Holt Algebra 1 2-3 Solving Two-Step and Multi-Step Equations 2-3 Solving Two-Step and Multi-Step Equations Holt Algebra 1 Warm Up Warm Up Lesson Quiz Lesson.

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Holt Algebra Solving Two-Step and Multi-Step Equations 2-3 Solving Two-Step and Multi-Step Equations Holt Algebra 1 Warm Up Warm Up Lesson Quiz Lesson Quiz Lesson Presentation Lesson Presentation

Holt Algebra Solving Two-Step and Multi-Step Equations Warm Up Evaluate each expression –3(–2) 2. 3(–5 + 7) – 4(7 – 5) Simplify each expression c + c b + 3.8b – 12b 7. 5m + 2(2m – 7) 8. 6x – (2x + 5) –4 11c 0 9m – 14 4x – 5

Holt Algebra Solving Two-Step and Multi-Step Equations Solve equations in one variable that contain more than one operation. Objective

Holt Algebra Solving Two-Step and Multi-Step Equations Alex belongs to a music club. In this club, students can buy a student discount card for $ This card allows them to buy CDs for $3.95 each. After one year, Alex has spent $ To find the number of CDs c that Alex bought, you can solve an equation. Cost per CDTotal cost Cost of discount card Notice that this equation contains multiplication and addition. Equations that contain more than one operation require more than one step to solve. Identify the operations in the equation and the order in which they are applied to the variable. Then use inverse operations and work backward to undo them one at a time.

Holt Algebra Solving Two-Step and Multi-Step Equations Operations in the Equation First c is multiplied by Then is added. To Solve Subtract from both sides of the equation Then divide both sides by 3.95.

Holt Algebra Solving Two-Step and Multi-Step Equations Solve 18 = 4a Example 1A: Solving Two-Step Equations First a is multiplied by 4. Then 10 is added. Work backward: Subtract 10 from both sides. 18 = 4a + 10 –10 – 10 8 = 4a Since a is multiplied by 4, divide both sides by 4 to undo the multiplication. 8 = 4a 44 2 = a

Holt Algebra Solving Two-Step and Multi-Step Equations Solve 5t – 2 = –32. Example 1B: Solving Two-Step Equations First t is multiplied by 5. Then 2 is subtracted. Work backward: Add 2 to both sides. 5t – 2 = – t = –30 Since t is multiplied by 5, divide both sides by 5 to undo the multiplication. 5t = –30 55 t = –6

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Check it Out! Example 1c First n is divided by 7. Then 2 is added. Work backward: Subtract 2 from both sides. –2 Since n is divided by 7, multiply both sides by 7 to undo the division. n = 0

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Example 2A: Solving Two-Step Equations That Contain Fractions Since y is divided by 8, multiply both sides by 8 to undo the division. Method 1 Use fraction operations. Since is subtracted from, add to both sides to undo the subtraction. 3 4 y 8 3 4

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Example 2A Continued Method 1 Use fraction operations. Simplify.

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Example 2A Continued Multiply both sides by 24, the LCD of the fractions. Distribute 24 on the left side. Method 2 Multiply by the LCD to clear the fractions. 3y – 18 = Simplify. Since 18 is subtracted from 3y, add 18 to both sides to undo the subtraction. 3y = 32

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Example 2A Continued Method 2 Multiply by the LCD to clear the fractions. 3 Since y is multiplied by 3, divide both sides by 3 to undo the multiplication. 3y = 32

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Example 2B: Solving Two-Step Equations That Contain Fractions Method 1 Use fraction operations. Since is added to r, subtract from both sides to undo the addition The reciprocal of is. Since r is multiplied by, multiply both sides by

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Example 2B Continued Method 1 Use fraction operations.

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Example 2B Continued Method 2 Multiply by the LCD to clear the fractions. Multiply both sides by 12, the LCD of the fractions. 8r + 9 = 7 –9 8r = –2 Distribute 12 on the left side. Simplify. Since 9 is added to 8r, subtract 9 from both sides to undo the addition.

