Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) NGSSS Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem.

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Presentation transcript:

Splash Screen

Lesson Menu Five-Minute Check (over Chapter 7) NGSSS Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1 Example 2:Identify Similar Right Triangles Theorems: Right Triangle Geometric Mean Theorems Example 3:Use Geometric Mean with Right Triangles Example 4:Real-World Example: Indirect Measurement

Over Chapter 7 A.A B.B C.C D.D 5-Minute Check 1 Solve the proportion A.15 B.16.5 C. D.18

Over Chapter 7 A.A B.B C.C D.D 5-Minute Check 2 A.x = 16.1, y = 1.6 B.x = 15.6, y = 2.1 C.x = 7.8, y = 8.4 D.x = 17.6, y = 3.7 The triangles at the right are similar. Find x and y.

Over Chapter 7 A.A B.B C.C D.D 5-Minute Check 3 A.yes, ΔABC ~ ΔEDF B.yes, ΔABC ~ ΔDEF C.yes, ΔABC ~ ΔEFD D.No, sides are not proportional. Determine whether the triangles are similar. If so, write a similarity statement.

Over Chapter 7 A.A B.B C.C D.D 5-Minute Check 4 A B.64.5 C.12.4 D.10.6 Find the perimeter of DEF if ΔABC ~ ΔDEF, AB = 6.3, DE = 15.75, and the perimeter of ABC is 26.5.

Over Chapter 7 A.A B.B C.C D.D 5-Minute Check 5 A.28 units B.54 units C.58 units D.112 units Figure JKLM has a perimeter of 56 units. After a dilation with a scale factor of 2, what will the perimeter of the figure J'K'L'M' be?

NGSSS MA.912.G.4.5 Apply theorems involving segments divided proportionally. MA.912.G.5.2 State and apply the relationships that exist when the altitude is drawn to the hypotenuse of a right triangle. Also addresses MA.912.G.4.4, MA.912.G.4.6, and MA.912.G.5.4.

Then/Now You used proportional relationships of corresponding angle bisectors, altitudes, and medians of similar triangles. (Lesson 7–5) Find the geometric mean between two numbers. Solve problems involving relationships between parts of a right triangle and the altitude to its hypotenuse.

Vocabulary geometric mean

Concept

Example 1 Geometric Mean Find the geometric mean between 2 and 50. Answer: The geometric mean is 10. Definition of geometric mean Let x represent the geometric mean. Cross products Take the positive square root of each side. Simplify.

A.A B.B C.C D.D Example 1 A.3.9 B.6 C.7.5 D.4.5 A. Find the geometric mean between 3 and 12.

Concept

Example 2 Identify Similar Right Triangles Write a similarity statement identifying the three similar triangles in the figure. Separate the triangles into two triangles along the altitude.

Example 2 Identify Similar Right Triangles Then sketch the three triangles, reorienting the smaller ones so that their corresponding angles and sides are in the same position as the original triangle. Answer: So, by Theorem 8.1, ΔEGF ~ ΔFGH ~ ΔEFH.

A.A B.B C.C D.D Example 2 A.ΔLNM ~ ΔMLO ~ ΔNMO B.ΔNML ~ ΔLOM ~ ΔMNO C.ΔLMN ~ ΔLOM ~ ΔMON D.ΔLMN ~ ΔLMO ~ ΔMNO Write a similarity statement identifying the three similar triangles in the figure.

Concept

Example 3 Use Geometric Mean with Right Triangles Find c, d, and e.

Example 3 Use Geometric Mean with Right Triangles Since e is the measure of the altitude drawn to the hypotenuse of right ΔJKL, e is the geometric mean of the lengths of the two segments that make up the hypotenuse, JM and ML. Geometric Mean (Altitude) Theorem Substitution Simplify.

Example 3 Use Geometric Mean with Right Triangles Geometric Mean (Leg) Theorem Substitution Use a calculator to simplify. Since d is the measure of leg JK, d is the geometric mean of JM, the measure of the segment adjacent to this leg, and the measure of the hypotenuse JL.

Example 3 Use Geometric Mean with Right Triangles Geometric Mean (Leg) Theorem Substitution Use a calculator to simplify. Answer: e = 12, d ≈ 13.4, c ≈ 26.8 Since c is the measure of leg KL, c is the geometric mean of ML, the measure of the segment adjacent to KL, and the measure of the hypotenuse JL.

A.A B.B C.C D.D Example 3 A.13.9 B.24 C.17.9 D.11.3 Find e to the nearest tenth.

Example 4 Indirect Measurement KITES Ms. Alspach is constructing a kite for her son. She has to arrange two support rods so that they are perpendicular. The shorter rod is 27 inches long. If she has to place the short rod 7.25 inches from one end of the long rod in order to form two right triangles with the kite fabric, what is the length of the long rod?

Example 4 Indirect Measurement Draw a diagram of one of the right triangles formed. Let be the altitude drawn from the right angle of ΔWYZ.

Example 4 Indirect Measurement Answer: The length of the long rod is , or about inches long. Geometric Mean (Altitude) Theorem Substitution Square each side. Divide each side by 7.25.

A.A B.B C.C D.D Example 4 A.68.3 ft B ft C ft D ft AIRPLANES A jetliner has a wingspan, BD, of 211 feet. The segment drawn from the front of the plane to the tail, at point E. If AE is 163 feet, what is the length of the aircraft to the nearest tenth of a foot?

End of the Lesson