Unit 3 Haley Parnham Mat Farley Jenna Hoffmire. Objective 1: To perform operations and simplify expressions involving powers of 10 Sample : Practice :

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Presentation transcript:

Unit 3 Haley Parnham Mat Farley Jenna Hoffmire

Objective 1: To perform operations and simplify expressions involving powers of 10 Sample : Practice :

Objective 2: Write numbers in decimal notation in Scientific Notation Sample Problem: Example Problem 1: Example Problem 2: Example Problem 3:

Objective 3 -Write numbers in Scientific Notation in decimal notation Since the exponent is a negative number I went 3 places to the left from the decimal. Since the exponent is a positive you move 2 places to the right.

Objective 4: Convert within units in the Customary System of Measurement Sample: miles= ___feet miles= ft. Practice: 43 fluid ounces= ___ pints 43 fl oz= 2.69 pt 106 ft= ___yd 106 ft= 35.3 yd 8500 lb= ___tons 8500 lb= 4.25 tons

Objective 5: Convert within units in the Metric System of Measurement. Sample Problem: Example Problem 1: Example Problem 2: Example Problem 3:

Objective 6 -Determine the appropriate unit of measure for a specific object Sample Problem: Best metric for measuring the height of the door - Meters Morton to Bahamas - Km Length of football field – M Thickness of a cheerio - mm

Objective 7: Convert area and volume within the Metric System of Measurement Sample: 325,000 cm = 0.325m Practice: change 2.5 L to mL= 2500mL change 5.2 cm to mm = 5200mm change 12.3 mm to cm = cm

Objective 8: Convert time. Sample Problem: How many seconds are in 3 days, 8 hours, 21 minutes, and 42 seconds. 60 seconds in one minute seconds in one hour seconds in one day.

Objective 8 continued. Example Problem 1: How many seconds are in 4 days, 3 hours, 13 minutes, and 53 seconds? Answer: seconds. Example Problem 2: How many seconds are in 1 day, 1 hour, 1 minute, and 1 second? Answer: seconds. Example Problem 3: How many seconds are in 4 days, 3 hours, 2 minutes, and 1 second? Answer: seconds.

Objective 9 -Convert Temperatures Sample Problem: 10°C = 50°F C= (F – 32°) F = C + 32° F = + 32 F = F = F = = 18° + 32 = = 50 ° = 89.6 ° F