11.3 Powers of Complex Numbers, DeMoivre's Theorem Objective To use De Moivre’s theorem to find powers of complex numbers.

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Presentation transcript:

11.3 Powers of Complex Numbers, DeMoivre's Theorem Objective To use De Moivre’s theorem to find powers of complex numbers.

(r cisθ)³ = (r cisθ)(r cisθ)(r cisθ) Remember: multiply absolute values and add polar angles. = (r² cis 2θ) (r cisθ) = r³ cis 3θ (r cis θ)ⁿ = rⁿ cis nθ

Abraham de Moivre ( ) DeMoivre’s Theorem You can repeat this process raising complex numbers to powers. Abraham DeMoivre did this and proved the following theorem: This says to raise a complex number to a power, raise the modulus to that power and multiply the argument by that power.

This theorem is used to raise complex numbers to powers. It would be a lot of work to find you would need to FOIL and multiply all of these together and simplify powers of i --- UGH! Instead let's convert to polar form and use DeMoivre's Theorem. but in Quad II

Note: In order to use De Moivre’s theorem, the equation must be in polar form.

Solve the following over the set of complex numbers : We know that if we cube root both sides we could get 1 but we know that there are 3 roots. So we want the complex cube roots of 1. Using DeMoivre's Theorem with the power being a rational exponent (and therefore meaning a root), we can develop a method for finding complex roots. This leads to the following formula:

Let's try this on our problem. We want the cube roots of 1. We want cube root so our n = 3. Can you convert 1 to polar form? (hint: 1 = 1 + 0i) We want cube root so use 3 numbers here Once we build the formula, we use it first with k = 0 and get one root, then with k = 1 to get the second root and finally with k = 2 for last root.

Here's the root we already knew. If you cube any of these numbers you get 1. (Try it and see!)

We found the cube roots of 1 were: Let's plot these on the complex plane about 0.9 Notice each of the complex roots has the same magnitude (1). Also the three points are evenly spaced on a circle. This will always be true of complex roots. each line is 1/2 unit

Acknowledgement I wish to thank Shawna Haider from Salt Lake Community College, Utah USA for her hard work in creating this PowerPoint. Shawna has kindly given permission for this resource to be downloaded from and for it to be modified to suit the Western Australian Mathematics Curriculum. Stephen Corcoran Head of Mathematics St Stephen’s School – Carramar

Assignment P. 410 #1, 5, 7, 17