3/11/2013 Standards: 6 (Solutions) Objectives: ● Students will be able to calculate problems involving Molarity (M) and molality (m) DO NOW: 1. Calculate M (molarity) of a solution with 4.7 L of solution in which there are 2.2 mol of NaClO4 HOMEWORK: 1. Ch 15.2 PP's p and Ch 15 Assess. p (a, b, & c) 5 pts (Std 6) 2. Two PRINTS (see website) 3. HANDOUTS TODAY - Tutorial Ch What Are Solutions, Ch Molarity - Molality - Colligative Properties Std 6 =========================================================== STAMPS: ● Journal 3/8 1. App A, p (1 pt) Std 6 2. Ch 15.2 p PP's (4 pts) Std 6

Units of measure in Henry's Law S (solubility) g/L g/mL mol/L mol/mL (or any unit of volume besides L or mL) P (pressure) atm, mmHg, Torr, kPa, Pa, psi (any unit of pressure is OK)

ctfolder/ flashfiles/thermochem/solutionSalt.html SOLVATION ANIMATION 1. agitation 2. increase surface area 3. temperature Demo -see videomade in classyesterdayDemo -see videomade in classyesterday

Units of measure in Henry's Law S (solubility) g/L g/mL mol/L mol/mL (or any unit of volume besides L or mL) P (pressure) atm, mmHg, Torr, kPa, Pa, psi (any unit of pressure is OK)

M Molarity

M = mol L molarity solute solution

Calculate the molarity of a solution having 15.0 g NaCl in 2.80 L of water (volume of solution is still 2.80 L). Molar mass Cl = 35.5 Molar mass Na = 23.0 In your answer, use 3 sig. figs and do not use any units of measure. NUMBER ONLY 1

m = (milli-) = How to derive equality with prefixes What is 1 mL equal to in terms of L ? mL = L x x mL = L x x 1000 mL = 1 L mL = L

k = (kilo-) = kg = 1000 g How to derive equality with prefixes What is 1 kg equal to in terms of g ?

Summary Is it 1000 kg = 1 g or 1000 g = 1 kg ? prefix letter x its mass unit (or volume) 1 kg = 1000 g mL = L 1 mg = g kL = 1000 L prefix value x its mass unit Make -- = PREFIXES

1 kg = 1000 g 1 mL = L Everything in blue will be a fraction. Everything in green will be a fraction.

prefixes.htm Big Bigger

M Molarity

2What is the value of S if 25.0 g of gas is dissolved in 1.00 L of water? Number only 3 sig figs only no units of measure

3What is the solubility of a gas if 25.0 g of the gas will dissolve in 1.00 L of water. Number only 3 sig figs only no units of measure

p. 463 possible solutes: a. salt (NaCl) b. sugar (sucrose) c. MgCl 2 d. C (smaller portion of steel) e. paint pigments possible solvents: f. water g. iron (Fe major portion of steel) h. laquer thinner `

3/13/2013 Standards: 6 (Solutions) (same as yesterday) Objectives: ● Practice Calculations of molarity and mass percent DO NOW: 1. Ch 15 Assess - p and 77 (all) & 78 (all) will be stamped as a 5 pt HW stamp for Th. (5 pts) Std 6 HOMEWORK: None =========================================================== STAMPS: ● Journal 3/11 1. Ch 15.2 PP's p and Ch 15 Assess. p (a, b, & c) 5 pts (Std 6) AT YOUR DESK: 1. Two PRINTS (see website) (Bigger - Units of Measure, and Mass% & Molarity Lab Sheet) (1 pts) Std 6

For Quiz 3.3 number correct x 2.4 = points earned 60 = total possible

Summary Is it 1000 kg = 1 g or 1000 g = 1 kg ? prefix letter x its mass unit (or volume) 1 kg = 1000 g mL = L 1 mg = g kL = 1000 L prefix value x its mass unit = Make -- PREFIXES

answers: % % % 77. a M (mol/L) b M (mol/L) c M (mol/L) 78.a M mol b mol c mol

3/13/2013 Standards: 6 (Solutions) (same as yesterday) Objectives: ● Practice Calculations of molarity and mass percent DO NOW: 1. Ch 15 Assess - p and 77 (all) & 78 (all) will be stamped as a 5 pt HW stamp for Th. (5 pts) Std 6 HOMEWORK: None =========================================================== STAMPS: ● Journal 3/11 1. Ch 15.2 PP's p and Ch 15 Assess. p (a, b, & c) 5 pts (Std 6) AT YOUR DESK: 1. Two PRINTS (see website) (Bigger - Units of Measure, and Mass% & Molarity Lab Sheet) (1 pts) Std 6

