Similar Experiences Similar Game Plans Similar Characters.

Slides:



Advertisements
Similar presentations
56.) Congruent Figures—figures that have the same size and shape 57.) Similar Figures—figures that have the same exact shape but different size (angles.
Advertisements

CONGRUENT AND SIMILAR FIGURES
4.1 Quadrilaterals Quadrilateral Parallelogram Trapezoid
8.6 Proportions & Similar Triangles
Proportions & Similar Triangles. Objectives/Assignments Use proportionality theorems to calculate segment lengths. To solve real-life problems, such as.
8.1, 2, 7: Ratios, Proportions and Dilations
Unit 8 Similarity Ratios, Proportions, Similar Polygons
By: Madi and Hrishika. Interior Angles: angles inside a polygon Exterior Angles: angles outside of a polygon that are formed by extending the sides Regular.
11.5 Similar Triangles Identifying Corresponding Sides of Similar Triangles By: Shaunta Gibson.
Ratio and Proportion.
Objective: Find and simplify the ratio of two numbers.
7-1 Ratio and Proportion Warm Up Lesson Presentation Lesson Quiz
Tuesday, January 15, §7.4 Parallel Lines & Proportional Parts CA B D E Theorem: Triangle Proportionality Theorem ◦ If a line parallel to one side.
Chapter 7: Proportions and Similarity
Problem Solving in Geometry with Proportions
Geometry 6-1 Big Idea: Use Ratios & Proportions. A comparison of two numbers Ratio A comparison of two numbers Ex.1) ½, 1:2 Ex.2) 3, 3:4 4.
8.1 – Ratio and Proportion Solve Proportions Reduce Ratios Find unknown lengths given ratios.
Lesson 8.1 & 8.2 Solving Problems with Ratio and Proportion Today, we will learn to… …find and simplify ratios...use proportions to solve problems.
7.5 Proportions & Similar Triangles
7-4 Parallel Lines and Proportional Parts
Objective: Students will use proportional parts of triangles and divide a segment into parts. S. Calahan 2008.
Proportions and Similar Triangles
8.6 Proportions and Similar Triangles Triangle Proportionality Theorem If a line parallel to one side of a triangle intersects the other two sides, then.
7.5 Proportions In Triangles
Section 7-4 Similar Triangles.
Proportional Lengths of a Triangle
RIGHT TRIANGLE CONGRUENCE WORKSHEET. RATIOS AND PROPORTIONS.
 Objectives:  Students will apply proportions with a triangle or parallel lines.  Why?, So you can use perspective drawings, as seen in EX 28  Mastery.
The product of the means equals the product of the extremes.
8.1 Ratio and Proportion Geometry Ms. Reser.
8.1 Ratio and Proportion Geometry--Honors Mrs. Blanco.
6.6 Proportionality Theorems Triangle Proportionality Theorem: A line // to one side of a triangle divides the other sides proportionally. Warning: This.
Ratio and Proportion Students will be able to write and simplify ratios and to use proportions to solve problems.
6.6 – Use Proportionality Theorems. Triangle Proportionality Theorem If a line parallel to one side of a triangle intersects the other two sides, then.
Chapter 6: Similarity By Elana, Kate, and Rachel.
Similarity Chapter Ratio and Proportion  A Ratio is a comparison of two numbers. o Written in 3 ways oA to B oA / B oA : B  A Proportion is an.
Holt Geometry 7-1 Ratio and Proportion Warm Up Find the slope of the line through each pair of points. 1. (1, 5) and (3, 9) 2. (–6, 4) and (6, –2) Solve.
12.5 Proportions & Similar Triangles. Triangle Proportionality Theorem If a line parallel to one side of a triangle intersects the other two sides, then.
8.1 Ratio and Proportion Slide #1.
8.6 Proportions & Similar Triangles
Triangle Proportionality
4.3 Warm Up Are the triangles similar? If so, which theorem justifies your answer.
Applying Properties of Similar Triangles
1. Give the postulate or theorem that justifies why the triangles are similar. ANSWER AA Similarity Postulate 2. Solve = .
8.2 Problem Solving in Geometry with Proportions
8.2 Problem Solving in Geometry with Proportions
DRILL Are these two triangles similar? (Explain).
Chapter 7 Proportions & Similarity
PROPORTIONAL SEGMENTS & BASIC SIMILARITY THEOREM
Similar figures are figures that have the same shape but not necessarily the same size. The symbol ~ means “is similar to.” 1.
8.1 Ratio and Proportion.
8.6 Proportions & Similar Triangles
Ratio and Proportion Unit IIA Day and 8.2.
8.2 Problem Solving in Geometry with Proportions
8.1 Ratio and Proportion.
8.1 Exploring Ratio and Proportion
8.6 Proportions & Similar Triangles
7.1 Ratio and Proportions.
CHAPTER 7 SIMILAR POLYGONS.
Proportions and Similar Triangles
8.6 Proportions & Similar Triangles
Problem Solving in Geometry with Proportions
Warm Up 1. If ∆QRS  ∆ZYX, identify the pairs of congruent angles and the pairs of congruent sides. Solve each proportion Q  Z; R 
8.6 Proportions & Similar Triangles
Parallel Lines and Proportional Parts
Chapter 8 Similarity.
8.6 Proportions & Similar Triangles
Chapter 8 Similarity.
Lesson 5-4: Proportional Parts
Presentation transcript:

