Ch. 7 (Section 7.3) Circular Motion

Describing Circular Motion An object undergoes acceleration moving at a constant speed. Explain!

Circular Motion Velocity Recall v = Δd/Δt so in circular motion v= Δr/Δt Velocity vector of object moving in a circle is tangent to the circle

Circular Motion Acceleration Acceleration of object in uniform circular motion ALWAYS points towards middle of circle = centripetal acceleration

Centripetal Acceleration Centripetal acceleration = (velocity)2 divided by the radius of the circle; ac = v2/r ALWAYS points to center or circle! To measure speed: measure the period, time (T) it takes for object to complete one revolution. In one revolution distance = circumference of circle = 2πr so v = 2πr/T If ac = v2/r then ac= (2πr/T)2÷r  4π2r/T2

Centripetal Acceleration Practice A test car moves at a constant speed around a circular track. If the car is 48.2 m from the track’s center and has a centripetal acceleration of 8.05 m/s2, what is the car’s tangential speed? a = v2/r

2. A dog sits 1. 5 m from the center of a merry-go-round 2. A dog sits 1.5 m from the center of a merry-go-round. The merry-go-round is set in motion, and the dog’s tangential speed is 1.5 m/s. what is the dog’s centripetal acceleration? a = v2/r

Centripetal Force Constant force applied causing circular motion Recall 2nd Law: F = ma, if in uniform circular motion a = ac So: Centripetal Force = Fc = mv2/r Fc = m (4π2r/T2) Points to center of circle, same direction as acceleration

Example Problem pg. 165 A 13-g rubber stopper is attached to a 0.93-m string and swung in a circle, making one revolution in 1.18 sec. Find the tension force exerted by the string on the stopper.

Nonexistent Force Imagine you’re riding in a car and it suddenly stops, what happens to you? Is there a force on you? Why/ why not? Imagine riding in a car again, and it makes a sharp left turn, what happens to you? Hence there is NOT an outward “force” on you, it is a fictitious force we call the centrifugal force, explained by Newton’s 1st Law

FUN DEMO

Changing Circular Motion: Torque Point mass: object moving in circular path (ex. rubber stopper swung in circle, person on merry go round etc…) Rigid rotating object: entire mass that rotates around its on axis (ex: a cd, the entire merry go round, a revolving door or ordinary door)

Torque How do you open a door? Should you push next to the hinges? Should you push in, towards the hinges? To open the door most easily, you push at a distance far from the hinges (axis of rotation), and in a direction perpendicular to the door.

Sesaw will balance when magda = mbgdb Torque Distance from the axis of rotation = lever arm The product of the perpendicular force applied AND the lever arm = TORQUE Greater torque = greater change in rotational motion Sesaw will balance when magda = mbgdb

Chapter 8

Newton’s Law of Universal Gravitation Everything pulls on everything else! Greater the mass = greater the force Greater the distance = weaker the force Force = (mass1 x mass2) (distance)2

The Universal Gravitation Constant M m

What is the force of gravity between a 100 kg astronaut and a 50 kg astronaut floating 2 m apart in deep space?

How strong is the gravitational force between Mercury and the sun? Mass (kg) Distance from Sun (km) Sun 1.99x1030 ------- Mercury 3.30x1023 57,895,000

How strong is the gravitational force between Earth and the sun? Mass (kg) Distance from Sun (km) Sun 1.99x1030 ------- Earth 5.97x1024 149,600,000

Calculate the force of gravity on you, at Earth’s Surface 1 pound = ~4.45 Newtons Mass of Earth = 5.97×1024 kg Radius of Earth = 6.38×106 m

Section 8.2: Using the Law of Universal Gravitation

Gravity can be a Centripetal Force Center seeking Any force that is directed at right angels to the path of a moving object that tends to produce circular motion

Centripetal Force Keeps the Moon and Planets Where they Are!

Satellites and Gravity The force of the Earth’s gravity keeps satellites in orbit Satellites have horizontal velocities large enough that their falling distance is equal to the curvature of the Earth 29,000km/hr

What would happen to Earth if… The sun’s gravity increased? The Earth’s inertia decreased? The Earth’s inertia increased? Balance is key for and orbit to happen!

Combining Equations to solve for Orbital speed and Period Recall Fc = mv2/r & F = GMEm/r2 GMEm/r2 = mv2/r getting V by itself:  v = √GME/r Period: T = 2π√r3/GME Both speed, v & period, T are independent of mass

Example Problem Pg. 187 A satellite orbits Earth 225 km above its surgace. What is its speed in orbit and its period? Radius of Earth = 6.36 × 106 m Mass of Earth = 5.97 × 1024 kg G = 6.67 × 10-11 N*m2/kg2

Gravitational Field gravity is always in the direction of the force To find strength of the field you can place a small body of mass (m) in the field and measure the forceon the body g= F/m on Earth’s surface the gravitation field = 9.80 N/kg

Einstein’s Theory of Gravity Einstein proposed that gravity is not a force but an affect of space itself Mass causes space to be curved and other bodies are accelerated because of the way they follow this curved space