3/14/2013 Standards: 6 (Solutions) Objectives: ● Students will be able to calculate boiling point INcreases, and freezing point DEcreases. ● Demonstrate conducive solutions. Students will be able to recognize compounds that ionize (make 2 or more particles, salts, acids & bases) as different from those who don't ionize (sugar). DO NOW: 1. Name 3 kinds of substances ionize in water, and give one example of each? HOMEWORK: 1. Ch 15 Assess p (a,b,c), Ch 15.4 p , 34, Ch 15 Assess p (a,b,c) (5 pts ) Std 6 (total problems = 8) =========================================================== STAMPS: ● Journal 3/13 (for periods 1,3,5) or 3/14 (for periods 2,6) 1. Ch 15 Assess - p and 77 (all) & 78 (all) will be stamped as a 5 pt HW stamp for Th. (5 pts) Std 6 period 2 was in assemb ly, which I photogr aphed. It was on driving safely. Answers: 78 a = mol; b = mol ; c = mol 79 a = g; b = 34.6 g; c = 5.91 g 87 a = fp = 10.2 deg C, bp = deg C b = fp = deg C, bp = 79.1 deg C c = fp = -1.0 deg C, bp = 83.3 deg C

m = molality = mole solute kg solvent M = molarity = mole solute L solution

Boiling & freezing points of water can be changed by dissolving: BP 100°C FP 0°C ionic compounds (salts, acids, bases) non-ionic compounds (like sugar that don't form ions)

p. 474 p. 472 More in the changes shown in charts BIGGERBIGGER particles changes

BP FP 100°C 0°C K b °C/m K f °C/m

p. 474 p. 472 More in the changes shown in charts BIGGERBIGGER particles changes

molaltiy mol (solute) kg (kg solvent) =

molaltiy mol (solute) kg (kg solvent) =

molaltiy mol (solute) kg (kg solvent) =

p. 474 p. 472 More in the changes shown in charts BIGGERBIGGER particles changes

3/15/2013 Standards: 6 (Solutions) Objectives: ● Polish skills learned in this chapter DO NOW: 1. Due end of period (8 points): Directions: All problems require calculations. So, show given, find, and calculations. Each problem is worth one point. p x 10 1 atmp a 71 25% 4 c p (b) mol 5 b 89 fp = deg C bp = deg HOMEWORK: Enjoy your week off and Think about Easter =========================================================== STAMPED: ● Journal 3/14 1. Ch 15 Assess p (a,b,c), Ch 15.4 p , 34, Ch 15 Assess p (a,b,c) (5 pts ) Std 6

3/14/2012 Standards: 6 (Solutions) Objectives: ● Complete data gathering and calculations of your mass% & molarity and turn in to basket before end of the period DO NOW: READ LAB SILENTLY AND try to figure out your procedure. HOMEWORK: Enjoy your week off and Think about Easter =========================================================== TURNED IN TO BASKET: ● Journal NONE TODAY

(for this lab, assume vol of solution = 20.00mL) g = mL (only for water) mass % = g solute g solution x 100 M = (molarity) mol (solute) L (solution)

When you come to me to get your salt, you will need to show me these masses: 1. filter paper 2. graduated cylinder mL beaker All masses must have 3 decimals Examples: 0.l56 g g g

Gp # g NaClg H20g solnMass %M Mass % & Molarity LAB - RESULTS BY GROUP Per 1

Gp # gNaClg H20g solnMass %M Mass % & Molarity LAB - RESULTS BY GROUP Per 2

Gp # gNaClg H20g solnMass %M Mass % & Molarity LAB - RESULTS BY GROUP Per 3

Mass % & Molarity LAB - RESULTS BY GROUP Per 5 Gp # gNaClg H20g solnMass %M

Gp # gNaClg H20g solnMass %M Mass % & Molarity LAB - RESULTS BY GROUP Per 6

Gp # gNaClg H20g solnMass %M Mass % & Molarity LAB - RESULTS BY GROUP Per

Work problems p