Do- Now Do- Now Warm UP Go over Test Review beginning slides from before break TLW find areas of regular polygons and circles. TEST FRIDAY!! No Homework
Find the area of each Figure Below:Find the area of each Figure Below: 6.79 cm yd 2 54 u 2
What is the definition of a regular polygon? A Regular Polygon is a convex polygon in which all angles are congruent and all the sides are congruent Context of the definition; What does convex refer to? Every internal angle is less than or equal to 180 o Every line segment between two vertices is in or on the polygon How could this information assist us in finding the area of a regular polygon?
Look at the Hexagon given below: Consider the following questions: What could we do to hexagon ABCDEF in order to find the height of h ? Inscribe the polygon in a circle How does this help us? We can now evaluate the area using Radius What would be our radii? GE & GF How does this help us? We can now use SOHCAHTOA to find lengths and angle measures h
Using the Hexagon given below: Looking at the image, line segment GH is drawn: from the center of the regular polygon perpendicular to a side of the polygon. This perpendicular segment, or height, is called the apothem. (Labeled by the “ h ”) How does labeling this segment help us find the area of the regular hexagon? What do we know about the central angles of a regular polygon? Does this help us? If so, how? h h
Using the Hexagon given below: By labeling and defining h as our perpendicular bisector, we know that Δ EGF is an Isosceles Triangle. We know that both of the radii are congruent in our triangle, that h bisects angle EGF making those angles congruent, and they share congruent right angles. h What would happen if we drew line segments from the center t each vertex on the hexagon? we end up with 6 congruent Δ ’s
How can we use this information to determine the area of our hexagon in square units? If we have 6 repeating triangles, how can we used this information to find the area of a hexagon ? Remember the area of a rhombus h Rhombus: (1/2) b h = [(1/2)((1/2) d 1 )((1/2) d 2 )] 4 = (1/2) d 1 d 2 Hexagon: (let a = h ) = [(1/2) a b ] # of sides = [(1/2) a b ] 6 = (1/2) 6 b awhat is 6b?
Area of a Regular Polygon:Area of a Regular Polygon: If a regular polygon has an area of A square units, a perimeter of P units, and an apothem of a units, then: Let’s begin with an example using a regular pentagon: What is the Perimeter of MNOPQ when QP = 12 inches? P = # of sides side length = 5 (12 in.) = 60 inches What is the Area? = in 2 SOHCAHTOA How do we find the apothem(a)? 360/ 5 = 72 o 72/ 2 = 36 o Tan (36 o ) = (6/a) a = (6/(tan(36 o ))) = 8.26 cm A = (1/2)P a
How can we use all of this information to find the area of a circle? Can we get to the area of a circle from the equation for Perimeter?
Can we use the area of a regular polygon? Yes! A = (1/2) Pa P C = 2πr Plug in! A = (1/2)(2πr)a What’s our “a”? It’s our radius !! A = (1/2)(2πr)(r) = πr 2 If a circle has an area of A square units and a radius of r units, then: A = πr 2
Let’s Try One!Let’s Try One! Let the circle shown below have a radius of 9 centimeters, what is the perimeter and the area of the circle? P = 2π r = 2π(9) = 18π cm ≈ cm A = π r 2 = π(9) 2 = (9 9)π cm 2 = 81π cm 2 ≈ cm 2 Your Turn!!
What if we want to know the area of the shaded region around an inscribed polygon? Let r = 12.5 inches What do we need to calculate?? Area of a Circle: = π r 2 = π (12.5) 2 = π in 2 ≈ in 2 Area of the Square: = s 2 s 2 + s 2 = (2r) 2, where r = s 2 = (25) 2 = 625 s 2 = in 2 Square root both sides! s = inches Area of a Circle – Area of a Square: ( in 2 ) – (312.5 in 2 ) in 2