Dependent Probability. P(Yellow then Blue) = P (Pink then not blue) = P(Yellow then Yellow) = 3 32 == = 2 8 3 8 1 4 3 8 2 8 2 8 1 4 1 4 0 8 5 8 0 64 1.

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Presentation transcript:

Dependent Probability

P(Yellow then Blue) = P (Pink then not blue) = P(Yellow then Yellow) = 3 32 == = = = With Replacing 0 =

P(Yellow then Blue) = P (Purple then Purple) = P(Yellow then Yellow) = 3 28 == = = = With Out Replacing 0 =

Mary is getting ready to paint her bedroom. Her mother went to the store and purchased samples for her to choose from. Colors# of samples Red shades2 Orange Shades4 Yellow Shades1 Green Shades2 Blue Shades4 Purple Shades3 If she randomly picks a color sample then does not replace it and picks another color sample, then what is the probability of Mary choosing …… A red shade and then a purple shade? A blue shade and then a orange shade? A yellow shade and then a yellow shade? = = 1 40 = = 0 =

P( then ) = == = = = With Out Replacing =

Mary is getting ready to paint her bedroom. Her mother went to the store and purchased samples for her to choose from. Colors# of samples Red shades2 Orange Shades4 Yellow Shades1 Green Shades2 Blue Shades4 Purple Shades3 If she randomly picks a color sample then does not replace it and picks another color sample, then what is the probability of Mary choosing …… A red shade and then a purple shade? A blue shade and then a orange shade? A yellow shade and then a yellow shade? = = = = =