Similar Experiences Similar Game Plans Similar Characters

Similarity in Geometric Figures Similarity in Geometry: - The concept that shapes or other relations exist in specific ratios or proportions to one another. Ratios: When two quantities are measured in the same units, (or can be converted to the same unit of measure), they can be expressed in a constant relation to one another, referred to as a ratio. Ratios are written: a / b or a:b Simplifying Ratios: Many times, the unit of measure provided will not always be the same. In those cases they need to be converted in order to specify a meaningful ratio. 12 cm 6ft 4m 18 in. How might we convert these to simplified / meaningful ratios? 12cm 12 3 = 4* 100cm * 12 in = 18 in. 18 1

Using Ratios To Solve Problems The perimeter of a rectangle ABCD is 60 centimeters. The ratio of AB:BC is 3:2. Find the length and width of the rectangle. Hint: Because the ratio o AB:BC is 3:2, we can represent the length of AB as 3x and BC as 2x D C w A B l 2 l + 2w = P 2(3x) + 2(2x) = 60 6x + 4x = 60 10x = 60 X = 6 Therefore, ABCD has a length of 18 cm and a width of 12 cm

Using Ratios To Solve Problems Extended Ratios: Ratios can extend beyond a simple relationship of two measures to incorporate a third, or more, provided they are all in a constant relation to one another. In the triangle ABC, the angles exist in the following extended ratio, 1:2:3. How can we use the extended ratio to determine the measure of the angles? 2x 3x x x + 2x + 3x = 180 o Triangle Sum Theorem 6x = 180 X = 30 Therefore the angle measures are 30 o, 60 o, and 90 o

Using Ratios To Solve Problems The ratios of the side lengths of triangle DEF to the corresponding side lengths of triangle ABC are 2:1. How can we use this information to find the unknown lengths? C 3 A B F D 8 E DE is twice AB. DE = 8, so AB = ½ (8) = 4 Using the Pythagorean Theorem, we can determine BC = 5 DF is twice AC. AC = 3, so DF = 6 EF is twice BC. BC = 5, so EF = 10.

Using Proportions An equation that equates two ratios is a proportion. For example, if the ratio a/b is equal to c/d, then the following proportion can be written: a/b = c/d The numbers “a” and “d” are referred to as the extremes. The numbers “b” and “c” are referred to as the means. MeansExtremes a c b = d Properties of Proportions: 1. Cross Product Property – The product of the extremes equals the product of the means. If a/b = c/d, then ad = bc 2. Reciprocal Property – If two ratios are equal, then their reciprocals are also equal. If a/b = c/d, then b/a = d/c

Solving Proportions Using the Properties of Proportions, solve the following: 4 / x = 5 / 7 3 = 2 y + 2 y 1.Using Cross Products: 5x = 28 X = 28/5 2. Using Reciprocal Property 4/x = 5/7 x/4 = 7/5 x = 4(7/5) x = 28/5 1.Using Cross Products 3y = 2(y + 2) 3y = 2y + 4 y = 4

What do these all have in common?

Additional Properties of Geometry in Proportions Properties of Proportions: 1. Cross Product Property – The product of the extremes equals the product of the means. If a/b = c/d, then ad = bc 2. Reciprocal Property – If two ratios are equal, then their reciprocals are also equal. If a/b = c/d, then b/a = d/c 3.If a/b = c/d, then a/c = b/d 4.If a/b = c/d, then a+b/b = c+d/d

Problem Solving in Geometry with Proportions In the diagram AB / BD = AC / CE. Find the length of BD. A B C x 10 D E Given: AB _ AC BD -- CE AB _ AC BD -- CE 16/x = (30-10)/10 16/x = 20/10 20x = 160 X = 8 16/30-10 = x/10 20x = 160 X = 8 16+x/x = 30/10 30x = 10(16+x) 30x = x 20x = 160 X = 8

Geometric Mean Geometric Mean: The geometric mean of two numbers “a” and “b” is the positive number x such that: a/x = x/b. If you solve this proportion for x, through cross multiplication we find that: x 2 = a*b, therefore x = \/ a* b Example: What is the Geometric Mean of 8 and 18? 8/x = x/18  x 2 = 144  x = 12 Also, 8/12 = 12/18 because \/ 8 * 18 = \/ 144 = 12

Using Geometric Mean A4 x A3 420mm 210 mm x International Paper Standards set a standard ratio for length and width for all writing paper which is generally recognized around the world. Two paper types A3 and A4 are shown to the right. The length represented by “x” is the geometric mean of 210mm and 420mm. Find the value of x. 210 / x = x / 420 X 2 = 210 * 420 X = \/ 210 * 420 X = \/ 210 * 210 * 2 X = 210 \/ 2

Using Proportions in Real Life A Scale model of the Titanic is inches long and inches wide. The Titanic itself was feet long. How wide was it? Width of ship = x X ft / in = ft / in X = (11.25 * ) / X = 92.4 Feet

Proportions and Similar Triangles Triangle Proportionality Theorem: If a line parallel to one side of a triangle intersects the other two sides, then it divides the two sides proportionately If TU || QS, then RT/TQ = RU/US > > R T U Q S Theorem 8.6 If thee parallel lines intersect two transversals, then they divide the transversals proportionately. If r|| s and s|| t, then l and m intersect r, s, t and t, then UW/WY = VX = XZ l U W Y m X Z V t r s Theorem 8.7 If a ray bisects an angle of a triangle, then it divides the opposite side into segments whose lengths are proportional to the lengths of the other two sides. If CD bisects <ABC, then AD/DB = CA/CB A D C B

Using Proportions in Similar Triangles In the diagram, AB||ED, BD = 8, DC = 4, and AE = 12. What is the length of EC? C 4 E D 12 8 A B Given the diagram, determine if MN || GH. G 21 M 56 H 16 N 48 L In the diagram, <1 = <2, <2 = <3. What is the length of TU? ~ ~ P S 9 11 Q T 15 R U 1 2 3