Week 15 – Units, Perimeter, & Area Warm up: 1.) Señora Molly Kuehl is visiting Mexico and wants to exchange $180 for pesos. The rate of currency exchange.

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Presentation transcript:

Week 15 – Units, Perimeter, & Area Warm up: 1.) Señora Molly Kuehl is visiting Mexico and wants to exchange $180 for pesos. The rate of currency exchange is pesos per U.S. dollar. How many pesos will she receive? 2.) Señora Chapman enjoyed her vacation in Mexico, but she misses her Algebra 1 class, so she must return. She has exactly 200 pesos left. How many U.S. dollars will she receive? The rate of currency exchange is now pesos per dollar. 180 dollars x 1 dollar = pesos 200 pesos x pesos ≈ $ pesos 1 dollar

Convert the following measures: 1.) 12 fluid ounces to cups (1 cup = 8 fl. oz.) 2.) length of a football field (100 yd, no endzones) to inches (3ft = 1 yd or 36 in. = 1 yd.) 3.) 85 cm to meters (100 cm = 1 m) 4.) 60 inches to ft (12 in = 1 ft) 12 fluid oz x 8 fluid oz = 1.5 cups 100 yd x 1 yd1 ft = 3600 inches100 yd x 1 yd = 3600 inches 85 cm x 100 cm = 0.85 m 60 in x 12 in = 5 ft 1 cup 3 ftx 12 in36 in 1 m 1 ft

Perimeter 1.) Find the perimeter of each rectangle with the given base and height. P = ___________ a. 21 in, 7 in b. 4 ft, 4 in. 2b + 2h 21 in 7 in P = 2(21in) + 2(7in) P = 42 in + 14 in P = 56 in 4 ft 4 in 4 ft x 1 ft = 48 in P = 2(48in) + 2(4in) P = 96 in + 8 in P = 104 in 4 in x 12 in = ft P = 2( ft) + 2(4 ft) P = ft + 8 ft P = ft 12 in 1 ft

c.30 in., 4 yd. d. You are designing a banner for the front of the new Math Museum. The banner will be 4 ft wide and 7 yd high. Find the perimeter. Math Rules!! 30 in x 36 in P = 2( yd) + 2(4yd) P = + 8yd = + 8 yd P = yd 4 yd x 1 yd = 144 in P = 2(144in) + 2(30in) P = 288 in + 60 in P = 348 in = yd 4 ft x 3 ft P = 2( ) + 2(7yd) P = yd + 14yd = + 14 yd P = yd 7 yd x 1 yd = 21 ft P = 2(21 ft) + 2(4ft) P = 42 ft + 8 ft P = 50 ft = yd 4 ft 4 yd 7 yd 30 in 1 yd 36 in 1 yd 3 ft

Area 2.) Find the area of each rectangle with the given base and height. A = ________ a. 40 cm, 2 m b. 9 ft., 40 in. bh 40 cm x 100 cm = 0.4 m A = 2m(0.4m) A = 0.8 m 2 2 m x 1 m = 200 cm A = 200cm(40cm) A = 8000 cm 2 9 ft x 1 ft = 108 in A = 108in (40in) A = 4320 in 2 40 in x 12 in = ft A = ft(9ft) A = 30 ft 2 40 cm 2 m 40 in 9 ft 1 m 100 cm 12 in 1 ft

c.Find the area of a driveway that is 20 ft wide and 100 yd long. 100 yd x 1 yd A = 300ft(20ft) A = 6000 ft 2 20 ft x 3 ft = yd A = yd(100yd) A = yd yd 20 ft = 300 ft 3 ft 1 yd