Quadratic Functions in Standard Form Finding Minimum or Maximum Values.

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Quadratic Functions in Standard Form Finding Minimum or Maximum Values

Find the minimum or maximum value of f(x) = –3x 2 + 2x – 4. Then state the domain and range of the function. Example 1 Step 1 Determine whether the function has minimum or maximum value. Step 2 Find the x-value of the vertex. Substitute 2 for b and –3 for a. Because a is negative, the graph opens downward and has a maximum value.

The maximum value is. The domain is all real numbers, R. The range is all real numbers less than or equal to Example 1 Continued Step 3 Then find the y-value of the vertex, Find the minimum or maximum value of f(x) = –3x 2 + 2x – 4. Then state the domain and range of the function.

Example 1 Continued CheckGraph f(x)=–3x 2 + 2x – 4 on a graphing calculator. The graph and table support the answer.

Find the minimum or maximum value of f(x) = x 2 – 6x + 3. Then state the domain and range of the function. Example 2 Step 1 Determine whether the function has minimum or maximum value. Step 2 Find the x-value of the vertex. Because a is positive, the graph opens upward and has a minimum value.

Step 3 Then find the y-value of the vertex, Find the minimum or maximum value of f(x) = x 2 – 6x + 3. Then state the domain and range of the function. f(3) = (3) 2 – 6(3) + 3 = –6 The minimum value is –6. The domain is all real numbers, R. The range is all real numbers greater than or equal to –6, or {y|y ≥ –6}. Example 2 Continued

CheckGraph f(x)=x 2 – 6x + 3 on a graphing calculator. The graph and table support the answer. Example 2 Continued

Example 3 Step 1 Determine whether the function has minimum or maximum value. Step 2 Find the x-value of the vertex. Because a is negative, the graph opens downward and has a maximum value. Find the minimum or maximum value of g(x) = –2x 2 – 4. Then state the domain and range of the function.

Example 3 Continued Step 3 Then find the y-value of the vertex, Find the minimum or maximum value of g(x) = –2x 2 – 4. Then state the domain and range of the function. f(0) = –2(0) 2 – 4 = –4 The maximum value is –4. The domain is all real numbers, R. The range is all real numbers less than or equal to –4, or {y|y ≤ –4}.

Example 3 Continued CheckGraph f(x)=–2x 2 – 4 on a graphing calculator. The graph and table support the answer.

The average height h in centimeters of a certain type of grain can be modeled by the function h(r) = 0.024r 2 – 1.28r , where r is the distance in centimeters between the rows in which the grain is planted. Based on this model, what is the minimum average height of the grain, and what is the row spacing that results in this height? Example 4: Agricultural Application

The minimum value will be at the vertex (r, h(r)). Step 1 Find the r-value of the vertex using a = and b = –1.28. Example 4 Continued

Step 2 Substitute this r-value into h to find the corresponding minimum, h(r). The minimum height of the grain is about 16.5 cm planted at 26.7 cm apart. h(r) = 0.024r 2 – 1.28r h(26.67) = 0.024(26.67) 2 – 1.28(26.67) h(26.67) ≈ 16.5 Example 4 Continued Substitute for r. Use a calculator.

Check Graph the function on a graphing calculator. Use the MINIMUM feature under the CALCULATE menu to approximate the minimum. The graph supports the answer.

The highway mileage m in miles per gallon for a compact car is approximately by m(s) = –0.025s s – 30, where s is the speed in miles per hour. What is the maximum mileage for this compact car to the nearest tenth of a mile per gallon? What speed results in this mileage? Example 5

The maximum value will be at the vertex (s, m(s)). Step 1 Find the s-value of the vertex using a = –0.025 and b = Example 5 Continued   b s a   

Step 2 Substitute this s-value into m to find the corresponding maximum, m(s). The maximum mileage is 30 mi/gal at 49 mi/h. m(s) = –0.025s s – 30 m(49) = –0.025(49) (49) – 30 m(49) ≈ 30 Substitute 49 for r. Use a calculator. Example 5 Continued

Check Graph the function on a graphing calculator. Use the MAXIMUM feature under the CALCULATE menu to approximate the MAXIMUM. The graph supports the answer. Example 5 Continued