Pressure Contents: How to calculate Whiteboards Gauge pressure Whiteboards.

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Pressure Contents: How to calculate Whiteboards Gauge pressure Whiteboards

Pressure is in Force per unit area TOC F = Force in N A = Area in m 2 P = pressure in N/m 2 (Pascals - Pa) Demo - 1 m 2 In a fluid– Same in all directions, perp to walls. Example - a 2.4 kg box measures 15 cm by 25 cm on the base. What is the pressure under the box? F = mg A = LxW

Pressure 11 | 2 | 323

A = (.20 m)(.32 m) =.064 m 2 P = F/A = (42 N)/(.064 m 2 ) 660 Pa What is the pressure of 42 N on a 20. cm x 32 cm plate?

A = LxW A = (.780 m)(1.82 m) = m 2 P = F/A, F = PA = (3200 Pa)( m 2 ) 4540 N What force does 3200 Pa exert on a 78.0 cm x 182 cm pane of glass?

Find area A =  r 2 for a circle Diameter = 2r P = F/A, A = F/P = (31360 N)/(1.38 x 10 6 Pa) A = m 2 A =  r 2 r = m d = 2r.170 m A hydraulic jack lifts a N car using a pressure of 1.38 MPa (M = x 10 6 ) What is the diameter of the cylinder?

Converting units of pressure 1 atm = 1.013x10 5 Pa = kPa = 760. torr = 14.7 PSI Convert 2.10 atm to Pa: (2.13x10 5 Pa) Convert 345 torr to Pa: (4.60x10 4 Pa) Convert 2.45x10 4 Pa to PSI: (3.56 PSI)

Conversions 11 | 2 | 323

solution answer Convert to

solution answer Convert to

solution answer Convert to

Gauge pressure Most pressure gauges compare to Atmospheric (i.e. this room is at 0 Gauge) Absolute p is 1 atm more P = P gauge + P A 1 atm = x 10 5 Pa = kPa = 760 Torr = 14.7 psi Demo - Magdeberg Hemispheres Example – What is the absolute pressure (In Torr and Pa) if you have a gauge pressure of 312 Torr? = 1072 Torr absolute (1.013 x10 5 Pa/atm)(1072 Torr)/(760 Torr/atm) = 1.43E5 Pa

Gauge Pressure 11 | 22

P = P gauge + 1 atm P = 35 psi psi = 49.7 psi 1.013E5*49.7/14.7 = 3.42E5 Pa 49.7 psi, 3.42E5 Pa What is the absolute pressure if you read 35 psi gauge? Answer in psi (1 atm = 14.7 psi) and Pascals

P = P gauge + 1 atm 812 = P gauge Torr P gauge = 52 Torr 52 Torr If you have an absolute pressure of 812 Torr, what is the gauge pressure? Answer in Torr (1 atm = 760 Torr)

P = P gauge + 1 atm P = 2.17 x 10 5 Pa x 10 5 Pa 3.18 x 10 5 Pa What is the absolute pressure if the gauge pressure is 2.17 x 10 5 Pa (1 atm = x 10 5 Pa = kPa)

P = P gauge + 1 atm 42.0 kPa = p gauge kPa kPa If you have an absolute pressure of 42.0 kPa, what is the gauge pressure in kPa? (1 atm = x 10 5 Pa = kPa)