AP Physics

 Think of a curve being traced out over time, sometimes doubling back on itself or crossing itself. Such a curve cannot be described by a function y=f(x). Instead, we will describe our position along the curve at time t by  x = x(t)  y = y(t)  Then x and y are related to each other through their dependence on the parameter t.

 Suppose we trace out a curve according to  x = t 2 −4t  y = 3t where t > 0.

 Sketch the parametric curve for the following set of parametric equations from t = 0 to t = 5 s.

 Given the following parametric equations, graph the trajectory an object from t = 0 s to t = 3s:

 Suppose a projectile is launched at an initial speed v 0, from a height h 0, at an angle  with the horizontal. It’s natural to consider the horizontal distance and the height of the projectile separately. Let t represent time, x represent the horizontal distance from the launching spot, y represent the height, and g the acceleration due to gravity, in the appropriate units.

 If one was looking at the projectile from above and had no depth perception, it would look as if the projectile was travelling in a straight line at a constant speed equal to v 0x = v 0 cos.  Since the speed is constant, it should be clear that x = (v 0 cos  )t.

 If one looked at the projectile from behind, in the plane of its motion, and had no depth perception, it would look as if the projectile was first going straight up and then falling, with an initial upward speed of v 0y = v 0 sin  but subject to gravity causing an acceleration g.  y =1/2gt 2 + (v 0 sin  ) t + y 0

 x = (v 0 cos  )t  y =1/2gt 2 + (v 0 sin  ) t + y 0

 Day 3: Application of Parametric Equations  AP Physics Practice Problem #1 Due (aka blue notebook)  Day 4: More on Position, Displacement, Velocity, & Acceleration Vectors  Day 5: Lab Report #1 Due; Lab #2; Projectile Motion  Day 6: Uniform Circular Motion & Relative Motion  Day 1: Practice Problem Solving  Unit 1 Test: Thursday, Sept. 24 th

 Day 3: Application of Parametric Equations  AP Physics Practice Problem #1 Due (aka blue notebook)  Day 4: More on Position, Displacement, Velocity, & Acceleration Vectors; Lab Report #1 Due; Lab #2  Day 5: Projectile Motion  Day 6: Uniform Circular Motion & Relative Motion  Day 1: Practice Problem Solving; Forces Baseline Inventory  Unit 1 Test: Wednesday, Sept. 23 rd

 Your task: To determine the magnitude and direction of the initial velocity of a soccer ball as it leaves your foot.

 Unit vectors are defined for convenience to be a vector of magnitude 1 in a particular direction. Traditionally the unit vectors for the x, y, and z axes are called i, j and k and are just unit vectors that point in the positive direction of the x, y, and z axes. The unit vectors are often written with small hats ^.

 The position of an object is described by telling three things about it: 1) The location of a reference point, called the origin. This is usually defined in a drawing of the experimental situation which shows the location of the origin. 2) The distance of the object from the origin. 3) The direction in which you must move from the origin in order to go to the object.

 The distance and direction information is combined into the position vector, drawn here with an arrow above a letter. (The arrow reminds us that there is a direction associated with this algebraic variable.) Vectors are represented pictorially as arrows. The direction of the arrow represent s the direction of the vector. For position, the length of the arrow represents the distance from the origin.

 When an object moves from one place to another, it is said to be "displaced." When it moves, the position of the object changes. The displacement vector is defined to be the vector which connects the old position to the new position, as sketched in the figure. Displacement differs from position in that no origin is needed to specify a displacement. In the figure, the subscript "f" represents the final position, and the subscript "i" represents the initial position. The drawing represents the displacement "Delta R" associated with changing from R(initial) to R(final). Since the displacement represents the difference between two positions, it is written algebraically as a subtraction.

 Using the parametric equations, calculate: (express each answer in unit vector notation)  The displacement vector from t = 1 s to t = 3s,  Average velocity from t = 1 s to t = 3 s,  Instantaneous velocity at t = 1 s and t = 3 s,  Average acceleration from t = 1 s to t = 3 s, and  Instantaneous acceleration at t = 1s and t = 3 s.

 The tangential component of acceleration or the component parallel to the velocity vector changes the magnitude of the velocity, but not its direction.  The perpendicular component of the acceleration or the radial component changes the direction of the velocity vector.

 /mmedia/vectors/mzi.html /mmedia/vectors/mzi.html

 A projectile launched horizontally with a dropped object and an object moving with a constant speed.

 Horizontal Motion  Constant motion  v o = v ox  a x = 0  Vertical Motion  Uniform accelerated motion  a y = - g = m/s 2

 If the horizontal speed is 12 m/s and the height of the table is 0.95 m,  How long does it take to hit the floor?  How far from the edge of the table does it land on the floor?

 A projectile is launched a with speed of 25 m/s at a 70 o angle above the horizontal from the top of a building that 50 m tall. How long does it take to land on the ground?

 The soccer player kicks the ball at 30 m/s at an angle of 40 o angle below the horizontal. If the ball lands 55 m from the top of the hill, how high is the hill?

 The quarterback releases the football with a speed of 15 m/s at an angle of 35 o above the horizontal when the receiver is 10 m away from him. If the receiver catches the ball at the same height as it was released, how much further did he need to run?

 The two triangles are similar; therefore,  For one complete revolution,

 When the motion is non-uniform circular motion, the speed and the direction change.

 If girl on the swing makes one complete revolution in 10.0 seconds,  What is her constant speed?  What is the centripetal acceleration?

 Velocity seen by a particular observer is said to be relative to that observer.

 Predict the path that the boat will travel.  s.mun.ca/~jjerrett /relative/relative. html s.mun.ca/~jjerrett /relative/relative. html

 Predict its motion.  s.mun.ca/~jjerrett /relative/relative. html s.mun.ca/~jjerrett /relative/relative. html

 The truck still moves at 40 km/hr west, but the car turns on to a road going 40 degrees south of east, and travels at 30 km/hr. What is the velocity of the car relative to the truck now?  The relative velocity equation for this situation looks like this:  v CT = v CG + v GT

1-D Uni.Accn. Non-Uni Accn. Vectors Applications 2-or 3-D