then substitute y, m, and x and then solve for the new b. y=mx+b 2=4(4)+b
2) Write an equation that is perpendicular to y= -1/4 x+1 and goes through ( 4,2). y=mx+b 2=4(4)+b 2 = 16+b - 16 -16 14=b
B=4 So our equation is… y= 4x+ -14 2) Write an equation that is perpendicular to y= -1/4 x+1 and goes through ( 4,2). B=4 So our equation is… y= 4x+ -14 m b