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Example 2B Continued Method 2 Multiply by the LCD to clear the fractions. 8r = –2 8 Since r is multiplied by 8, divide both sides by 8 to undo the multiplication.

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Check It Out! Example 2c Method 1 Use fraction operations. Since is subtracted from, add to both sides to undo the subtraction. 1 3 n Simplify.

Holt Algebra Solving Two-Step and Multi-Step Equations Solve. Check It Out! Example 2c Continued Method 1 Use fraction operations. n = 15 Since n is divided by 5, multiply both sides by 5 to undo the division.

Holt Algebra Solving Two-Step and Multi-Step Equations Equations that are more complicated may have to be simplified before they can be solved. You may have to use the Distributive Property or combine like terms before you begin using inverse operations.

Holt Algebra Solving Two-Step and Multi-Step Equations Solve 8x – x = –15. Example 3A: Simplifying Before Solving Equations Use the Commutative Property of Addition. 8x – 21 – 5x = –15 8x – 5x – 21 = –15 3x – 21 = –15 Combine like terms. Since 21 is subtracted from 3x, add 21 to both sides to undo the subtraction x = 6 x = 2 Since x is multiplied by 3, divide both sides by 3 to undo the multiplication.

Holt Algebra Solving Two-Step and Multi-Step Equations End, Part 1

Holt Algebra Solving Two-Step and Multi-Step Equations Solve 10y – (4y + 8) = –20 Example 3B: Simplifying Before Solving Equations Write subtraction as addition of the opposite. 10y + (–1)(4y + 8) = –20 10y + (–1)(4y) + (–1)( 8) = –20 Distribute –1 on the left side. Combine like terms. 10y – 4y – 8 = –20 6y – 8 = – y = –12 y = –2 Simplify. Since 8 is subtracted from 6y, add 8 to both sides to undo the subtraction. 6 6y = –12 Since y is multiplied by 6, divide both sides by 6 to undo the multiplication.

Holt Algebra Solving Two-Step and Multi-Step Equations If 4a = 5, find the value of a – 1. Example 5A: Solving Equations to Find an Indicated Value Since 0.2 is added to 4a, subtract 0.2 from both sides to undo the addition. Step 1 Find the value of a. 4a = 5 Since a is multiplied by 4, divide both sides by 4 to undo the multiplication. –0.2 –0.2 4a = 4.8 a = 1.2 Step 2 Find the value of a – – 1 To find the value of a – 1, substitute 1.2 for a. 0.2 Simplify.

Holt Algebra Solving Two-Step and Multi-Step Equations If 3d – (9 – 2d) = 51, find the value of 3d. Example 5B: Solving Equations to Find an Indicated Value Since 9 is subtracted from 5d, add 9 to both sides to undo the subtraction. Step 1 Find the value of d. 3d – (9 – 2d) = 51 Since d is multiplied by 5, divide both sides by 5 to undo the multiplication d = 60 d = 12 3d – 9 + 2d = 51 5d – 9 = 51

Holt Algebra Solving Two-Step and Multi-Step Equations If 3d – (9 – 2d) = 51, find the value of 3d. Example 5B Continued d = 12 Step 2 Find the value of 3d. 3(12) To find the value of 3d, substitute 12 for d. 36 Simplify.

Holt Algebra Solving Two-Step and Multi-Step Equations Lesson Quiz: Part 1 Solve each equation. 1. 4y + 8 = y + 29 – 8y = (x – 9) = x – (12 – x) = –

Holt Algebra Solving Two-Step and Multi-Step Equations Part 1 Assignment P. 96, #’s 24-35

Holt Algebra Solving Two-Step and Multi-Step Equations Lesson Quiz: Part 2 7. If 3b – (6 – b) = –22, find the value of 7b. 8. Josie bought 4 cases of sports drinks for an upcoming meet. After talking to her coach, she bought 3 more cases and spent an additional $6.95 on other items. Her receipts totaled $ Write and solve an equation to find how much each case of sports drinks cost. –28 4c + 3c = 74.15; $9.60

Holt Algebra Solving Two-Step and Multi-Step Equations Part 2 Assignment P , #’s 36-63