Quadratic Relations and Functions Chapter 13 Quadratic Relations and Functions Corresponding Notes Date Assigned Assignment # Day 1 & 2 Solving Quadratic Equations Friday 3/9 Page 507: 3 – 12 (all) 15 – 42 every 3rd ( 1st column) 1 Day 3 Notes Word Problems Consecutive ntegers Monday 3/12 Worksheet: HW Day 3 Consecutive Integer 2 Day 4 Notes Geometric Word Problems Tuesday 3/13 Worksheet: HW Day 4 Geometric word problems 3 Day 5 Notes More Word Problems Wednesday 3/14 Worksheet: HW Day 5 More Geometric word problem 4 Day 6 Notes Graphing Quadratics Thursday 3/15 Worksheet: Parabolas 5

Warm-up: Simplify:

highest exponent term to lowest an equation with a degree of 2, it has 2 answers, called roots. highest exponent term to lowest

Step 3: After the problem has been factored we will complete a step Step 3: After the problem has been factored we will complete a step called the “t” chart. Create a T separating the two ( ). Step 4: Once ( ) are separated set each ( ) = to 0 and solve for the variable. Step 5: Check each of the roots in the ORIGINAL quadratic equation

(r – 7 )(r – 5 ) = 0 (y + 8 )(y + 3 ) = 0 (r – 7 ) = 0 (r – 5 ) = 0 (y + 8 ) = 0 (y + 3 ) = 0 +7 +7 +5 +5 -8 -8 -3 -3 y = -8 y = -3 r = 7 r = 5 Check: #1 (-8)2 + 11(-8) + 24 =0 64 – 88 + 24 = 0 -24 + 24 = 0 Check: #1 72 – 12(7) + 35 =0 49 – 84 + 35 = 0 -35 + 35 = 0 Check: #2 52 – 12(5) + 35 =0 25 – 60 + 35 = 0 -35 + 35 = 0 Check: #2 (-3)2 + 11(-3) + 24 =0 9 – 33 + 24 = 0 -24 + 24 = 0

y2 – 3y – 28 = 0 3. Find the roots: 4. Solve for y: (x – 6 )(x + 1) = 0 (y – 7 )(y + 4) = 0 (x – 6 ) = 0 (x + 1 ) = 0 x = 6 x = -1 (y – 7 ) = 0 (y + 4 ) = 0 y = 7 y = -4

x2 – x – 30 = 0 3x2 – 10x + 3 = 0 5. Find the roots:

ex. SOLVING QUADRATIC EQUATIONS (DAY 2) Put in Standard Form Factor RECALL SOLVING STEPS: Step 1: Step 2: Step 3: Step 4: Put in Standard Form Factor Set equal to 0 and solve Check INCOMPLETE (SPECIAL) QUADRATICS: ex. Missing one of the three Standard Form terms and ex.

Solve the following equations. Check all the roots: 1. 2. 3. 5X2 - 45 = 0 X2 + 4x = 0 D2PS GCF (z – 2 )(z + 2) = 0 GCF 5(x2 – 9 ) = 0 x(x + 4) = 0 (x – 2) = 0 (x + 2 ) = 0 x = 0 (x + 4 ) = 0 D2PS x = 2 x = -2 x = 0 x = -4 5(x - 3)( x + 3) = 0 (x – 3) = 0 (x + 3 ) = 0 x = 3 x = -3

4. Solve for x: 5. Solve for x: CHALLENGE PROBLEMS: Solve and Check the roots 4. Solve for x: 5. Solve for x:

6. Solve for x: