ACTIVITY 34 Review (Sections )
Problems 3 and 5: Sketch the graph of the function by transforming an appropriate function of the form y = x n. Indicate all x- and y-intercepts on each graph.
y = 2x 4 y = x 4 y = 2x No x – intercepts y – intercepts is (0,8)
Problems 11, 13, and 15: Match the polynomial function with the below graphs
Problems 21: Sketch the graph of the polynomial function. Make sure your graph shows all intercepts and exhibits the proper end behavior. The leading term is 3x 3
Problem 31: Factor the polynomial P(x) = −x 3 + x x and use the factored form to find the zeros. Then sketch the graph. Zeros
Problem 3: Let P(x) = x 4 − x 3 + 4x + 2 and Q(x) = x (a)Divide P(x) by Q(x). (b)Express P(x) in the form P(x) = D(x) · Q(x) + R(x). x 4 − x 3 + 4x + 2 x x2x2 x 4 + 3x 2 –x 4 – 3x 2 − x 3 – 3x 2 + 4x + 2 – x – x 3 – 3x+ x 3 + 3x – 3x 2 + 7x + 2 – 3 – 3x 2 – 9+3x x + 11
Problem 9: Find the quotient and remainder using long division for the expression x 3 + 6x + 3x 2 – 2x+2 x x 3 – 2x 2 + 2x –x 3 + 2x 2 – 2x 2x 2 + 4x x 2 – 4x + 4 – 2x 2 + 4x – 4 8x – 1
Problem 21: Find the quotient and remainder using synthetic division for the expression
Problem 35: Use synthetic division and the Remainder Theorem to evaluate P(c) if P(x) = 5x x 3 − 40x x + 14 and c = −7.
Problem 43: Use the Factor Theorem to show that x − 1 is a factor of P(x) = x 3 − 3x 2 + 3x − 1. Showing that x = 1 is a zero. Therefore, (x – 1) is a factor
Problem 53: Find a polynomial of degree 3 that has zeros 1, −2, and 3, and in which the coefficient of x 2 is 3.
Problem 3: List all possible rational zeros given by the Rational Zeros Theorem (but don’t check to see which actually are zeros). possible rational zeros:
Problems 13 and 23: Find all rational zeros of the polynomial. possible rational zeros:
Consequently, the zero’s are x = 2 and x = – 1
possible rational zeros:
So we need only factor possible rational zeros:
So we need only factor possible rational zeros: Consequently, the roots are x = -4, x = -2, x = -1, and x = 1